Using Notepad++ Find and Replace feature, I would like to insert a new line at every nth occurrence of a character or string (a comma in my case).
I have tried the regex below using "Regular expression" mode, but no luck.
Find what: ((,){1000})
Replace with: \1\n
If you mean to add a newline after nth occurrence of any string on a line, I'd use
(?:.*?,){2}
and replace with $&\n
(or $&\r\n
) where .*?
matches any 0+ chars other than line break characters, as few as possible, up to the first occurrence of ,
. The $&
is the backreference to the whole match value (2
is used for the demo to look cleaner, 1000
is a rather big value). See a demo showing that a newline is placed after each second ,
.
With a single char, you'd better use a negated character class (but add line break chars there to force the pattern to not overflow across lines):
(?:[^\n\r,]*,){2}