Reading lines in a file and avoiding lines with #

问题:

I tried this:

file="myfile"
while read -r line
do
    [[ $line = \#* ]] && continue
    "address=\$line\127.0.0.1"
done < "$file"

This code doesn't avoid the lines that begin with comments. Even if I don't have any comments, dnsmasq tells that there are errors.

Its going to be a dnsmasq conf file, and it will read and insert domain names like so: address=\mydomain.com\127.0.0.1.

---

EDIT:1

Input file:

domain1.com
domain2.com
domain3.com
#domain4.com
domain5.com

Output should be:

address=/domain1.com/127.0.0.1
address=/domain2.com/127.0.0.1
address=/domain3.com/127.0.0.1
address=/domain5.com/127.0.0.1

I will drop the script in /etc/dnsmasq.d/ directory so that dnsmaq.conf can process it when dnsmasq is started.

回答1:

It's safer to use [[ "$line" = "\#*" ]]

Btw, address="\\${line}\\127.0.0.1"

UPD:

If I've understand you right you need to change every uncommented domains to address=\domain\127.0.0.1. It could be done fast and easy with sed, there is no need in bash-program.

$> cat ./text
domain1.com
domain2.com
domain3.com
#domain4.com
domain5.com

$> sed -r -e 's/(^[^#]*$)/address=\/\1\/127.0.0.1/g' ./text2
address=/domain1.com/127.0.0.1
address=/domain2.com/127.0.0.1
address=/domain3.com/127.0.0.1
#domain4.com
address=/domain5.com/127.0.0.1

If you need to remove commented lines, sed can do it too with /matched_line/d

$> sed -r -e 's/(^[^#]*$)/address=\/\1\/127.0.0.1/g; /^#.*$/d' ./text2 
address=/domain1.com/127.0.0.1
address=/domain2.com/127.0.0.1
address=/domain3.com/127.0.0.1
address=/domain5.com/127.0.0.1

UPD2: if you want to do all that stuff inside the bash script, here is your code modification:

file="./text2"
while read -r line; do
    [[ "$line" =~ ^#.*$ ]] && continue
    echo "address=/${line}/127.0.0.1"
done < "$file"

And it's output:

address=/domain1.com/127.0.0.1
address=/domain2.com/127.0.0.1
address=/domain3.com/127.0.0.1
address=/domain5.com/127.0.0.1

回答2:

To skip lines starting with #:

grep -v '^#' myfile | while read -r file ; do
    ...
done

Modify the grep command as needed to, for example, skip lines starting with whitespace and a # character.

回答3:

Only one working for me was:

while IFS=$'\n' read line
do  
    if [[ "$line" =~ \#.* ]];then
        logDebug "comment line:$line"
    else
        logDebug "normal line:$line"
    fi
done < myFile

回答4:

Comment lines can and often do begin with whitespace. Here's a bash native regex solution that handles any preceeding whitespace;

while read line; do
  [[ "$line" =~ ^[[:space:]]*# ]] && continue
  ...work with valid line...
done

回答5:

You can filter with awk:

awk '!/^#/{print"address=/"$0"/127.0.0.1"}' file

回答6:

[ "${line:0:1}" = "#" ] && continue

This takes the string, gets the substring at offset 0, length 1:

"${line:0:1}"

and checks if it is equal to #

= "#"

and continues looping if so

&& continue

http://www.tldp.org/LDP/abs/html/string-manipulation.html

回答7:

This could also be accomplished with 1 sed command:

file="myfile"

sed -i".backup" 's/^#.*$//' $file

This will modify the file in-place (creating a backup copy first), removing all lines starting with a #.

回答8:

awk '{ if ($0 !~ /^#/){printf "address=/%s/127.0.0.1 \n",$0}}' <your_input_file>

回答9:

It has 3 parts. Please read each to understand clearly

1. To remove # line ----- awk -F'#' '{print $1}' t.txt
2. To remove a blank line created by # ---- awk 'NF > 0'
3. To print in required format. ------awk '{print "address=/"$0"/127.0.0.1"}'

So Total Script Needed is,

**awk -F'#' '{print $1}' t.txt | awk 'NF > 0' | awk '{print "address=/"$0"/127.0.0.1"}'**

Output :

address=/domain1.com/127.0.0.1
address=/domain2.com/127.0.0.1
address=/domain3.com/127.0.0.1
address=/domain5.com/127.0.0.1

回答10:

Maybe you can try

[[ "$line"~="#.*" ]] && continue

Check the ~ in operand!