I got an official answer to this question that decltype
should not trigger function compilation. In fact decltype
on a function that is declared but not defined is legal.
Next question, should taking the address of a function trigger the compilation of a function? Take this example:
template <typename T>
void foo(T&& x) { x.func(); }
int main()
{
auto bar = &foo<int>;
}
All the compilers I've tested fail with an error like:
Request for member func
in x
, which is of non-class type int
But if I just define foo
and don't declare it, the code compiles fine. Can someone provide me with an official source on whether taking the address of a function should require it's compilation?
3.2/2:
An expression is potentially evaluated unless it is an unevaluated
operand (Clause 5) or a subexpression thereof. ... A non-overloaded
function whose name appears as a potentially-evaluated expression or a
member of a set of candidate functions, if selected by overload
resolution when referred to from a potentially-evaluated expression,
is odr-used, unless it is a pure virtual function and its name is not
explicitly qualified.
Then 3.2/3:
Every program shall contain exactly one definition of every non-inline
function or variable that is odr-used in that program; no diagnostic
required. The definition can appear explicitly in the program, it can
be found in the standard or a user-defined library, or (when
appropriate) it is implicitly defined (see 12.1, 12.4 and
12.8). An inline function shall be defined in every translation unit in which it is odr-used.
The function name is definitely not an unevaluated operand (for example to sizeof
, decltype
), AND it appears in an expression, so it's potentially evaluated. Then the second one requires exactly one non-inline definition, or identical inline definitions in each translation unit.