I'm wondering if there is a gcc macro that will tell me the Linux kernel version so I can set variable types appropriately. If not, how would I go about defining my own macro that does this?
问题:
回答1:
The linux/version.h file has a macro called KERNEL_VERSION
which will let you check the version you want against the current linux headers version (LINUX_VERSION_CODE
) installed. For example to check if the current Linux headers are for kernel v2.6.16 or earlier:
#include <linux/version.h>
#if LINUX_VERSION_CODE <= KERNEL_VERSION(2,6,16)
...
#else
...
#endif
A better way to get the version information at run-time is to use the utsname
function in include/linux/utsname.h.
char *my_kernel_version = utsname()->release;
This is essentially how /proc/version
gets the current kernel verison.
See also
Getting kernel version from linux kernel module at runtime
回答2:
gcc
won't know this information. As an alternative, you can determine a lot of kernel information at runtime easily.
You can define your runtime type like
struct unified_foo {
unsigned int kernel_version;
union {
kernel_x_foo_type k_x;
kernel_y_foo_type k_y;
kernel_z_foo_type k_z;
} u;
};
and have code at runtime look at /proc/version
(or whatever you need from the kernel runtime environment) and set kernel_version
approriately. The kernel_x_foo_type
et al. is your type that you want to be conditional on the kernel version. The calling code needs to look at kernel_version
and access the appropriate u.k_x
, u.k_y
, or u.k_z
data.