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问题:
I have a Java Property file and there is a KEY
as ORDER
. So I retrieve the VALUE
of that KEY
using the getProperty()
method after loading the property file like below.:
String s = prop.getProperty("ORDER");
then
s ="SALES:0,SALE_PRODUCTS:1,EXPENSES:2,EXPENSES_ITEMS:3";
I need to create a HashMap from above string. SALES,SALE_PRODUCTS,EXPENSES,EXPENSES_ITEMS
should be KEY
of HashMap and 0,1,2,3,
should be VALUE
s of KEY
s.
If it's hard corded, it seems like below:
Map<String, Integer> myMap = new HashMap<String, Integer>();
myMap.put("SALES", 0);
myMap.put("SALE_PRODUCTS", 1);
myMap.put("EXPENSES", 2);
myMap.put("EXPENSES_ITEMS", 3);
回答1:
Use the String.split()
method with the ,
separator to get the list of pairs. Iterate the pairs and use split()
again with the :
separator to get the key and value for each pair.
Map<String, Integer> myMap = new HashMap<String, Integer>();
String s = "SALES:0,SALE_PRODUCTS:1,EXPENSES:2,EXPENSES_ITEMS:3";
String[] pairs = s.split(",");
for (int i=0;i<pairs.length;i++) {
String pair = pairs[i];
String[] keyValue = pair.split(":");
myMap.put(keyValue[0], Integer.valueOf(keyValue[1]));
}
回答2:
You can do that with Guava's Splitter.MapSplitter:
Map<String, String> properties = Splitter.on(",").withKeyValueSeparator(":").split(inputString);
回答3:
In one line :
HashMap<String, Integer> map = (HashMap<String, Integer>) Arrays.asList(str.split(",")).stream().map(s -> s.split(":")).collect(Collectors.toMap(e -> e[0], e -> Integer.parseInt(e[1])));
Details:
1) Split entry pairs and convert string array to List<String>
in order to use java.lang.Collection.Stream
API from Java 1.8
Arrays.asList(str.split(","))
2) Map the resulting string list "key:value"
to a string array with [0] as key and [1] as value
map(s -> s.split(":"))
3) Use collect
terminal method from stream API to mutate
collect(Collector<? super String, Object, Map<Object, Object>> collector)
4) Use the Collectors.toMap()
static method which take two Function to perform mutation from input type to key and value type.
toMap(Function<? super T,? extends K> keyMapper, Function<? super T,? extends U> valueMapper)
where T is the input type, K the key type and U the value type.
5) Following lambda mutate String
to String
key and String
to Integer
value
toMap(e -> e[0], e -> Integer.parseInt(e[1]))
Enjoy the stream and lambda style with Java 8
. No more loops !
回答4:
Assuming no key contains either ','
or ':'
:
Map<String, Integer> map = new HashMap<String, Integer>();
for(final String entry : s.split(",")) {
final String[] parts = entry.split(":");
assert(parts.length == 2) : "Invalid entry: " + entry;
map.put(parts[0], new Integer(parts[1]));
}
回答5:
I recommend using com.fasterxml.jackson.databind.ObjectMapper
(Maven repo link: https://mvnrepository.com/artifact/com.fasterxml.jackson.core) like
final ObjectMapper mapper = new ObjectMapper();
Map<String, Object> mapFromString = new HashMap<>();
try {
mapFromString = mapper.readValue(theStringToParse, new TypeReference<Map<String, Object>>() {
});
} catch (IOException e) {
LOG.error("Exception launched while trying to parse String to Map.", e);
}
回答6:
Use StringTokenizer to parse the string.
String s ="SALES:0,SALE_PRODUCTS:1,EXPENSES:2,EXPENSES_ITEMS:3";
Map<String, Integer> lMap=new HashMap<String, Integer>();
StringTokenizer st=new StringTokenizer(s, ",");
while(st.hasMoreTokens())
{
String [] array=st.nextToken().split(":");
lMap.put(array[0], Integer.valueOf(array[1]));
}
回答7:
You can to use split to do it:
String[] elements = s.split(",");
for(String s1: elements) {
String[] keyValue = s1.split(":");
myMap.put(keyValue[0], keyValue[1]);
}
Nevertheless, myself I will go for guava based solution.
https://stackoverflow.com/a/10514513/1356883
回答8:
You can also use JSONObject class from json.org to this will convert your HashMap to JSON string which is well formatted
Example:
Map<String,Object> map = new HashMap<>();
map.put("myNumber", 100);
map.put("myString", "String");
JSONObject json= new JSONObject(map);
String result= json.toString();
System.out.print(result);
result:
{'myNumber':100, 'myString':'String'}
Your can also get key from it like
System.out.print(json.get("myNumber"));
result:
100
回答9:
try
String s = "SALES:0,SALE_PRODUCTS:1,EXPENSES:2,EXPENSES_ITEMS:3";
HashMap<String,Integer> hm =new HashMap<String,Integer>();
for(String s1:s.split(",")){
String[] s2 = s1.split(":");
hm.put(s2[0], Integer.parseInt(s2[1]));
}
回答10:
String mapString=hasmap.toString();
Pattern p = Pattern.compile("[\\{\\}\\=\\, ]++");
String[] split = p.split(mapString);
for more info click here