mysql insert if value not exist in another table

问题:

I have two tables that store value as VARCHAR.
I'm populating table and I want just insert values in one of tables if they are not exist in other table.
Something like:

INSERT IF IS EMPTY(SELECT * FROM t1 where v='test') INTO t2 (v) VALUES ('test')

How Can I do that?

回答1:

You need to use some type of INSERT...SELECT query.

Update (after clarification): For example, here is how to insert a row in t2 if a corresponding row do not already exist in t1:

INSERT INTO t2 (v)
  SELECT temp.candidate
  FROM (SELECT 'test' AS candidate) temp
  LEFT JOIN t1 ON t1.v = temp.candidate
  WHERE t1.v IS NULL

To insert multiple rows with the same query, I 'm afraid there is nothing better than

INSERT INTO t2 (v)
  SELECT temp.candidate
  FROM (
      SELECT 'test1' AS candidate
      UNION SELECT 'test2'
      UNION SELECT 'test3' -- etc
  ) temp
  LEFT JOIN t1 ON t1.v = temp.candidate
  WHERE t1.v IS NULL

Original answer

For example, this will take other_column from all rows from table1 that satisfy the WHERE clause and insert rows into table2 with the values used as column_name. It will ignore duplicate key errors.

INSERT IGNORE INTO table2 (column_name)
  SELECT table1.other_column
  FROM table1 WHERE table1.something == 'filter';

回答2:

for insertion of Multiple columns you can try this.

INSERT INTO table_1 (column_id,column_2,column_3,column_4,column_5)
 SELECT
    table_2.*
FROM
    table_2
LEFT JOIN table_1 ON table_1.column_id = table_2.column_id
WHERE
    table_1.column_id IS NULL;

回答3:

$result = mysql_query("SELECT * FROM t1 WHERE v='test'");
if(mysql_num_rows($result) == 0){
    mysql_query("INSERT INTO t2 (v) VALUES ('test')");
}

Haven't been using mysql for a while so these functions are deprecated, but this is how I should do it.

回答4:

Kinda ghetto.. but works. Assumes that you are inserting a static value into 'col'

INSERT INTO t1 (col)
SELECT 'test' 
  FROM t2
 WHERE (SELECT count(*) FROM t2 WHERE v='test') = 0;