I was experimenting with C++17 feature std::optional
The optional return type is std::optional<std::pair<int, int>>
. I call the
sum_pair
function in print_answer
function and wanted a optional print.
In print_answer
function I wanted to check whether the required pair holds something to show.
like in the example given in: optional-returning factory functions are usable as conditions of while and if
Following is the code: here is it live with error
#include <iostream>
#include <vector>
#include <unordered_map>
#include <optional>
typedef std::optional<std::pair<int, int>> returnType;
// following algorithum works fine: just to show,
// how I have used the std::optional
returnType sum_pair(const std::vector<int>& vec, const int sum)
{
std::unordered_map<int, int> compIndexMap;
int index = 0;
for(const int& ele: vec)
{
if(auto check = compIndexMap.find(sum - ele); check != compIndexMap.cend())
return returnType{std::make_pair(check->second, index)};
compIndexMap.emplace(sum - ele, index);
++index;
}
return std::nullopt;
}
// problem is here:
void print_answer(const std::vector<int>& vec, const int sum)
{
// if I uncomment the if-else, everything works
/*if*/(auto Pair = sum_pair(vec, sum) )?
std::cout << "Resulting indexes are: " << Pair->first << " " << Pair->second << std::endl: //;
//else
std::cout << "Nothing found!\n";
}
int main()
{
std::vector<int> vec0{ 1,3,2,8 };
const int sum = 8;
print_answer(vec0, sum);
return 0;
}
When I use the if-else
statement in the following format
(condion) ? print something: print something else;
I get the following two errors. (used GCC 7.1)
||=== Build: Debug in MyTestProgram (compiler: GNU GCC Compiler) ===|
|25|error: expected primary-expression before 'auto'|
|25|error: expected ')' before 'auto'|
Can somebody explain, why I need to use if-else, but not with "operator ?" ?