Configure spring boot to redirect 404 to a single

问题:

I want to configure my Spring Boot app to redirect any 404 not found request to my single page app.

For example if I am calling localhost:8080/asdasd/asdasdasd/asdasd which is does not exist, it should redirect to localhost:8080/notFound.

The problem is that I have a single page react app and it runs in the root path localhost:8080/. So spring should redirect to localhost:8080/notFound and then forward to / (to keep route).

回答1:

This should do the trick: Add an error page for 404 that routes to /notFound, and forward that to your SPA (assuming the entry is on /index.html):

@Configuration
public class WebApplicationConfig extends WebMvcConfigurerAdapter {

    @Override
    public void addViewControllers(ViewControllerRegistry registry) {
        registry.addViewController("/notFound").setViewName("forward:/index.html");
    }


    @Bean
    public EmbeddedServletContainerCustomizer containerCustomizer() {
        return container -> {
            container.addErrorPages(new ErrorPage(HttpStatus.NOT_FOUND,
                    "/notFound"));
        };
    }

}

回答2:

This is the full Spring Boot 2.0 example:

@Configuration
public class WebApplicationConfig implements WebMvcConfigurer {

@Override
public void addViewControllers(ViewControllerRegistry registry) {
    registry.addViewController("/notFound").setViewName("forward:/index.html");
}


@Bean
public WebServerFactoryCustomizer<ConfigurableServletWebServerFactory> containerCustomizer() {
    return container -> {
        container.addErrorPages(new ErrorPage(HttpStatus.NOT_FOUND,
                "/notFound"));
    };
  }

}

回答3:

In case anyone stumbles here looking for how to handle Angular/React/other routes and paths in a Spring Boot app - but not always return index.html for any 404 - it can be done in a standard Spring controller RequestMapping. This can be done without adding view controllers and/or customizing the container error page.

The RequestMapping supports wild cards, so you can make it match against a set of well known paths (ie. angular routes etc.) in your application and only then return forward index.html:

@Controller 
public class Html5PathsController { 

    @RequestMapping( method = {RequestMethod.OPTIONS, RequestMethod.GET}, path = {"/path1/**", "/path2/**", "/"} )
    public String forwardAngularPaths() { 
        return "forward:/index.html"; 
    } 
}

Another option (borrowed from an old Spring article here: https://spring.io/blog/2015/05/13/modularizing-the-client-angular-js-and-spring-security-part-vii) is to use a naming convention:

@Controller 
public class Html5PathsController { 

    @RequestMapping(value = "/{[path:[^\\.]*}")
    public String redirect() {
        return "forward:/index.html";
    } 
}

The above configuration will match all paths that do not contain a period and are not already mapped to another controller.

回答4:

Here the security configuration (SecurityConfig.java)

@Configuration
@EnableWebSecurity
@EnableGlobalMethodSecurity(prePostEnabled=true)
public class SecurityConfig extends WebSecurityConfigurerAdapter {
    @Autowired
    private Environment env;

    @Autowired
    private UserSecurityService userSecurityService;

    private BCryptPasswordEncoder passwordEncoder() {
        return SecurityUtility.passwordEncoder();
    }

    private static final String[] PUBLIC_MATCHERS = {
            "/css/**",
            "/js/**",
            "/data/**",
            "/sound/**",
            "/img/**",
            "/",
            "/login",
            "/logout,
            "/error",
            "/index2",
    };

    @Override
    protected void configure(HttpSecurity http) throws Exception {
        http
            .authorizeRequests().
        /*  antMatchers("/**").*/
            antMatchers(PUBLIC_MATCHERS).
            permitAll().anyRequest().authenticated();
        //.logout().logoutRequestMatcher(new AntPathRequestMatcher("/logout")).logoutSuccessUrl("/login");

        http
            .csrf().disable().cors().disable()
            .formLogin().failureUrl("/login?error")
            .defaultSuccessUrl("/index2")
            .loginPage("/login").permitAll()
            .and()
            .logout().logoutRequestMatcher(new AntPathRequestMatcher("/logout"))
            .logoutSuccessUrl("/?logout").deleteCookies("remember-me").permitAll()
            .and()
            .rememberMe()
            .and()
            .sessionManagement().maximumSessions(3600)
            .and().
            invalidSessionUrl("/login");
    }

    @Autowired
    public void configureGlobal(AuthenticationManagerBuilder auth) throws Exception {
        auth.userDetailsService(userSecurityService).passwordEncoder(passwordEncoder());
    }
}

If not found any resource redirect to error page

@Controller
public class IndexController implements ErrorController{

    private static final String PATH = "/error";

    @RequestMapping(value = PATH)
    public String error() {
        return PATH;
    }

    @Override
    public String getErrorPath() {
        return PATH;
    }
}

Error page like

<!DOCTYPE html>
<html lang="en" xmlns:th="http://www.w3.org/1000/xhtml"
    xmlns:sec="http://www.thymeleaf.org/extras/spring-security">
    <meta http-equiv="refresh" content="5;url=/login" />
<body>
 <h1>Page not found please login the system!</h1>
</body>
</html>

回答5:

//add this controller : perfect solution(from jhipster)
@Controller
public class ClientForwardController {
    @GetMapping(value = "/**/{path:[^\\.]*}")
    public String forward() {
        return "forward:/";
    }
}

回答6:

Simply implementing the org.springframework.boot.web.servlet.error.ErrorController did the trick for me. I use SpringBoot 2.0 with React. (If you are interested in how to do that here is a boilerplate project made by me: https://github.com/archangel1991/react-with-spring)

@Controller
public class CustomErrorController implements ErrorController {

    @Override
    public String getErrorPath() {
        return "/error";
    }
}

I am not sure why is this working though.