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问题:
So I have to create code that validate whether a password:
- Is at least 8 characters long
- Contains at least 1 number
- Contains at least 1 capital letter
Here is the code:
def validate():
while True:
password = input("Enter a password: ")
if len(password) < 8:
print("Make sure your password is at lest 8 letters")
elif not password.isdigit():
print("Make sure your password has a number in it")
elif not password.isupper():
print("Make sure your password has a capital letter in it")
else:
print("Your password seems fine")
break
validate()
I'm not sure what is wrong, but when I enter a password that has a number - it keeps telling me that I need a password with a number in it. Any solutions?
回答1:
You can use re module for regular expressions.
With it your code would look like this:
import re
def validate():
while True:
password = raw_input("Enter a password: ")
if len(password) < 8:
print("Make sure your password is at lest 8 letters")
elif re.search('[0-9]',password) is None:
print("Make sure your password has a number in it")
elif re.search('[A-Z]',password) is None:
print("Make sure your password has a capital letter in it")
else:
print("Your password seems fine")
break
validate()
回答2:
password.isdigit() does not check if the password contains a digit, it checks all the characters according to:
str.isdigit(): Return true if all characters in the string are digits
and there is at least one character, false otherwise.
password.isupper() does not check if the password has a capital in it, it checks all the characters according to:
str.isupper(): Return true if all cased characters in the string are
uppercase and there is at least one cased character, false otherwise.
For a solution, please check the question and accepted answer at check if a string contains a number.
You can build your own hasNumbers()-function (Copied from linked question):
def hasNumbers(inputString):
return any(char.isdigit() for char in inputString)
and a hasUpper()-function:
def hasUpper(inputString):
return any(char.isupper() for char in inputString)
回答3:
r_p = re.compile('^(?=\S{6,20}$)(?=.*?\d)(?=.*?[a-z])(?=.*?[A-Z])(?=.*?[^A-Za-z\s0-9])')
this code will validate your password with :
- min length is 6 and max length is 20
- at least include a digit number,
- at least a upcase and a lowcase letter
- at least a special characters
回答4:
You are checking isdigit and isupper methods on the entire password string object not on each character of the string. The following is a function which checks if the password meets your specific requirements. It does not use any regex stuff. It also prints all the defects of the entered password.
#!/usr/bin/python3
def passwd_check(passwd):
"""Check if the password is valid.
This function checks the following conditions
if its length is greater than 6 and less than 8
if it has at least one uppercase letter
if it has at least one lowercase letter
if it has at least one numeral
if it has any of the required special symbols
"""
SpecialSym=['$','@','#']
return_val=True
if len(passwd) < 6:
print('the length of password should be at least 6 char long')
return_val=False
if len(passwd) > 8:
print('the length of password should be not be greater than 8')
return_val=False
if not any(char.isdigit() for char in passwd):
print('the password should have at least one numeral')
return_val=False
if not any(char.isupper() for char in passwd):
print('the password should have at least one uppercase letter')
return_val=False
if not any(char.islower() for char in passwd):
print('the password should have at least one lowercase letter')
return_val=False
if not any(char in SpecialSym for char in passwd):
print('the password should have at least one of the symbols $@#')
return_val=False
if return_val:
print('Ok')
return return_val
print(passwd_check.__doc__)
passwd = input('enter the password : ')
print(passwd_check(passwd))
回答5:
isdigit() checks the whole string is a digit, not if the string contains a digit
Return true if all characters in the string are digits and there is at least one character, false otherwise.
isupper() checks the whole string is in uppercase, not if the string contains at least one uppercase character.
Return true if all cased characters in the string are uppercase and there is at least one cased character, false otherwise.
What you need is using the any built-in function:
any([x.isdigit() for x in password]) will return True if at least one digit is present in passwordany([x.isupper() for x in password]) will return True if at least one character is considered as uppercase.
回答6:
Maybe you can use regex expression:
re.search(r"[A-Z]", password)
Check uppercase letters.
re.search(r"[0-9]", password)
Check digits in password.
回答7:
Python 2.7
The for loop will assign a condition number for each character. i.e. Pa$$w0rd in a list would = 1,2,4,4,2,3,2,2,5. Since sets only contains unique values, the set would = 1,2,3,4,5; therefore since all conditions are met the len of the set would = 5. if it was pa$$w the set would = 2,4 and len would = 2 therefore invalid
name = raw_input("Enter a Password: ")
list_pass=set()
special_char=['#','$','@']
for i in name:
if(i.isupper()):
list_pass.add('1')
elif (i.islower()):
list_pass.add('2')
elif(i.isdigit()) :
list_pass.add('3')
elif(i in special_char):
list_pass.add('4')
if len(name) >=6 and len(name) <=12:
list_pass.add('5')
if len(list_pass) is 5:
print ("Password valid")
else: print("Password invalid")
回答8:
''' Minimum length is 5;
- Maximum length is 10;
- Should contain at least one number;
- Should contain at least one special character (such as &, +, @, $, #, %, etc.);
- Should not contain spaces.
'''
import string
def checkPassword(inputStr):
if not len(inputStr):
print("Empty string was entered!")
exit(0)
else:
print("Input:","\"",inputStr,"\"")
if len(inputStr) < 5 or len(inputStr) > 10:
return False
countLetters = 0
countDigits = 0
countSpec = 0
countWS = 0
for i in inputStr:
if i in string.ascii_uppercase or i in string.ascii_lowercase:
countLetters += 1
if i in string.digits:
countDigits += 1
if i in string.punctuation:
countSpec += 1
if i in string.whitespace:
countWS += 1
if not countLetters:
return False
elif not countDigits:
return False
elif not countSpec:
return False
elif countWS:
return False
else:
return True
print("Output: ",checkPassword(input()))
With Regex
s = input("INPUT: ")
print("{}\n{}".format(s, 5 <= len(s) <= 10 and any(l in "0123456789" for l in s) and any(l in "!\"#$%&'()*+,-./:;<=>?@[\]^_`{|}~" for l in s) and not " " in s))
Module import
from string import digits, punctuation
def validate_password(p):
if not 5 <= len(p) <= 10:
return False
if not any(c in digits for c in p):
return False
if not any(c in punctuation for c in p):
return False
if ' ' in p:
return False
return True
for p in ('DJjkdklkl', 'John Doe'
, '$kldfjfd9'):
print(p, ': ', ('invalid', 'valid')[validate_password(p)], sep='')
回答9:
Example:
class Password:
def __init__(self, password):
self.password = password
def validate(self):
vals = {
'Password must contain an uppercase letter.': lambda s: any(x.isupper() for x in s),
'Password must contain a lowercase letter.': lambda s: any(x.islower() for x in s),
'Password must contain a digit.': lambda s: any(x.isdigit() for x in s),
'Password must be at least 8 characters.': lambda s: len(s) >= 8,
'Password cannot contain white spaces.': lambda s: not any(x.isspace() for x in s)
}
valid = True
for n, val in vals.items():
if not val(self.password):
valid = False
return n
return valid
def compare(self, password2):
if self.password == password2:
return True
if __name__ == '__main__':
input_password = input('Insert Password: ')
input_password2 = input('Repeat Password: ')
p = Password(input_password)
if p.validate() is True:
if p.compare(input_password2) is True:
print('OK')
else:
print(p.validate())
回答10:
Or you can use this to check if it got at least one digit:
min(passwd).isdigit()
