How can I merge multiple Streams into a higher lev

2020-02-05 07:04发布

问题:

I have two streams, Stream<A> and Stream<B>. I have a constructor for a type C that takes an A and a B. How do I merge the two Streams into a Stream<C>?

回答1:

You can use StreamZip in package:async to combine two streams into one stream of pairs, then create the C objects from that.

import "package:async" show StreamZip;
...
Stream<C> createCs(Stream<A> as, Stream<B> bs) =>
  new StreamZip([as, bs]).map((ab) => new C(ab[0], ab[1]));


回答2:

import 'dart:async' show Stream;
import 'package:async/async.dart' show StreamGroup;

main() async {
  var s1 = stream(10);
  var s2 = stream(20);
  var s3 = StreamGroup.merge([s1, s2]);
  await for(int val in s3) {
    print(val);
  }
}

Stream<int> stream(int min) async* {
  int i = min;
  while(i < min + 10) {
    yield i++;
  }
}

See also http://news.dartlang.org/2016/03/unboxing-packages-async-part-2.html

prints

10
20
11
21
12
22
13
23
14
24
15
25
16
26
17
27
18
28
19
29


回答3:

If you need to react when either Stream<A> or Stream<B> emits an event and use the latest value from both streams, use combineLatest.

Stream<C> merge(Stream<A> streamA, Stream<B> streamB) {
  return streamA
    .transform(combineLatest(streamB, (a, b) => new C(a, b)));
}