append dataframe to excel with pandas

问题:

I desire to append dataframe to excel

This code works nearly as desire. Though it does not append each time. I run it and it puts data-frame in excel. But each time I run it it does not append. I also hear openpyxl is cpu intensive but not hear of many workarounds.

import pandas
from openpyxl import load_workbook

book = load_workbook('C:\\OCC.xlsx')
writer = pandas.ExcelWriter('C:\\OCC.xlsx', engine='openpyxl')
writer.book = book
writer.sheets = dict((ws.title, ws) for ws in book.worksheets)

df1.to_excel(writer, index = False)

writer.save()

I want the data to append each time I run it, this is not happening.

Data output looks like original data:

A   B   C
H   H   H

I want after run a second time

A   B    C
H   H    H
H   H    H

Apologies if this is obvious I new to python and examples I practise did not work as wanted.

Question is - how can I append data each time I run. I try change to xlsxwriter but get AttributeError: 'Workbook' object has no attribute 'add_format'

回答1:

first of all, this post is the first piece of the solution, where you should specify startrow=: Append existing excel sheet with new dataframe using python pandas

you might also consider header=False. so it should look like:

df1.to_excel(writer, startrow = 2,index = False, Header = False)

if you want it to automatically get to the end of the sheet and append your df then use:

startrow = writer.sheets['Sheet1'].max_row

and if you want it to go over all of the sheets in the workbook:

for sheetname in writer.sheets:
    df1.to_excel(writer,sheet_name=sheetname, startrow=writer.sheets[sheetname].max_row, index = False,header= False)

btw: for the writer.sheets you could use dictionary comprehension (I think it's more clean, but that's up to you, it produces the same output):

writer.sheets = {ws.title: ws for ws in book.worksheets}

so full code will be:

import pandas
from openpyxl import load_workbook

book = load_workbook('test.xlsx')
writer = pandas.ExcelWriter('test.xlsx', engine='openpyxl')
writer.book = book
writer.sheets = {ws.title: ws for ws in book.worksheets}

for sheetname in writer.sheets:
    df1.to_excel(writer,sheet_name=sheetname, startrow=writer.sheets[sheetname].max_row, index = False,header= False)

writer.save()

回答2:

Here is a helper function:

def append_df_to_excel(filename, df, sheet_name='Sheet1', startrow=None,
                       truncate_sheet=False, 
                       **to_excel_kwargs):
    """
    Append a DataFrame [df] to existing Excel file [filename]
    into [sheet_name] Sheet.
    If [filename] doesn't exist, then this function will create it.

    Parameters:
      filename : File path or existing ExcelWriter
                 (Example: '/path/to/file.xlsx')
      df : dataframe to save to workbook
      sheet_name : Name of sheet which will contain DataFrame.
                   (default: 'Sheet1')
      startrow : upper left cell row to dump data frame.
                 Per default (startrow=None) calculate the last row
                 in the existing DF and write to the next row...
      truncate_sheet : truncate (remove and recreate) [sheet_name]
                       before writing DataFrame to Excel file
      to_excel_kwargs : arguments which will be passed to `DataFrame.to_excel()`
                        [can be dictionary]

    Returns: None
    """
    from openpyxl import load_workbook

    # ignore [engine] parameter if it was passed
    if 'engine' in to_excel_kwargs:
        to_excel_kwargs.pop('engine')

    writer = pd.ExcelWriter(filename, engine='openpyxl')

    try:
        # try to open an existing workbook
        writer.book = load_workbook(filename)

        # get the last row in the existing Excel sheet
        # if it was not specified explicitly
        if startrow is None and sheet_name in writer.book.sheetnames:
            startrow = writer.book[sheet_name].max_row

        # truncate sheet
        if truncate_sheet and sheet_name in writer.book.sheetnames:
            # index of [sheet_name] sheet
            idx = writer.book.sheetnames.index(sheet_name)
            # remove [sheet_name]
            writer.book.remove(writer.book.worksheets[idx])
            # create an empty sheet [sheet_name] using old index
            writer.book.create_sheet(sheet_name, idx)

        # copy existing sheets
        writer.sheets = {ws.title:ws for ws in writer.book.worksheets}
    except FileNotFoundError:
        # file does not exist yet, we will create it
        pass

    if startrow is None:
        startrow = 0

    # write out the new sheet
    df.to_excel(writer, sheet_name, startrow=startrow, **to_excel_kwargs)

    # save the workbook
    writer.save()

Usage examples:

filename = r'C:\OCC.xlsx'

append_df_to_excel(filename, df)

append_df_to_excel(filename, df, header=None, index=False)

append_df_to_excel(filename, df, sheet_name='Sheet2', index=False)

append_df_to_excel(filename, df, sheet_name='Sheet2', index=False, startrow=25)

回答3:

I tried to read an excel, put it in a dataframe and then concat the dataframe from excel with the desired dataframe. It worked for me.

def append_df_to_excel(df, excel_path):
    df_excel = pd.read_excel(excel_path)
    result = pd.concat([df_excel, df], ignore_index=True)
    result.to_excel(excel_path, index=False)

df = pd.DataFrame({"a":[11,22,33], "b":[55,66,77]})
append_df_to_excel(df, r"<path_to_dir>\<out_name>.xlsx")