How can I make multiple empty lists in python?

问题:

How can I make many empty lists without manually typing

list1=[] , list2=[], list3=[]

Is there a for loop that will make me 'n' number of such empty lists?

回答1:

A list comprehension is easiest here:

>>> n = 5
>>> lists = [[] for _ in range(n)]
>>> lists
[[], [], [], [], []]

Be wary not to fall into the trap that is:

>>> lists = [[]] * 5
>>> lists
[[], [], [], [], []]
>>> lists[0].append(1)
>>> lists
[[1], [1], [1], [1], [1]]

回答2:

If you want to create different lists without a "list of lists", try this:

list1, list2, list3, list4 = ([] for i in range(4))

回答3:

Lookup list comprehensions

listOfLists = [[] for i in range(N)]

Now, listOfLists has N empty lists in it

More links on list comprehensions:

1 2 3

Hope this helps

回答4:

Sorry that I am two years late, but maybe I can still help some other people.

The code below will dynamically 'create' itself. For every iteration, the following command will issued:

listnumber = []

Where number is the value of i in the loop.

x = 3 # amount of lists you want to create
for i in range(1, x+1):
    command = "" # this line is here to clear out the previous command
    command = "list" + str(i) + " = []"
    exec(command)

The result of this particular piece of code is three variables: list1, list2 and list3 being created and each assigned an empty list.

You can generalize this to make practically anything you want. Do note that you cannot put this into a function as far as I know, because of how variables and global variables work.

name = "my_var" # This has to be a string, variables like my_var1, my_var2 will be created.
value = "[]" # This also has to be a string, even when you want to assign integers! When you want to assign a string "3", you'd do this: value = "'3'"
amount = 5 # This must be an integer. This many variables will be created (my_var1, my_var2 ... my_var5).

for i in range(1, amount+1):
    command_variable = ""
    command_variable = name + str(i) + " = " + value
    exec(command_variable)

I hope I helped!

回答5:

How about this.

def mklist(n):
    for _ in range(n):
        yield []

Usage:

list(mklist(10))
[[], [], [], [], [], [], [], [], [], []]

a, b, c = mklist(3) # a=[]; b=[]; c=[]

回答6:

You can also add a list of list of list of list... like this too. It won't return any error. But i got no idea what it's use for.

n = 5 
>>> lists = [[[]]] for _ in range(n)]
>>> lists
   [[[[]]], [[[]]], [[[]]], [[[]]], [[[]]]]

回答7:

I see that many answers here get you many lists with no names assigned (as elements of a larger list). This may be not always what's needed. It is possible to create multiple empty lists, each with a different name/value, using a tuple:

a,b,c = ([],[],[])

changing this structure should get you what you want.