how to sort a string alphabetically java [closed]

问题:

Closed. This question is off-topic. It is not currently accepting answers.

---

Want to improve this question? Update the question so it's on-topic for Stack Overflow.

Closed 6 years ago.

I want to sort a string in JAVA alphabetically, as follows Capital letter and lowercase letter followed AaBbCcDdEeFfGg. for example if I put AbaC return me AabC thanks!!

回答1:

You can do this using Arrays.sort, if you put the characters into an array first. (It must be an array of Character objects rather than char primitives, in order to use a custom case-insensitive comparator.)

// put the characters into an array
Character[] chars = new Character[str.length()];
for (int i = 0; i < chars.length; i++)
    chars[i] = str.charAt(i);

// sort the array
Arrays.sort(chars, new Comparator<Character>() {
    public int compare(Character c1, Character c2) {
        int cmp = Character.compare(
            Character.toLowerCase(c1.charValue()),
            Character.toLowerCase(c2.charValue())
        );
        if (cmp != 0) return cmp;
        return Character.compare(c1.charValue(), c2.charValue());
    }
});

// rebuild the string
StringBuilder sb = new StringBuilder(chars.length);
for (char c : chars) sb.append(c);
str = sb.toString();

回答2:

You may try to look for Collections.sort and then try like this:-

Collections.sort(caps, String.CASE_INSENSITIVE_ORDER);

Something like this:-

private static Comparator<String> ALPHA_ORDER = new Comparator<String>() {
    public int compare(String str1, String str2) {
        int x = String.CASE_INSENSITIVE_ORDER.compare(str1, str2);
        if (x== 0) {
            x= str1.compareTo(str2);
        }
        return x;
    }
};

Collections.sort(list, ALPHA_ORDER);

EDIT:-

For sorting alphabetically in a string try like this:-

Collator col = Collator.getInstance(new Locale("en", "EN"));
String s = "AbaC";
String[] s1= s.split("");
Arrays.sort(s1, col);
String sorted = "";
for (int i = 0; i < s1.length; i++)
{
  sorted += s1[i];
}
System.out.println(sorted);

回答3:

Turn the String into a character array, then compare the int values of each character in your sort.

Methods needed: String.toCharArray();