Access variable outside function scope [duplicate]

问题:

This question already has answers here:

An example of variable shadowing in javascript (5 answers)

Closed 6 years ago.

This is a simplified version of what I am trying to accomplish, but I want to pass a variable outside the scope of the function. I am declaring the variable outside the function but can't get it.

HTML:

<p>5</p>
<p>6</p>
<p>7</p>

JS:

$(document).ready(function () {
    var gsd = "";
    $("p").each(function () {
        if ($(this).text() === "5") {
            var gsd = $(this).text();
            alert(gsd); // this works
        }
    })
    alert("get var outside func" + gsd); //does not work
});

回答1:

You redeclare gsd as a new variable inside your function. Remove var in front of gsd inside the function to address the gsd in the outer scope.