I am working in Android 2.1, and I want to detect when the headset is plugged in/taken out. I'm pretty new to android.
I think the way to do it is using a Broadcast receiver. I sublcassed this, and I also put the following in my AndroidManifest.xml. But do you have to register the receiver somehwere else, like in the activity? I'm aware there are lots of threads on this, but I don't really understand what they're talking about. Also, what's the difference between registering in AndroidManifest.xml versus registering dynamically in your activity?
<receiver android:enabled="true" android:name="AudioJackReceiver" >
<intent-filter>
<action android:name="android.intent.action.HEADSET_PLUG" >
</action>
</intent-filter>
</receiver>
And this was the implementation of the class (plus imports)
public class AudioJackReceiver extends BroadcastReceiver {
@Override
public void onReceive(Context context, Intent intent) {
Log.w("DEBUG", "headset state received");
}
}
I was just trying to see if it works, but nothing shows up when I unplug/plug in the headset while running the application.
EDIT: the documentation doesn't say this, but is it possible that this one won't work if registered in the manifest? I was able to get it to respond when I registered the receiver in one of my applications (or do you have to do that anyway?)
Here are two sites that may help explain it in more detail:
- http://www.grokkingandroid.com/android-tutorial-broadcastreceiver/
- http://www.vogella.com/articles/AndroidBroadcastReceiver/article.html
You have to define your intent; otherwise it won't access the system function. The broadcast receiver; will alert your application of changes that you'd like to listen for.
Every receiver needs to be subclassed; it must include a onReceive()
. To implement the onReceive()
you'll need to create a method that will include two items: Context & Intent.
More then likely a service would be ideal; but you'll create a service and define your context through it. In the context; you'll define your intent.
An example:
context.startService
(new Intent(context, YourService.class));
Very basic example. However; your particular goal is to utilize a system-wide broadcast. You want your application to be notified of Intent.ACTION_HEADSET_PLUG
.
How to subscribe through manifest:
<receiver
android:name="AudioJackReceiver"
android:enabled="true"
android:exported="true" >
<intent-filter>
<action android:name="android.intent.action.HEADSET_PLUG" />
</intent-filter>
</receiver>
Or you can simply define through your application; but. Your particular request; will require user permissions if you intend to detect Bluetooth MODIFY_AUDIO_SETTINGS
.
Just complementing Greg`s answer, here is the code that you need divided in two parts
Register the Service in the first Activity (here its called MainActivity.java
).
Switch over the result of the ACTION_HEADSET_PLUG
action in the BroadCastReceiver
.
Here it goes:
public class MainActivity extends Activity {
private static final String TAG = "MainActivity";
private MusicIntentReceiver myReceiver;
@Override protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
myReceiver = new MusicIntentReceiver();
}
@Override public void onResume() {
IntentFilter filter = new IntentFilter(Intent.ACTION_HEADSET_PLUG);
registerReceiver(myReceiver, filter);
super.onResume();
}
private class MusicIntentReceiver extends BroadcastReceiver {
@Override public void onReceive(Context context, Intent intent) {
if (intent.getAction().equals(Intent.ACTION_HEADSET_PLUG)) {
int state = intent.getIntExtra("state", -1);
switch (state) {
case 0:
Log.d(TAG, "Headset is unplugged");
break;
case 1:
Log.d(TAG, "Headset is plugged");
break;
default:
Log.d(TAG, "I have no idea what the headset state is");
}
}
}
}
You need to enable the broadcast receiver and set the exported
attribute to true
:
<receiver
android:name="AudioJackReceiver"
android:enabled="true"
android:exported="true" >
<intent-filter>
<action android:name="android.intent.action.HEADSET_PLUG" />
</intent-filter>
</receiver>