In the following code, the mc
assigment works fine in Python 2 and 3.
The cc
assignment, which uses the same list comprehension within a class, works in Python 2 but fails with Python 3.
What explains this behavior?
ml1 = "a b c".split()
ml2 = "1 2 3".split()
mc = [ i1 + i2 for i1 in ml1 for i2 in ml2 ]
class Foo(object):
cl1 = ml1
cl2 = ml2
cc1 = [ i1 for i1 in cl1 ]
cc2 = [ i2 for i2 in cl2 ]
cc = [ i1 + i2 for i1 in cl1 for i2 in cl2 ]
print("mc = ", mc)
foo = Foo()
print("cc = ", foo.cc)
I get this:
(default-3.5) snafu$ python2 /tmp/z.py
('mc = ', ['a1', 'a2', 'a3', 'b1', 'b2', 'b3', 'c1', 'c2', 'c3'])
('cc = ', ['a1', 'a2', 'a3', 'b1', 'b2', 'b3', 'c1', 'c2', 'c3'])
(default-3.5) snafu$ python3 /tmp/z.py
Traceback (most recent call last):
File "/tmp/z.py", line 5, in <module>
class Foo(object):
File "/tmp/z.py", line 11, in Foo
cc = [ i1 + i2 for i1 in cl1 for i2 in cl2 ]
File "/tmp/z.py", line 11, in <listcomp>
cc = [ i1 + i2 for i1 in cl1 for i2 in cl2 ]
NameError: name 'cl2' is not defined
Why is the class variable cl2
not defined? Note that the cc2
assignment works fine, as does cc1
. Swapping cl1
and cl2
in the comprehension shows that the second loop is the one that triggers the exception, not cl2
per se.)
Versions:
(default-3.5) snafu$ python2 --version
Python 2.7.11+
(default-3.5) snafu$ python3 --version
Python 3.5.1+