I am looking some kind method to get gif frames number. i am looking on google, stackoverflow and any outher sites and i find only rubbish!! Someone know how to do it? i need only simple number of gif frames.
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问题:
回答1:
Just parse the file, gifs are pretty simple:
class GIFError(Exception): pass
def get_gif_num_frames(filename):
frames = 0
with open(filename, 'rb') as f:
if f.read(6) not in ('GIF87a', 'GIF89a'):
raise GIFError('not a valid GIF file')
f.seek(4, 1)
def skip_color_table(flags):
if flags & 0x80: f.seek(3 << ((flags & 7) + 1), 1)
flags = ord(f.read(1))
f.seek(2, 1)
skip_color_table(flags)
while True:
block = f.read(1)
if block == ';': break
if block == '!': f.seek(1, 1)
elif block == ',':
frames += 1
f.seek(8, 1)
skip_color_table(ord(f.read(1)))
f.seek(1, 1)
else: raise GIFError('unknown block type')
while True:
l = ord(f.read(1))
if not l: break
f.seek(l, 1)
return frames
回答2:
Which method are you using to load/manipulate the frame? Are you using PIL? If not, I suggest checking it out: Python Imaging Library and specifically the PIL gif page.
Now, assuming you are using PIL to read in the gif, it's a pretty simple matter to determine which frame you are looking at. seek will go to a specific frame and tell will return which frame you are looking at.
from PIL import Image
im = Image.open("animation.gif")
# To iterate through the entire gif
try:
while 1:
im.seek(im.tell()+1)
# do something to im
except EOFError:
pass # end of sequence
Otherwise, I believe you can only find the number of frames in the gif by seeking until an exception (EOFError) is raised.