How to replace a given index element in knockoutjs

问题:

How do you replace a given index in an observableArray with another element.

I have: ViewModel.Elements()[index]

how can i replace it with another element.

回答1:

observableArrays do have a replace method. This takes in the old item and the new item.

So, you would call it like:

ViewModel.Elements.replace(ViewModel.Elements()[index], yourNewElement);

Internally, this just sets that index to your new item and calls valueHasMutated() to notify any potential subscribers.

回答2:

It's a little late by now, but I have noticed that this question is still left unanswered (properly).

As the others have stated, the 1st answer does not give the expected behavior, it will replace an item of an observableArray by value and not by index!

The other answers are overly complicated and does not take advantage of Knockout's extended natives.

---

To truly replace a value in a given index of an observableArray, you should use the splice() method.

var myObservable = ko.observableArray([1, 2, 3, 4]);
myObservable.splice(0, 1, 100); // Replace the value at [0] with "100"
myObservable.splice(2, 1, 300); // Replace the value at [2] with "300"
console.log(myObservable()); // [100, 2, 300, 4]

And since the splice() method is extended by Knockout, it will automatically notify any dependencies, eliminating the need to call valueHasMutated().

EDIT / February 14th 2016

In case you need to replace multiple values at once, it'll be much quicker to get the underlying array, perform the replacement and then notify changes.

var myObservable = ko.observableArray([1, 2, 3, 4]);
var underlyingArray = myObservable();

myObservable.valueWillMutate();

for(...)
   underlyingArray[i] = newValue[i];

this.valueHasMutated();

回答3:

Like dvijaz correctly points out, the accepted answer replaces a given value. This can cause problems when the given value is not unique in the array.

Instead of slicing the array and then gluing the array back together, I did the following which is more readable IMHO:

ViewModel.Elements()[index] = yourNewElement;
ViewModel.Elements.valueHasMutated();

Thanks to RP Niemeyer for pointing out how .replace works internally.

You can also extend observableArray to support this:

ko.observableArray.fn.replaceIndex = function(index, newValue) {
    this.valueWillMutate();
    this()[index] = newValue;
    this.valueHasMutated();
};

Which means you can do the following:

var arr = ko.observableArray([1, 2, 1, 4]);
arr.replaceIndex(2, 3); 
console.log(arr()); // logs [1, 2, 3, 4]

回答4:

The question asks how to replace "a given index", rather than a given value. The accepted answer works when there are no repetitions in the observableArray, but in case there are repetitions then it will not always behave as expected. E.g. suppose we have:

index = 2;
elements = ko.observableArray([9,8,9]);

and then we use the accepted answer.

elements.replace(elements()[index], 7);

Then elements will be [7,8,9] (because replace uses indexOf, which finds the lowest index of the given value 9), whereas the question surely expects a solution that would make elements be [9,8,7].

To truly replace with newElement the item at index in an observableArray elements, you can use the following.

elements(elements.slice(0, index).concat(newElement, elements.slice(index + 1)));

Something more elegant would be nice. Though IIUC it's a question of readability rather than of performance.

回答5:

Editing the underlying array and reassigning it did the trick for me. I had trouble with other approaches.

var underlyingArray = this.someObservableArray();

// Do modifications... Swap some items...
// No one is being notified just yet...

// Reassign to observable to update everything
this.someObservableArray(underlyingArray);