How to prevent a Command Line Tool from exiting be

问题:

In a swift 2 command line tool (main.swift), I have the following:

import Foundation
print("yay")

var request = HTTPTask()
request.GET("http://www.stackoverflow.com", parameters: nil, completionHandler: {(response: HTTPResponse) in
    if let err = response.error {
        print("error: \(err.localizedDescription)")
        return //also notify app of failure as needed
    }
    if let data = response.responseObject as? NSData {
        let str = NSString(data: data, encoding: NSUTF8StringEncoding)
        print("response: \(str)") //prints the HTML of the page
    }
})

The console shows 'yay' and then exits (Program ended with exit code: 0), seemingly without ever waiting for the request to complete. How would I prevent this from happening?

The code is using swiftHTTP

I think I might need an NSRunLoop but there is no swift example

回答1:

I realize this is an old question, but here is the solution I ended on. Using DispatchGroup.

let dispatchGroup = DispatchGroup()

for someItem in items {
    dispatchGroup.enter()
    doSomeAsyncWork(item: someItem) {
        dispatchGroup.leave()
    }
}

dispatchGroup.notify(queue: DispatchQueue.main) {
    exit(EXIT_SUCCESS)
}
dispatchMain()

回答2:

Adding RunLoop.main.run() to the end of the file is one option. More info on another approach using a semaphore here

回答3:

You can call dispatchMain() at the end of main. That runs the GCD main queue dispatcher and never returns so it will prevent the main thread from exiting. Then you just need to explicitly call exit() to exit the application when you are ready (otherwise the command line app will hang).

import Foundation

let url = URL(string:"http://www.stackoverflow.com")!
let dataTask = URLSession.shared.dataTask(with:url) { (data, response, error) in
    // handle the network response
    print("data=\(data)")
    print("response=\(response)")
    print("error=\(error)")

    // explicitly exit the program after response is handled
    exit(EXIT_SUCCESS)
}
dataTask.resume()

// Run GCD main dispatcher, this function never returns, call exit() elsewhere to quit the program or it will hang
dispatchMain()

回答4:

Don't depend on timing.. You should try this

let sema = DispatchSemaphore( value: 0)

let url = URL(string: "https://upload.wikimedia.org/wikipedia/commons/4/4d/Cat_November_2010-1a.jpg")!;

let task = URLSession.shared.dataTask(with: url) { (data, response, error) in
  print("after image is downloaded");
  sema.signal(); // signals the process to continue
};

task.resume();
sema.wait(); // sets the process to wait

回答5:

If your need isn't something that requires "production level" code but some quick experiment or a tryout of a piece of code, you can do it like this :

SWIFT 3

//put at the end of your main file
RunLoop.main.run(until: Date(timeIntervalSinceNow: 15))  //will run your app for 15 seconds only

More info : https://stackoverflow.com/a/40870157/469614

---

Please note that you shouldn't rely on fixed execution time in your architecture.

回答6:

Swift 4: RunLoop.main.run()

At the end of your file