Pick contact directly from contact picker intent

问题:

Hello I want to pick a contact from our default contact book intent. I tried several ways to do it. Please find the code below. The problem with all those code is that they open one intermediate documents screen with few options there user has to select contact and than it opens contact book.

private void openContactIntent() {
     Intent intent = new Intent(Intent.ACTION_GET_CONTENT, ContactsContract.Contacts.CONTENT_URI);
     intent.setType(ContactsContract.CommonDataKinds.Phone.CONTENT_ITEM_TYPE);
     startActivityForResult(intent, REQ_CONTACT_DIRECTORY);
}

I also tried

Intent intent = new Intent(Intent.ACTION_PICK, ContactsContract.Contacts.CONTENT_URI);
startActivityForResult(intent, PICK_CONTACT);

and

Intent intent = new Intent(Intent.ACTION_PICK);
intent.setType(ContactsContract.Contacts.CONTENT_TYPE);
startActivityForResult(intent, PICK_CONTACT); 

What I see as an intermediate screen is

回答1:

I also had the same problem. Finally, I got rid of intermediate picker screen using below code,

Intent i=new Intent(Intent.ACTION_PICK);
i.setType(ContactsContract.CommonDataKinds.Phone.CONTENT_TYPE);
startActivityForResult(i, SELECT_PHONE_NUMBER);

In onActivityResult get phone number as below

if (requestCode == SELECT_PHONE_NUMBER && resultCode == RESULT_OK) {
  // Get the URI and query the content provider for the phone number
  Uri contactUri = data.getData();
  String[] projection = new String[]{ContactsContract.CommonDataKinds.Phone.NUMBER};
  Cursor cursor = getContext().getContentResolver().query(contactUri, projection,
      null, null, null);

  // If the cursor returned is valid, get the phone number
  if (cursor != null && cursor.moveToFirst()) {
    int numberIndex = cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER);
    String number = cursor.getString(numberIndex);
    // Do something with the phone number
    ... 
  } 

  cursor.close();
}

回答2:

Try the below code to pick contact:

Intent contactPickerIntent = new Intent(Intent.ACTION_PICK,
                    ContactsContract.CommonDataKinds.Phone.CONTENT_URI);
            startActivityForResult(contactPickerIntent, RESULT_PICK_CONTACT);

You can fetch the required information in onActivityResult as follows:

protected void onActivityResult(int requestCode, int resultCode, Intent data) {
    if (resultCode == RESULT_OK) {
        switch (requestCode) {
            case RESULT_PICK_CONTACT:
                  Cursor cursor = null;
    try {
        String phoneNo = null;
        String name = null;

        Uri uri = data.getData();
        cursor = getContentResolver().query(uri, null, null, null, null);
        cursor.moveToFirst();
        int  phoneIndex =cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER);
        int  nameIndex =cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME);
        phoneNo = cursor.getString(phoneIndex);
        name = cursor.getString(nameIndex);

       Log.e("Name and Contact number is",name+","+phoneNo);

    } catch (Exception e) {
        e.printStackTrace();
    }
                break;
        }
    } else {
        Log.e("Failed", "Not able to pick contact");
    }
}

回答3:

Here is a way to pick name, phone number from Contact in Kotlin

private fun pickEmergencyFromContacts() {
    val i = Intent(Intent.ACTION_PICK)
    i.type = ContactsContract.CommonDataKinds.Phone.CONTENT_TYPE
    startActivityForResult(i, SELECT_PHONE_NUMBER)
}

override fun onActivityResult(requestCode: Int, resultCode: Int, data: Intent?) {
    super.onActivityResult(requestCode, resultCode, data)
    if (requestCode == SELECT_PHONE_NUMBER && resultCode == Activity.RESULT_OK) {
        val contactUri = data?.data ?: return
        val projection = arrayOf(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME,
                ContactsContract.CommonDataKinds.Phone.NUMBER)
        val cursor = requireContext().contentResolver.query(contactUri, projection,
                null, null, null)

        if (cursor != null && cursor.moveToFirst()) {
            val nameIndex = cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME)
            val numberIndex = cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER)
            val name = cursor.getString(nameIndex)
            val number = cursor.getString(numberIndex)

            // do something with name and phone
        }
        cursor?.close()
    }
}

companion object {

    private const val SELECT_PHONE_NUMBER = 111    
    ...
}

Hope it help

回答4:

This works for me:

Intent it= new Intent(Intent.ACTION_PICK, 
     ContactsContract.Contacts.CONTENT_URI); 
startActivityForResult(it, requestCode);

回答5:

 private static final int RESULT_PICK_CONTACT1= 1;
 public void pickContact1 (View v)
      {
        Intent contactPickerIntent = new Intent(Intent.ACTION_PICK, ContactsContract.CommonDataKinds.Phone.CONTENT_URI);
        startActivityForResult(contactPickerIntent, RESULT_PICK_CONTACT1);
      }
 @Override
    protected void onActivityResult ( int requestCode, int resultCode, Intent data){
        if (resultCode == RESULT_OK) {
            switch (requestCode) {
                case RESULT_PICK_CONTACT1:
                    contactPicked1(data);
                    break;
            }
        } else {
            Log.e("SetupActivity", "Failed to pick contact");
        }
    }

 private void contactPicked1 (Intent data){
        Cursor cursor = null;
        try {
            String phoneNo = null;
            String name = null;
            Uri uri = data.getData();
            cursor = getContentResolver().query(uri, null, null, null, null);
            cursor.moveToFirst();
            int phoneIndex = cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER);
            int nameIndex = cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME);
            name = cursor.getString(nameIndex);
            phoneNo = cursor.getString(phoneIndex);
            ed11.setText(name);
            ed12.setText(phoneNo);
        } catch (Exception e) {
            e.printStackTrace();
        }
    }

This will surely work.