Equivalent of Underscore _.pluck in pure JavaScrip

2020-02-09 06:12发布

问题:

I'm trying to recreate the Underscore pluck function using pure JS. However, I keep getting an array of undefineds being returned, instead of the actual values from the properties of the objects in an array.

Checking another thread here I found that you could reproduce it in jQuery with the following code...

$.pluck = function(arr, key) { 
    return $.map(arr, function(e) { return e[key]; }) 
}

...however I am having difficulty just reproducing this in pure JS. I tried the following, however this is just returning an array of undefineds for me.

var pluck = function(arr,key){
  var newArr = [];
  for (var i = 0, x = arr.length; i < x; i++){
    if (arr[i].hasOwnProperty(key)){
      newArr.push(arr[i].key)
    }
  }
  return newArr;
}

So, the goal would be the following, except instead of using the underscore _.pluck, just use a JS function name, eg. var pluck = function(arr,key){...}

var Tuts = [{name : 'NetTuts', niche : 'Web Development'}, {name : 'WPTuts', niche : 'WordPress'}, {name : 'PSDTuts', niche : 'PhotoShop'}, {name : 'AeTuts', niche : 'After Effects'}];
var niches = _.pluck(Tuts, 'niche');

console.log(niches);

// ["Web Development", "WordPress", "PhotoShop", "After Effects"]

Could someone steer me in the right direction?

回答1:

In ES5:

function pluck(array, key) {
  return array.map(function(obj) {
    return obj[key];
  });
}

In ES6:

function pluck(array, key) {
  return array.map(o => o[key]);
}


回答2:

You can do it with the native JavaScript .map():

Array.prototype.pluck = function(key) {
  return this.map(function(object) { return object[key]; });
};

edit — modifying built-in prototype objects should be done with care; a better way to add the function (should you be OK with the idea of doing so in general) would be with Object.defineProperty so that it can be made non-enumerable:

Object.defineProperty(Array.prototype, "pluck", {
    value: function(key) {
        return this.map(function(object) { return object[key]; });
    }
});


回答3:

You are so close. You need to change:

newArr.push(arr[i].key);

to:

newArr.push(arr[i][key]);

Consider this:

var obj = { myKey: 'my Value', theKey: 'another value' };
var theKey = 'myKey';

alert(obj.theKey); // another value
alert(obj[theKey]); // my Value
// You can also send in strings here:
alert(obj['theKey']); // another value

Hope you get my point.



回答4:

Here's a working solution

function pluck(array,key){
  var a = [],
     i1 = -1, i2 = array.length,
      o ;

    while(++i1 < i2)
    {
        o = array[i1] ; // you have to use the bracket operator here
        if(o.hasOwnProperty(key)) a[a.length] = o[key] ;
    }
  return a ;
}

I didn't really change all that much. The reason why your code failed is because you used the dot operator .key to access the named property of the array elements instead of the bracket operator [key]. When using a reference as a key you need to use the bracket operator.



回答5:

How about a reduce:

$.pluck = function(arr, key) { 
    return arr.reduce(function(p, v) { 
      return p.concat(v[key]); 
    }, []); 
}

var people = [
  { name: 'James', age: 26 }, 
  { name: 'Fred', age: 56 }
];

$.pluck(people, 'age');
=> [26, 56]

$.pluck(people, 'name');
=> ['James', 'Fred']


回答6:

var array = {
name: ["Pedro", "João", "Francisco", "Diogo"],
ID: [1,2,3,4]
};
console.log(pluck(array,'name'));

function pluck(array, key) {
   return (array[key]);
};

JSFiddle

You can use this function, click in JSFiddle to see a Example!! :)