How can restrict my EditText input to some special

2020-02-02 11:24发布

问题:

I am developing an application for keyboard, but i am geting an issue. I want to restrict/block some special character from soft keyboard in EditText in android programmatically.

So, Is there any way i can restrict any special character input in edit text in android.

If anyone have idea,Please reply.

Thanks in advance.

回答1:

Try this may works for you

public class MainActivity extends Activity {

    private EditText editText;
    private String blockCharacterSet = "~#^|$%&*!";

    private InputFilter filter = new InputFilter() {

        @Override
        public CharSequence filter(CharSequence source, int start, int end, Spanned dest, int dstart, int dend) {

            if (source != null && blockCharacterSet.contains(("" + source))) {
                return "";
            }
            return null;
        }
    };

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        editText = (EditText) findViewById(R.id.editText);
        editText.setFilters(new InputFilter[] { filter });
    }

}


回答2:

This should work:

InputFilter filter = new InputFilter() { 
        public CharSequence filter(CharSequence source, int start, int end, 
Spanned dest, int dstart, int dend) { 
                for (int i = start; i < end; i++) { 
                        if (!Character.isLetterOrDigit(source.charAt(i))) { 
                                return ""; 
                        } 
                } 
                return null; 
        } 
}; 

edit.setFilters(new InputFilter[]{filter});

Or if you prefer the easy way:

<EditText android:inputType="text" android:digits="0123456789*,qwertzuiopasdfghjklyxcvbnm" />


回答3:

If you want to add spaces you can give space after the last digit.

  android:digits="0123456789qwertzuiopasdfghjklyxcvbnm "


回答4:

check this link which shows How to restrict special characters from an Android EditText field?

Try this code android:digits="abcde.....012345789" i guess this is the easiest way to do.Hope this help you.



回答5:

Its late but may be helpfull for others. Instead of programaticaly, you can go with xml attribute. It may be the case that in Single layout you have many editText, out of which you wanna restrict special characters only in one EditText. So defining in xml will help you out. Here is the code to restrict special Characters by allowing them to only enter alphabets and numbers like below

<EditText
     android:id="@+id/editText"
     android:layout_width="match_parent"
     android:layout_height="wrap_content"
     android:textSize="@dimen/text10"
     android:singleLine="true"
     android:maxLines="1"
     android:maxLength="16"
     android:digits="abcdefghijklmnopqrstuvwxyz0123456789"/>


回答6:

For those who might be facing issues while adding space please add a blank space with all the alphabets. Below is an example Also you should know that user won't be able to add a new line in this case.

            <EditText
            android:layout_width="match_parent"
            android:layout_height="wrap_content"
            android:inputType="text"
            android:digits="0123456789,a bcdefghijklmnopqrstuvwxyz"
            android:maxLines="1"
            android:singleLine="true" />


回答7:

You can create regular expression and check it on onTextChanged method

yourEditText.addTextChangedListener(new TextWatcher() {

          public void afterTextChanged(Editable s) {

            // you can call or do what you want with your EditText here
            yourEditText. ... 

          }

          public void beforeTextChanged(CharSequence s, int start, int count, int after) {}

          public void onTextChanged(CharSequence s, int start, int before, int count) {}
       });


回答8:

you can prevent for typing special character:

yourEditText.addTextChangedListener(new TextWatcher() {
      CharSequence previous;
      public void afterTextChanged(Editable s) {
        if(s.toString().contains("&^%$#*&(")){
              s.clear();
              s.append(previous.toString());
        }
      }

      public void beforeTextChanged(CharSequence s, int start, int count, int after) {    
            previous = s;
      }

      public void onTextChanged(CharSequence s, int start, int before, int count) {}
   });


回答9:

First need to add DigitsKeyListener for allowing characters and then setRawInputType to edittext field

edit_field.setKeyListener(DigitsKeyListener.getInstance("ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz"));


edit_field.setRawInputType(InputType.TYPE_TEXT_VARIATION_PERSON_NAME);


回答10:

Unfortunately the accepted solution doesn't work in all the cases. The proper solution would be to use the following InputFilter:

private InputFilter filter = new InputFilter() {
    // An example pattern that restricts the input only to the lowercase letters
    private static final Pattern restrictedChars = Pattern.compile("[a-z]*")

    @Override
    public CharSequence filter(CharSequence source, int start, int end, Spanned dest, int dstart, int dend) {
        final CharSequence replacementText = source.subSequence(start, end);
        final CharSequence replacedText = dest.subSequence(dstart, dend);

        if (source == null || restrictedChars.matcher(replacementText).matches()) {
            return null; // Accept the original replacement
        }

        return replacedText; // Keep the original text
    }
};

This solution differs from the accepted one in that it solves the following problems:

  • only a subsequence of the source is the replacement, not the full source
  • source doesn't necessarily include only the newly typed text, sometimes it is the full text typed so-far