How can I create a series of months to join sparse

问题:

I think this is a pretty common issue, but I don't know what the process is called, so I'll describe it with an example. The concept is that I want to join a sparse dataset to a complete series, such as the days of the week, months of the year, or any ordered set (for example, for ranking). Empty positions in the sparse data will show as NULL alongside the complete series.

Let's say I run the following query in SQL Server to find out monthly sales.

SELECT
    YEAR([timestamp]),
    MONTH([timestamp]),
    COUNT(*)
FROM table1
WHERE YEAR([timestamp]) = YEAR(GETDATE())
GROUP BY
    YEAR([timestamp]),
    MONTH([timestamp])
ORDER BY
    YEAR([timestamp]) DESC,
    MONTH([timestamp]) DESC;

If, however, sales only occurred in May and August of this year, for example, then the return result would look like this:

2010    August    1234
2010    May       5678

I want my return result set to look like this:

2010    January
2010    February
2010    March
2010    April
2010    May        1234
2010    June
2010    July
2010    August     5678
2010    September
2010    October
2010    November
2010    December

The only way I know to do this is this:

SELECT
    YEAR(GETDATE()),
    month_index.month_name,
    sales_data.sales
FROM (
    SELECT 'January' as month_name, 1 as month_number
    UNION
    SELECT 'February', 2
    UNION
    SELECT 'March', 3
    UNION
    SELECT 'April', 4
    UNION
    SELECT 'May', 5
    UNION
    SELECT 'June', 6
    UNION
    SELECT 'July', 7
    UNION
    SELECT 'August', 8
    UNION
    SELECT 'September', 9
    UNION
    SELECT 'October', 10
    UNION
    SELECT 'November', 11
    UNION
    SELECT 'December', 12
) as month_index
LEFT JOIN (
    SELECT
        YEAR([timestamp]) AS year_name,
        MONTH([timestamp]) AS month_name,
        COUNT(*) AS sales
    FROM table1
    WHERE YEAR([timestamp]) = GETDATE()
    GROUP BY
        YEAR([timestamp]),
        MONTH([timestamp])
) AS sales_data
ON month_index.month_name = sales_data.month_name
ORDER BY
    month_index.month_number DESC;

Is there a better way to create complete date and alphanumeric series to join data onto? And what is this called?

Thanks!

回答1:

try something like this:

DECLARE @StartDate datetime
       ,@EndDate datetime
SELECT @StartDate=DATEADD(month,-6,DATEADD(month,DATEDIFF(month,0,GETDATE()),0) )
      ,@EndDate=GETDATE()

;with AllDates AS
(
    SELECT @StartDate AS DateOf
    UNION ALL
    SELECT DateAdd(month,1,DateOf)
        FROM AllDates
    WHERE DateOf<@EndDate
)
SELECT * FROM AllDates

output:

DateOf
-----------------------
2009-12-01 00:00:00.000
2010-01-01 00:00:00.000
2010-02-01 00:00:00.000
2010-03-01 00:00:00.000
2010-04-01 00:00:00.000
2010-05-01 00:00:00.000
2010-06-01 00:00:00.000
2010-07-01 00:00:00.000

(8 row(s) affected)

回答2:

Queries like this are one of the main reasons that many experienced DBAs or database programmers keep a calendar table in their databases.

回答3:

I like this approach to build the months table:

SELECT 
  DATENAME(mm, date_val) AS month_name,  
  MONTH(date_val) AS month_number,  
  date_val as dt
FROM ( 
  SELECT DATEADD(mm, number, '2010-01-01') AS date_val
  FROM master.dbo.spt_values
  WHERE type = 'P'
  AND number BETWEEN 0 AND 11
) months

Based on my tests, it's faster than a CTE. I'm running SQL Server 2008 Express.

Here are the test results, using SET STATISTICS IO ON and SET STATISTICS TIME ON

CTE:

(12 row(s) affected)
Table 'Worktable'. Scan count 2, logical reads 73, physical reads 0, read-ahead reads 0, lob logical reads 0, lob physical reads 0, lob read-ahead reads 0.

(1 row(s) affected)

 SQL Server Execution Times:
   CPU time = 15 ms,  elapsed time = 64 ms.

 SQL Server Execution Times:
   CPU time = 0 ms,  elapsed time = 0 ms.

Subquery:

(12 row(s) affected)
Table 'spt_values'. Scan count 1, logical reads 2, physical reads 2, read-ahead reads 0, lob logical reads 0, lob physical reads 0, lob read-ahead reads 0.

(1 row(s) affected)

 SQL Server Execution Times:
   CPU time = 0 ms,  elapsed time = 4 ms.

 SQL Server Execution Times:
   CPU time = 0 ms,  elapsed time = 0 ms.

Although your original question is asking what this is called. I don't know a name for it; maybe something like "left outer join against a series?"

One additional part to add: when you join against the months table, or even when do your original query, it's typically recommended to avoid using a function like YEAR([timestamp]) on the left side of your WHERE clause.

So this code:

SELECT                     
    YEAR([timestamp]),                     
    MONTH([timestamp]),                     
    COUNT(*)                     
FROM table1                     
WHERE YEAR([timestamp]) = YEAR(GETDATE())                     
GROUP BY                     
    YEAR([timestamp]),                     
    MONTH([timestamp])

...will cause an index scan (assuming timestamp is indexed) because of the YEAR([timestamp]) must be evaluted for every row. On a 1m+ row table, this will mean poor performance.

So you will typically see a recommendation like this instead:

SELECT                     
    YEAR([timestamp]),                     
    MONTH([timestamp]),                     
    COUNT(*)                     
FROM #table1                     
WHERE [timestamp] >= DATEADD(YY, DATEDIFF(YY, 0, GETDATE()), 0) -- First day of this year
AND   [timestamp] < DATEADD(YY, DATEDIFF(YY, 0, GETDATE()) + 1, 0) -- First day of next year
GROUP BY                     
    YEAR([timestamp]),                     
    MONTH([timestamp])

This will use an index seek (again, assuming timestamp is an indexed column) and result in fewer logical reads and thus a faster response. This can be confirmed by checking the execution plan.

回答4:

I'm with KM, that for SQL Server 2005+ you could use a recursive CTE:

WITH months AS (
  SELECT DATENAME(mm, '2010-01-01') AS month_name, 
         MONTH('2010-01-01') AS month_number, 
         CAST('2010-01-01' AS DATETIME) AS dt
  UNION ALL
  SELECT DATENAME(mm, DATEADD(mm, 1, m.dt)),
         MONTH(DATEADD(mm, 1, m.dt)),
         DATEADD(mm, 1, m.dt)
    FROM months m
   WHERE DATEADD(mm, 1, m.dt) <= '2010-12-01')
   SELECT x.month_name,
          y.*
     FROM months x
LEFT JOIN your_table y ON MONTH(y.date) = x.month_number

After all, the last time KM & chatted about this - we found a recursive CTE to be slightly more efficient than using a numbers table.

回答5:

how about making a new table called Months: then populating it with data you can join to?