I want to make a drawable for my Android button, defined as drawable. I found I could set all the borders by using a rectangle, but I got kinda stuck when I wanted it on three sides. I want for example have either the top or the bottom open.
Could anyone show me how to do this?
Try doing this, though I saw it on some other post
<?xml version="1.0" encoding="utf-8"?>
<layer-list xmlns:android="http://schemas.android.com/apk/res/android" >
<item>
<shape android:shape="rectangle" >
<solid android:color="#FFFFFF" />
<padding
//android:bottom="10dp" Remove this to avoid seeing the bottom border
android:left="10dp"
android:right="10dp"
//android:top="10dp" Remove this to avoid seeing the top border
/>
<corners android:radius="5dp" />
</shape>
</item>
<item>
<shape android:shape="rectangle" >
<padding
android:bottom="5dp"
android:left="5dp"
android:right="5dp"
android:top="5dp" />
<solid android:color="#666666" />
</shape>
</item>
</layer-list>
https://stackoverflow.com/a/10133434/1244489
If anyone is running into issues regarding padding taking effect in the accepted answer, try taking a look at: https://stackoverflow.com/a/11006931. That solution uses position attributes on the tags to achieve the same effect.
I was having trouble using the accepted answer here while creating drawables for use in an ActionBar, and the linked approach worked for me.
This might help you.
I The border on Three sides of the XML
<?xml version="1.0" encoding="utf-8"?>
<layer-list xmlns:android="http://schemas.android.com/apk/res/android" >
<item android:left="0dp" android:right="0dp"
android:top="0dp" android:bottom="-5dp">
<shape
android:shape="rectangle">
<solid android:color="#ffffff" />
<corners android:radius="0dp" />
<stroke android:width="3dp" android:color="#000000" />
</shape>
</item>
