C# how to use enum with switch

问题:

I can't figure out how to use switches in combination with an enum. Could you please tell me what I'm doing wrong, and how to fix it? I have to use an enum to make a basic calculator.

public enum Operator
{
    PLUS, MINUS, MULTIPLY, DIVIDE
}

public double Calculate(int left, int right, Operator op)
{

    int i = (int) op;

    switch(i)
    {
        case 0:
        {
            return left + right;
        }

        case 1:
        {
            return left - right;
        }

        case 2:
        { 
            return left * right;
        }

        case 3:
        {
            return left / right;
        }

        default:
        {
            return 0.0;
        }
    }
}

The end result should be something like this:

Console.WriteLine("The sum of 5 and 5 is " + Calculate(5, 5, PLUS))
Output: The sum of 5 and 5 is 10

Could you guys please tell me how I'm messing up?

回答1:

You don't need to convert it

switch(op)
{
     case Operator.PLUS:
     {
        // your code 
        // for plus operator
        break;
     }
     case Operator.MULTIPLY:
     {
        // your code 
        // for MULTIPLY operator
        break;
     }
     default: break;
}

By the way, use brackets

回答2:

The correct answer is already given, nevertheless here is the better way (than switch):

private Dictionary<Operator, Func<int, int, double>> operators =
    new Dictionary<Operator, Func<int, int, double>>
    {
        { Operator.PLUS, ( a, b ) => a + b },
        { Operator.MINUS, ( a, b ) => a - b },
        { Operator.MULTIPLY, ( a, b ) => a * b },
        { Operator.DIVIDE ( a, b ) => (double)a / b },
    };

public double Calculate( int left, int right, Operator op )
{
    return operators.ContainsKey( op ) ? operators[ op ]( left, right ) : 0.0;
}

回答3:

Since C# 8.0 introduced a new switch expression for enums you can do it even more elegant:

public double Calculate(int left, int right, Operator op) =>
            op switch 
        {
            Operator.PLUS => left + right,
            Operator.MINUS => left - right,
            Operator.MULTIPLY => left * right,
            Operator.DIVIDE => left / right,
            _    =>  0
        }

Ref. https://docs.microsoft.com/en-us/dotnet/csharp/whats-new/csharp-8

回答4:

simply don't cast to int

 switch(operator)
    {
       case Operator.Plus:
       //todo

回答5:

You should not cast to integer. And for the division, you need to cast left to double first, if not you will be doing an integer divide.

public enum Operator
{
    PLUS, MINUS, MULTIPLY, DIVIDE
}

public double Calculate(int left, int right, Operator op)
{
    double sum = 0.0;

    switch(op)
    {
       case Operator.PLUS:
       sum = left + right;
       return sum;

       case Operator.MINUS:
       sum = left - right;
       return sum;

       case Operator.MULTIPLY:
       sum = left * right;
       return sum;

       case Operator.DIVIDE:
       sum = (double)left / right;
       return sum;

       default:
       return sum;
   }

   return sum;
}

回答6:

 public enum Operator
    {
        PLUS, MINUS, MULTIPLY, DIVIDE
    }

    public class Calc
    {
        public void Calculate(int left, int right, Operator op)
        {

            switch (op)
            {
                case Operator.DIVIDE:
                    //Divide
                    break;
                case Operator.MINUS:
                    //Minus
                    break;
                case Operator.MULTIPLY:
                    //...
                    break;
                case Operator.PLUS:
                    //;;
                    break;
                default:
                    throw new InvalidOperationException("Couldn't process operation: " + op);
            }
        }
    }

回答7:

In case you don't want to use return statement for each case, try this:

Calculate(int left, int right, Operator op)
{
   int result = 0;
   switch(op)
   {
        case Operator.PLUS:
        {
            result = left + right;;  
        }
        break;
        ....
   }

   return result;
}

回答8:

All the other answers are correct, but you also need to call your method correctly:

Calculate(5, 5, Operator.PLUS))

And since you use int for left and right, the result will be int as well (3/2 will result in 1). you could cast to double before calculating the result or modify your parameters to accept double

回答9:

Two things. First, you need to qualify the enum reference in your test - rather than "PLUS", it should be "Operator.PLUS". Second, this code would be a lot more readable if you used the enum member names rather than their integral values in the switch statement. I've updated your code:

public enum Operator
{
    PLUS, MINUS, MULTIPLY, DIVIDE
}

public static double Calculate(int left, int right, Operator op)
{
    switch (op)
    {
        default:
        case Operator.PLUS:
            return left + right;

        case Operator.MINUS:
            return left - right;

        case Operator.MULTIPLY:
            return left * right;

        case Operator.DIVIDE:
            return left / right;
    }
}

Call this with:

Console.WriteLine("The sum of 5 and 5 is " + Calculate(5, 5, Operator.PLUS));

回答10:

Your code is fine. In case you're not sure how to use Calculate function, try

Calculate(5,5,(Operator)0); //this will add 5,5
Calculate(5,5,Operator.PLUS);// alternate

Default enum values start from 0 and increase by one for following elements, until you assign different values. Also you can do :

public enum Operator{PLUS=21,MINUS=345,MULTIPLY=98,DIVIDE=100};

回答11:

No need to convert. You can apply conditions on Enums inside a switch. Like so,

public enum Operator
{ 
    PLUS,
    MINUS,
    MULTIPLY,
    DIVIDE
}

public double Calculate(int left, int right, Operator op)
{
    switch (op)
    {
        case Operator.PLUS: return left + right; 
        case Operator.MINUS: return left - right; 
        case Operator.MULTIPLY: return left * right;
        case Operator.DIVIDE: return left / right;
        default: return 0.0; 
    }
}

Then, call it like this:

Console.WriteLine("The sum of 5 and 5 is " + Calculate(5, 5, Operator.PLUS));