Unsetting array values in a foreach loop [duplicat

问题:

This question already has answers here:

How do you remove an array element in a foreach loop? (8 answers)

Closed 3 years ago.

I have a foreach loop set up to go through my array, check for a certain link, and if it finds it removes that link from the array.

My code:

foreach($images as $image)
{
    if($image == 'http://i27.tinypic.com/29yk345.gif' ||
    $image == 'http://img3.abload.de/img/10nx2340fhco.gif' ||
    $image == 'http://i42.tinypic.com/9pp2456x.gif')
    {
        unset($images[$image]);
    }
}

But it doesn't remove the array entires. It's probably something to do with $images[$image], as that's not the key of the array entry, only the content? Is there a way to do this without incorporating a counter?

Thanks.

EDIT: Thanks guys, but now I have another problem where the array entries don't actually get deleted.

My new code:

foreach($images[1] as $key => $image)
{
    if($image == 'http://i27.tinypic.com/29yk345.gif')
    $image == 'http://img3.abload.de/img/10nx2340fhco.gif' ||
    $image == 'http://i42.tinypic.com/9pp2456x.gif')
    {
        unset($images[$key]);
    }
}

$images is actuallty a two-dimensional array now hence why I need $images[1]. I have checked and it successfully goes around the array elements, and some elements do actually have some of those URLs in that I wish to delete, but they're not getting deleted. This is my $images array:

Array
(
    [0] => Array
        (
            [0] => useless
            [1] => useless
            [2] => useless
            [3] => useless
            [4] => useless
        )

    [1] => Array
        (
            [0] => http://i27.tinypic.com/29yk345.gif
            [1] => http://img3.abload.de/img/10nx2340fhco.gif
            [2] => http://img3.abload.de/img/10nx2340fhco.gif
            [3] => http://i42.tinypic.com/9pp2456x.gif
        )

)

Thanks!

回答1:

foreach($images as $key => $image)
{
    if(in_array($image, array(
       'http://i27.tinypic.com/29ykt1f.gif',
       'http://img3.abload.de/img/10nxjl0fhco.gif',
       'http://i42.tinypic.com/9pp2tx.gif',
    ))
    {
        unset($images[$key]);
    }
}

回答2:

Try that:

foreach ($images as $key => &$image) {
    if (yourConditionGoesHere) {
        unset($images[$key])
    }
}

Normally, foreach operates on a copy of your array so any changes you make, are made to that copy and don't affect the actual array.

So you need to unset the values via $images[$key];

The reference on &$image prevents the loop from creating a copy of the array which would waste memory.

回答3:

To answer the initial question (after your edit), you need to unset($images[1][$key]);

Now some more infos how PHP works: You can safely unset elements of the array in foreach loop, and it doesn't matter if you have & or not for the array item. See this code:

$a=[1,2,3,4,5];
foreach($a as $key=>$val)
{
   if ($key==3) unset($a[$key]);
}
print_r($a);

This prints:

Array
(
    [0] => 1
    [1] => 2
    [2] => 3
    [4] => 5
)

So as you can see, if you unset correct thing within the foreach loop, everything works fine.

回答4:

You can use the index of the array element to remove it from the array, the next time you use the $list variable, you will see that the array is changed.

Try something like this

foreach($list as $itemIndex => &$item) {

   if($item['status'] === false) {
      unset($list[itemIndex]);
   }

}

回答5:

$image is in your case the value of the item and not the key. Use the following syntax to get the key too:

foreach ($images as $key => $value) {
    /* … */
}

Now you can delete the item with unset($images[$key]).

回答6:

You would also need a

$i--;

after each unset to not skip an element/

Because when you unset $item[45], the next element in the for-loop should be $item[45] - which was [46] before unsetting. If you would not do this, you'd always skip an element after unsetting.

回答7:

One solution would be to use the key of your items to remove them -- you can both the keys and the values, when looping using foreach.

For instance :

$arr = array(
    'a' => 123,
    'b' => 456,
    'c' => 789, 
);

foreach ($arr as $key => $item) {
    if ($item == 456) {
        unset($arr[$key]);
    }
}

var_dump($arr);

Will give you this array, in the end :

array
  'a' => int 123
  'c' => int 789

Which means that, in your case, something like this should do the trick :

foreach($images as $key => $image)
{
    if($image == 'http://i27.tinypic.com/29yk345.gif' ||
    $image == 'http://img3.abload.de/img/10nx2340fhco.gif' ||
    $image == 'http://i42.tinypic.com/9pp2456x.gif')
    {
        unset($images[$key]);
    }
}

回答8:

foreach($images as $key=>$image)                                
{               
   if($image == 'http://i27.tinypic.com/29ykt1f.gif' ||    
   $image == 'http://img3.abload.de/img/10nxjl0fhco.gif' ||    
   $image == 'http://i42.tinypic.com/9pp2tx.gif')     
   { unset($images[$key]); }                               
}

!!foreach($images as $key=>$image

cause $image is the value, so $images[$image] make no sense.

回答9:

Sorry for the late response, I recently had the same problem with PHP and found out that when working with arrays that do not use $key => $value structure, when using the foreach loop you actual copy the value of the position on the loop variable, in this case $image. Try using this code and it will fix your problem.

for ($i=0; $i < count($images[1]); $i++)
{

    if($images[1][$i] == 'http://i27.tinypic.com/29yk345.gif' ||

    $images[1][$i] == 'http://img3.abload.de/img/10nx2340fhco.gif' ||

    $images[1][$i] == 'http://i42.tinypic.com/9pp2456x.gif')

    {

        unset($images[1][$i]);

    }

}

var_dump($images);die();