I need to create a CSS shape like this image..
Please check this fiddle of my work
I have created something like that, but I cannot give a curve to it.
#shape {
border-left: 70px solid transparent;
border-top: 100px solid red;
height: 0;
width: 200px;
}
Can anyone help me?
You can use a pseudo element with border-radius and background-shadows to create the curve and enable a transparent background for the curve.
Output :
#shape {
width: 300px; height: 100px;
position: relative;
overflow: hidden;
}
#shape:before {
content: '';
position: absolute;
top: 10%; right: 0;
width: 300%;
padding-bottom: 300%;
border-radius: 100%;
background: none;
box-shadow: 10px -10px 5px 300px #F15723;
z-index: -1;
}
body{background:url(https://farm9.staticflickr.com/8461/8048823381_0fbc2d8efb.jpg);background-size:cover;}
<div id="shape"></div>
demo
Variant #01:
CSS3 linear-gradient()
can draw this background as well:
CSS:
div {
background: linear-gradient(45deg, transparent 50px, tomato 50px);
}
Output Image:
body {
background: linear-gradient(lightgreen, green);
min-height: 100vh;
margin: 0;
}
div {
background: linear-gradient(45deg, transparent 50px, tomato 50px);
height: 150px;
margin: 20px;
width: 400px;
}
<div>
</div>
Variant #02:
We can use :before
and :after
pseudo elements and use css3 transformation to make this shape with round corners.
body {
background: linear-gradient(lightgreen, green);
min-height: 100vh;
margin: 0;
}
div {
border-radius: 10px;
position: relative;
overflow: hidden;
height: 150px;
margin: 20px;
width: 400px;
}
div:before {
border-radius: 0 0 10px 10px;
transform-origin: 100% 0;
transform: skewY(45deg);
background: tomato;
position: absolute;
width: 45px;
z-index: -1;
content: '';
bottom: -5px;
left: 0;
top: 0;
}
div:after {
border-radius: 0 10px 10px 10px;
background: tomato;
position: absolute;
content: '';
left: 35px;
bottom: 0;
right: 0;
top: 0;
}
<div>
</div>