PHPUnit Mock Objects and Static Methods

问题:

I am looking for the best way to go about testing the following static method (specifically using a Doctrine Model):

class Model_User extends Doctrine_Record
{
    public static function create($userData)
    {
        $newUser = new self();
        $newUser->fromArray($userData);
        $newUser->save();
    }
}

Ideally, I would use a mock object to ensure that "fromArray" (with the supplied user data) and "save" were called, but that's not possible as the method is static.

Any suggestions?

回答1:

Sebastian Bergmann, the author of PHPUnit, recently had a blog post about Stubbing and Mocking Static Methods. With PHPUnit 3.5 and PHP 5.3 as well as consistent use of late static binding, you can do

$class::staticExpects($this->any())
      ->method('helper')
      ->will($this->returnValue('bar'));

Update: staticExpects is deprecated as of PHPUnit 3.8 and will be removed completely with later versions.

回答2:

There is now the AspectMock library to help with this:

https://github.com/Codeception/AspectMock

$this->assertEquals('users', UserModel::tableName());   
$userModel = test::double('UserModel', ['tableName' => 'my_users']);
$this->assertEquals('my_users', UserModel::tableName());
$userModel->verifyInvoked('tableName'); 

回答3:

I would make a new class in the unit test namespace that extends the Model_User and test that. Here's an example:

Original class:

class Model_User extends Doctrine_Record
{
    public static function create($userData)
    {
        $newUser = new self();
        $newUser->fromArray($userData);
        $newUser->save();
    }
}

Mock Class to call in unit test(s):

use \Model_User
class Mock_Model_User extends Model_User
{
    /** \PHPUnit\Framework\TestCase */
    public static $test;

    // This class inherits all the original classes functions.
    // However, you can override the methods and use the $test property
    // to perform some assertions.
}

In your unit test:

use Module_User;
use PHPUnit\Framework\TestCase;

class Model_UserTest extends TestCase
{
    function testCanInitialize()
    {   
        $userDataFixture = []; // Made an assumption user data would be an array.
        $sut = new Mock_Model_User::create($userDataFixture); // calls the parent ::create method, so the real thing.

        $sut::test = $this; // This is just here to show possibilities.

        $this->assertInstanceOf(Model_User::class, $sut);
    }
}

回答4:

Testing static methods is generally considered as a bit hard (as you probably already noticed), especially before PHP 5.3.

Could you not modify your code to not use static a method ? I don't really see why you're using a static method here, in fact ; this could probably be re-written to some non-static code, could it not ?

For instance, could something like this not do the trick :

class Model_User extends Doctrine_Record
{
    public function saveFromArray($userData)
    {
        $this->fromArray($userData);
        $this->save();
    }
}

Not sure what you'll be testing ; but, at least, no static method anymore...

回答5:

Another possible approach is with the Moka library:

$modelClass = Moka::mockClass('Model_User', [ 
    'fromArray' => null, 
    'save' => null
]);

$modelClass::create('DATA');
$this->assertEquals(['DATA'], $modelClass::$moka->report('fromArray')[0]);
$this->assertEquals(1, sizeof($modelClass::$moka->report('save')));

回答6:

The doublit library could also help you to test static methods :

/* Create a mock instance of your class */
$double = Doublit::mock_instance(Model_User::class);

/* Test the "create" method */
$double::_method('create')
   ->count(1) // test that the method is called once
   ->args([Constraints::isInstanceOf('array')]) // test that first argument is an array
   ->stub('my_value') // stub the method to return "myvalue"