Angular2 email validation

问题:

I am new in learning Angular2, and I want to make a validation form that verifies emails after a RegEx pattern.

My code looks something like this but I don't have any idea if I am doing it right, or what I did wrong, can somebody please help me a bit?

Thank you!

I fixed it. Thank you a lot everybody.

<div class="alert-email">
    <label for="contactemail">EMAIL: </label>
    <input type="email" id="contactemail" name="contactemail"
           required ng-pattern="/^[a-zA-Z0-9.!#$%&’*+/=?^_`{|}~-]+@[a-zA-Z0-9-]+(?:\.[a-zA-Z0-9-]+)*$/"
           [(ngModel)]="model.contactemail" #contactemail="ngModel"
           placeholder="Your email" /><br><br>
    <div *ngIf="contactemail.errors && (contactemail.dirty || contactemail.touched)" class="alert-email alert-danger-email"><br>
      <div [hidden]="!contactname.errors.required">
        Email is required
      </div>
      <div [hidden]="!contactname.errors">
        Please input a valid email.
      </div>
    </div>
  </div>

回答1:

Try Something like that

<div class="alert-email">
        <label>Email</label>
            <input
                id="contactemail"
                type="text"                
                #contactemail="ngModel"
                [(ngModel)]="model.contactemail"
                required
                pattern="^\w+([\.-]?\w+)*@\w+([\.-]?\w+)*(\.\w{2,3})+$">

        <div class="md-errors-spacer" [hidden]="contactemail.valid || contactemail.untouched">
            <div  *ngIf="contactemail.errors && contactemail.errors.required">
                Email is required
            </div>
            <div  *ngIf="contactemail.errors && contactemail.errors.pattern">
                Email is invalid
            </div>
        </div>
    </div>

回答2:

Angular 4 has a built-in "email" validation tag that can be added within the input. E.g.:

<input type="email" id="contactemail" email>

This will be valid for a series of numbers and letters then an @ then another series of letters. It will not account for the dot after the @ -- for that you can use the "pattern" tag within the input and your standard regex.

回答3:

Angular 4 Email Validation :

• Use email to your input
• If you want .com for email use pattern pattern="[a-zA-Z0-9.-_]{1,}@[a-zA-Z.-]{2,}[.]{1}[a-zA-Z]{2,}

Final :

`<input type="email" [(ngModel)]="enterEmail" name="myEmail" #myEmail="ngModel" email pattern="[a-zA-Z0-9.-_]{1,}@[a-zA-Z.-]{2,}[.]{1}[a-zA-Z]{2,}" required>`

回答4:

For multiple email validation in a single field, you can do using the custom email validator.

import { FormControl } from '@angular/forms';

export class EmailValidator {

public static isValid(email) {
    var re = /^(([^<>()\[\]\\.,;:\s@"]+(\.[^<>()\[\]\\.,;:\s@"]+)*)|(".+"))@((\[[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\])|(([a-zA-Z\-0-9]+\.)+[a-zA-Z]{2,}))$/;
    return re.test(String(email).toLowerCase());
}

static isMultiValid(control: FormControl): any {

  console.log(control.value);
  let tempEmail = control.value;
  let invalid = false;
  let regex =/[a-z0-9!#$%&'*+=?^_`{|}~-]+(?:\.[a-z0-9!#$%&'*+=?^_`{|}~-]+)*@(?:[a-z0-9](?:[a-z0-9-]*[a-z0-9])?\.)+[a-z0-9](?:[a-z0-9-]*[a-z0-9])?/g;

  if(tempEmail.indexOf(',') > -1){
    var emails = control.value.split(',');
      for (let email of emails) {
        console.log(email);
        let isValid = EmailValidator.isValid(email)
        if(!isValid){
          return{"email not valid":isValid}
        }
      }
      return null;
  }
  else{
    let email = control.value.split(',');
    if( email == "" || ! regex.test(email)){
        invalid = true;
        return {
            "email not valid": invalid
        };
    }
    console.log("valid");
    return null;

   }
  }
}

.

回答5:

You can use this pattern for your email inputs:

^[a-z0-9._%+-]+@[a-z0-9.-]+\.[a-z]{2,4}$

ref

This pattern accepts "sample@domain" also in addition of "[e-mail]". Using this email pattern "sample@domain." is not acceptable and 1 letter domain tld is not allowed ("sample@domain.s" goes wrong).

回答6:

This pattern worked for me which will accept alphanumeric characters and '.' special character.

^[\\w]+(?:\\.[\\w])*@(?:[a-zA-Z0-9-]+\\.)+[a-zA-Z]{2,6}$

回答7:

This pattern worked for me :

 pattern="[a-zA-Z0-9.-]{1,}@[a-zA-Z.-]{2,}[.]{1}[a-zA-Z]{3,}"

回答8:

Try This One it will work:

^[a-zA-Z]+([.-]?[a-zA-Z0-9]+)*@([a-zA-Z]+([.-]?[a-zA-Z]))[.]{1}[a-zA-Z]{2,}$