How do I eliminate line break from fgets function

问题:

I am attempting to make a gallery that calls the image names from a flat file database using the PHP 'fgets' function. There are different sections in the gallery, each with it's own default image, and a small list of images that the users can select from. Everything is working fine, except for one button.

I have one button on the page that is supposed to reset all the galleries to their default images using Javascript OnClick. It works exactly as I want it to, with one small hitch: It copies the line break at the end of the line allong with the characters on the line, breaking the Javascript.

The offending code:

function back(){
document.getElementById('back').className='back';
document.getElementById('one').className='cellcont';

//This should output the proper javascript, but does not
<?php
$a = fopen('c.txt','r');
if (!$a) {echo 'ERROR: Unable to open file.'; exit;}
$b = fgets($a);
echo "document.getElementById('i1').src='$b';";
fclose($a);
?>

}

How it outputs:

function back(){
document.getElementById('back').className='back';
document.getElementById('one').className='cellcont';
document.getElementById('i1').src='00.jpg
';}

As you can see, the ending quotation mark and the semi-colon falls on the next line, and this breaks the button.

With the files I'm using now, I can get around this problem by changing, "fgets($a)" to, "fgets($a, 7)" but I need to have it grab the entire line so that if the client decides to enter a file with a longer name, it does not break the gallery on them.

回答1:

Your best bet is to use the php trim() function. See http://php.net/manual/en/function.trim.php

$b = trim(fgets($a));

回答2:

Use rtrim().

Specifically:

rtrim($var, "\r\n");

(To avid trimming other characters, pass in just newline.)

回答3:

$b = fgets($a);
$b = preg_replace("/[\n|\r]/",'',$b);