How to manually call another target from a make ta

2020-02-07 18:57发布

问题:

I would like to have a makefile like this:

cudaLib :
    # Create shared library with nvcc

ocelotLib :
    # Create shared library for gpuocelot

build-cuda : cudaLib
    make build

build-ocelot : ocelotLib
    make build

build :
    # build and link with the shared library

I.e. the *Lib tasks create a library that runs cuda directly on the device, or on gpuocelot respectively.

For both build tasks I need to run the same build steps, only creating the library differs.

Is there an alternative to running make directly?

make build

Kind of a post-requisite?

回答1:

As you have written it, the build target will need to do something different depending on whether you have just done an ocelot or cuda build. That's another way of saying you have to parameterise build in some way. I suggest separate build targets (much like you already have), with associated variables. Something like:

build-cuda: cudaLib
build-ocelot: ocelotLib

build-cuda build-ocelot:
    shell commands
    which invoke ${opts-$@}

On the command-line you type make build-cuda (say). Make first builds cudaLib, then it carries out the recipe for build-cuda. It expands the macros before calling the shell. $@ in this case is build-cuda, thus ${opts-$@} is first expanded to ${opts-build-cuda}. Make now goes on to expand ${opts-build-cuda}. You will have defined opts-build-cuda (and of course its sister opts-build-ocelot) elsewhere in the makefile.

P.S. Since build-cuda et. al. are not real files, you had better tell make this (.PHONY: build-cuda).



回答2:

Note: This answer focuses on the aspect of a robust recursive invocation of a different target in a given makefile.

To complement Jack Kelly's helpful answer, here's a GNU makefile snippet that demonstrates the use of $(MAKE) to robustly invoke a different target in the same makefile (ensuring that the same make binary is called, and that the same makefile is targeted):

# Determine this makefile's path.
# Be sure to place this BEFORE `include` directives, if any.
THIS_FILE := $(lastword $(MAKEFILE_LIST))

target:
    @echo $@  # print target name
    @$(MAKE) -f $(THIS_FILE) other-target # invoke other target

other-target:
    @echo $@ # print target name

Output:

$ make target

target
other-target

Using $(lastword $(MAKEFILE_LIST)) and -f ... ensures that the $(MAKE) command uses the same makefile, even if that makefile was passed with an explicit path (-f ...) when make was originally invoked.


Note: While GNU make does have features for recursive invocations - for instance, variable $(MAKE) specifically exists to enable them - their focus is on invoking subordinate makefiles, not on calling a different target in the same makefile.

That said, even though the workaround above is somewhat cumbersome and obscure, it does use regular features and should be robust.

Here is the link to the manual section covering recursive invocations ("sub-makes"):

  • Recursive Use of make


回答3:

Most versions of make set a variable $(MAKE) that you can use for recursive invocations.



标签: gnu-make