Substring after last character in xslt

问题:

I can't find the exact answer for this question so I hope someone will help me here.

I have a string and I want get the substring after the last '.'. I'm using xslt 1.0.

How is this done? This is my code.

<xsl:choose>
    <xsl:otherwise> 
        <xsl:attribute name="class">method txt-align-left case-names</xsl:attribute>&#160;
        <xsl:value-of select="./@name"/> // this prints a string eg: 'something1.something2.something3'
    </xsl:otherwise>
</xsl:choose>

When i paste the suggested code I get an error message. "Parsing an XSLT stylesheet failed."

回答1:

I can't think of a way to do this with a single expression in XSLT 1.0, but you can do it with a recursive template:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:output method="xml" indent="yes" omit-xml-declaration="yes"/>

  <xsl:template match="/">
    <n>
      <xsl:call-template name="GetLastSegment">
        <xsl:with-param name="value" select="'something1.something2.something3'" />
        <xsl:with-param name="separator" select="'.'" />
      </xsl:call-template>
    </n>
  </xsl:template>

  <xsl:template name="GetLastSegment">
    <xsl:param name="value" />
    <xsl:param name="separator" select="'.'" />

    <xsl:choose>
      <xsl:when test="contains($value, $separator)">
        <xsl:call-template name="GetLastSegment">
          <xsl:with-param name="value" select="substring-after($value, $separator)" />
          <xsl:with-param name="separator" select="$separator" />
        </xsl:call-template>
      </xsl:when>
      <xsl:otherwise>
        <xsl:value-of select="$value" />
      </xsl:otherwise>
    </xsl:choose>
  </xsl:template>
</xsl:stylesheet>

Result:

<n>something3</n>

回答2:

I did the same behaviour with a xsl:function - usage is then a little bit simpler:

<xsl:function name="ns:substring-after-last" as="xs:string" xmlns:ns="yourNamespace">
    <xsl:param name="value" as="xs:string?"/>
    <xsl:param name="separator" as="xs:string"/>        
    <xsl:choose>
        <xsl:when test="contains($value, $separator)">
            <xsl:value-of select="ns:substring-after-last(substring-after($value, $separator), $separator)" />
        </xsl:when>
        <xsl:otherwise>
            <xsl:value-of select="$value" />
        </xsl:otherwise>
    </xsl:choose>
</xsl:function>

And you can call it directly in a value-of:

<xsl:value-of select="ns:substring-after-last(.,'=')" xmlns:ns="yourNamespace"/>  

回答3:

Here is a solution using EXSLT str:tokenize:

<xsl:if test="substring($string, string-length($string)) != '.'"><xsl:value-of select="str:tokenize($string, '.')[last()]" /></xsl:if> 

(the if is here because if your string ends with the separator, tokenize won't return an empty string)

回答4:

I resolved it

<xsl:call-template name="GetLastSegment">
<xsl:with-param name="value" select="./@name" />
</xsl:call-template>

Did not need the

<xsl:with-param name="separator" value="'.'" />

in the template call