Why do you need an explicit `-lm` compiler option

问题:

This question already exists:

Closed 7 years ago.

Possible Duplicate:
gcc: why the -lm flag is needed to link the math library?

Generally speaking, in order to use any of the math functions apart from including the header file math.h you have to link with the linker option -lm. -l here would mean the linker option to search of the specific library libm.o.

My Question is

Why GCC does not include this library by default? Is it because the library heavily uses math-coprocessor and it requires to add the extra bit of code to initialize the floating point initialization (I may use the wrong terminology here)?

Note

I just reviewed all the answers mentioned in the link http://stackoverflow.com. This doesn't makes much sense to me. There are three basic reasons attributed

1. The standard libraries are guaranteed to be available. Linking other posix libraries like pthread explicitly makes sense, but why do we have to do an explicit link for a standard library. Even the historical reason is not very clear.
2. Why was libm separated from libc?
3. Why are we still inheriting these behaviors in the recent gcc compilers? What simplicity it achives? Here is what I tested, without libm and with libm. The One without libm, I have written my own version of Pow

Here is the example

abhibhat@abhibhat-VirtualBox:~/Projects/GIPL6_2$ ls -1 Test_*|xargs -I{} sh -c "echo {} && echo "-----------------" && cat {}"
Test_withlibm.c
-----------------
#include<stdio.h>
#include<math.h>
int main() {
    int i=20;
    double output1=pow(2.618033988749895,i);
    return 0;
    }
Test_withoutlibm.c
-----------------
#include<stdio.h>
#include<math.h>
double Pow(double _X, int _Y)  {
    double _Z = 1;
    for (; _Y; _X *= _X) {
    if (_Y & 1) _Z *= _X;
    _Y >>= 1;
    }
    return _Z; 
    }
int main() {
    int i=20;
    double output1=Pow(2.618033988749895,i);
    return 0;
    }
abhibhat@abhibhat-VirtualBox:~/Projects/GIPL6_2$ gcc Test_withlibm.c -lm -o Main_withlibm.o
abhibhat@abhibhat-VirtualBox:~/Projects/GIPL6_2$ gcc Test_withoutlibm.c -o Main_withoutlibm.o
abhibhat@abhibhat-VirtualBox:~/Projects/GIPL6_2$ objdump -d Main_withoutlibm.o|wc -l
261
abhibhat@abhibhat-VirtualBox:~/Projects/GIPL6_2$ objdump -d Main_withlibm.o|wc -l
241

回答1:

It is to accomodate systems (mainly embedded) where floating point math is not possible or necessary. It's kind of historical indeed but don't forget that gcc and most other C compilers were written in a time where a 386SX was considered a high performance processor.

To give an example, when I still worked in embedded computing, we used standard compilers (Microsoft and Borland) to generate code for our processors (Z80, 80186 and 68030). If the compilers had by default linked to the math library we would have been in trouble as none of our systems had floating point capabilities or even needed it.

It's true that 30 years afterwards it seems silly but the reason was sound at that time.

回答2:

There are many libraries you may want, and libm is just one of them.
For each of these, you may ask why it isn't included by default.

Perhaps libm is more useful than others, but still, C prefers to keep things simple - you want a library, use -l to use it.

回答3:

Historical reasons

The reasons libc and libm are separated and you have to specify -lm on the command line are historical reasons because the libm was also used by the Fortran compiler.