what is the best way to compare int arrays b and c with a:
int a[] = {0,1,0,0,1};
int b[] = {0,1,0,0,1};
int c[] = {1,1,0,0,1};
b and c are just examples, assume they can be any combination of 0s and 1s.
I am trying to detect arrays identical to a. I have googled this for a while and have not found a satisfactory answer.
This is a beginners question I realise, thank you for your patience.
Use the standard memcmp
function from <string.h>
.
memcmp(a, b, sizeof(a)) == 0
whenever a
and b
are equal.
If you mean
int a[] = {0,1,0,0,1};
int b[] = {0,1,0,0,1};
int c[] = {1,1,0,0,1};
then
memcmp(a, b, sizeof(a)); /* returns zero for a match */
memcmp(a, c, sizeof(a)); /* returns nonzero for no match */
Use a loop and compare the individual elements one after another.
More information is needed on the question.
I can divide your question in two ways as below,
- Compare array contents considering order??
Ex:char a[]={a, b, c}, b[]={a, c, b} here since you are considering the order, the contents are not same so a!=b
- compare array contents irrespective of order?
Ex:char a[]={a, b, c}, b[]={a, c, b}
here if you are not considering the order, the contents are same so a==b
Solution for Question no 1:
One can use memcmp for this problem. Because memcmp will compare lexicographical and return 0 or 1 or -1 as below
#include<stdio.h>
#include<string.h>
int main()
{
char a[]={'a','b','c'};
char b[]={'a','b','c'};
int x=memcmp(a,b,sizeof(a));
printf("%d\n",x);
return 0;
}
***output:0***
#include<stdio.h>
#include<string.h>
int main()
{
char a[]={'a','c','b'};
char b[]={'a','b','c'};
int x=memcmp(a,b,sizeof(a));
printf("%d\n",x);
return 0;
}
***output:1***
#include<stdio.h>
#include<string.h>
int main()
{
char a[]={'a','b','c'};
char b[]={'b','a','c'};
int x=memcmp(a,b,sizeof(a));
printf("%d\n",x);
return 0;
}
***output:-1***
Solution for Question no 2:
One can use memcmp for this problem, the best solution for this problem is as below
Here, I answered for the above problem
https://stackoverflow.com/a/36130812/5206646