URL parameters are not being passed by curl POST

问题:

This is my java code:

@POST
@Path("/sumPost")
@Produces(MediaType.TEXT_PLAIN)
public String sumPost(@QueryParam(value = "x") int x,
        @QueryParam(value = "y") int y) {
    System.out.println("x = " + x);
    System.out.println("y = " + y);
    return (x + y) + "\n";
}

I call it like this:

curl -XPOST "http://localhost:8080/CurlServer/curl/curltutorial/sumPost" -d 'x:5&y:3'

The problem is the System.out.println call keeps posting zero zero, it seems I am not passing x and y correctly.

Update

After the answer, I changed my request to:

curl   -d '{"x" : 4, "y":3}'  "http://localhost:8080/CurlServer/curl/curltutorial/sumPost" -H "Content-Type:application/json" -H "Accept:text/plain"  --include

and the service is:

@POST
@Path("/sumPost")
@Produces(MediaType.TEXT_PLAIN)
@Consumes(MediaType.APPLICATION_JSON)
public String sumPost(@QueryParam(value = "x") int x,
        @QueryParam(value = "y") int y) {
    System.out.println("sumPost");
    System.out.println("x = " + x);
    System.out.println("y = " + y);
    return (x + y) + "\n";
}

but I still have the same problem. Here is the response from the server:

HTTP/1.1 200 OK
Server: Apache-Coyote/1.1
Content-Type: text/plain
Transfer-Encoding: chunked
Date: Wed, 23 Sep 2015 11:12:38 GMT

0

You can see the zero at the end :(

回答1:

-d x=1&y=2 (notice the =, not :) is form data (application/x-www-form-urlencoded) sent it the body of the request, in which your resource method should look more like

@POST
@Path("/sumPost")
@Produces(MediaType.TEXT_PLAIN)
@Consumes(MediaType.APPLICATION_FORM_URLENCODED)
public String sumPost(@FormParam("x") int x,
                      @FormParam("y") int y) {

}

and the following request would work

curl -XPOST "http://localhost:8080/CurlServer/curl/curltutorial/sumPost" -d 'x=5&y=3'

_{Note: With Windows, double quotes are required ("x=5&y=3")}

You could even separate the key value pairs

curl -XPOST "http://localhost:8080/..." -d 'x=5' -d 'y=3'

The default Content-Type is application/x-www-form-urlencoded, so you don't need to set it.

@QueryParams are supposed to be part of the query string (part of the URL), not part of the body data. So your request should be more like

curl "http://localhost:8080/CurlServer/curl/curltutorial/sumPost?x=1&y=2"

With this though, since you are not sending any data in the body, you should probably just make the resource method a GET method.

@GET
@Path("/sumPost")
@Produces(MediaType.TEXT_PLAIN)
public String sumPost(@QueryParam("x") int x,
                      @QueryParam("y") int y) {
}

If you wanted to send JSON, then your best bet is to make sure you have a JSON provider^[1] that handle deserializing to a POJO. Then you can have something like

public class Operands {
    private int x;
    private int y;
    // getX setX getY setY
}
...
@POST
@Path("/sumPost")
@Produces(MediaType.TEXT_PLAIN)
@Consumes(MediaType.APPLICATION_JSON)
public String sumPost(Operands ops) {

}

[1]- The important thing is that you do have a JSON provider. If you don't have one, you will get an exception with a message like "No MessageBodyReader found for mediatype application/json and type Operands". I would need to know what Jersey version and if you are using Maven or not, to able to determine how you should add JSON support. But for general information you can see

• Unmarshal JSON to Java POJO in JAX-RS

回答2:

You are missing the data part of the command:

curl --data "param1=value1&param2=value2" https://example.com/fakesite.php

The -d (or --data) should come before the link. And the "name value pair" should be varName=varValue&otherVar=otherValue

Also, from documentation, the -X command is not correct:

This option only changes the actual word used in the HTTP request, it does not alter the way curl behaves. So for example if you want to make a proper HEAD request, using -X HEAD will not suffice. You need to use the -I, --head option. 

It should be -X POST

Finally, Remember to use "html encode" to encode your values.

回答3:

Have you tried calling it like this:

curl -XPOST "http://localhost:8080/CurlServer/curl/curltutorial/sumPost?x=5&y=3" 

?