Concatenate char arrays in C++

问题:

I have the following code and would like to end up with a char such as: "Hello, how are you?" (this is just an example of what I'm trying to achieve)

How can I concatenate the 2 char arrays plus adding the "," in the middle and the "you?" at the end?

So far this concatenates the 2 arrays but not sure how to add the additional characters to my final char variable I want to come up with.

#include "stdafx.h"
#include <iostream>
#include <string>
using namespace std;

int _tmain(int argc, _TCHAR* argv[])
{
    char foo[] = { "hello" };
    char test[] = { "how are" };
    strncat_s(foo, test, 12);
    cout << foo;
    return 0;
}

EDIT:

This is what I came up with after all your replies. I'd like to know if this is the best approach?

#include "stdafx.h"
#include <iostream>
#include <string>
using namespace std;

int _tmain(int argc, _TCHAR* argv[])
{
    char foo[] = { "hola" };
    char test[] = { "test" };
    string foos, tests;
    foos = string(foo);
    tests = string(test);
    string concat = foos + "  " + tests;
    cout << concat;
    return 0;
}

回答1:

In C++, use std::string, and the operator+, it is designed specifically to solve problems like this.

#include <iostream>
#include <string>
using namespace std;

int main()
{
    string foo( "hello" );
    string test( "how are" );
    cout << foo + " , " + test;
    return 0;
}

回答2:

Best thing is use std::string in C++ as other answers. If you really need to work with char try this way. didn't tested.

const char* foo = "hello";
const char* test= "how are";

char* full_text;
full_text= malloc(strlen(foo)+strlen(test)+1); 
strcpy(full_text, foo ); 
strcat(full_text, test);