I need to remove spaces from the end of a string. How can I do that?
Example: if string is "Hello "
it must become "Hello"
问题:
回答1:
Taken from this answer here: https://stackoverflow.com/a/5691567/251012
- (NSString *)stringByTrimmingTrailingCharactersInSet:(NSCharacterSet *)characterSet {
NSRange rangeOfLastWantedCharacter = [self rangeOfCharacterFromSet:[characterSet invertedSet]
options:NSBackwardsSearch];
if (rangeOfLastWantedCharacter.location == NSNotFound) {
return @"";
}
return [self substringToIndex:rangeOfLastWantedCharacter.location+1]; // non-inclusive
}
回答2:
Another solution involves creating mutable string:
//make mutable string
NSMutableString *stringToTrim = [@" i needz trim " mutableCopy];
//pass it by reference to CFStringTrimSpace
CFStringTrimWhiteSpace((__bridge CFMutableStringRef) stringToTrim);
//stringToTrim is now "i needz trim"
回答3:
Here you go...
- (NSString *)removeEndSpaceFrom:(NSString *)strtoremove{
NSUInteger location = 0;
unichar charBuffer[[strtoremove length]];
[strtoremove getCharacters:charBuffer];
int i = 0;
for(i = [strtoremove length]; i >0; i--) {
NSCharacterSet* charSet = [NSCharacterSet whitespaceCharacterSet];
if(![charSet characterIsMember:charBuffer[i - 1]]) {
break;
}
}
return [strtoremove substringWithRange:NSMakeRange(location, i - location)];
}
So now just call it. Supposing you have a string that has spaces on the front and spaces on the end and you just want to remove the spaces on the end, you can call it like this:
NSString *oneTwoThree = @" TestString ";
NSString *resultString;
resultString = [self removeEndSpaceFrom:oneTwoThree];
resultString
will then have no spaces at the end.
回答4:
To remove whitespace from only the beginning and end of a string in Swift:
Swift 3
string.trimmingCharacters(in: .whitespacesAndNewlines)
Previous Swift Versions
string.stringByTrimmingCharactersInSet(.whitespaceAndNewlineCharacterSet()))
回答5:
NSString *trimmedString = [string stringByTrimmingCharactersInSet:
[NSCharacterSet whitespaceAndNewlineCharacterSet]];
//for remove whitespace and new line character
NSString *trimmedString = [string stringByTrimmingCharactersInSet:
[NSCharacterSet punctuationCharacterSet]];
//for remove characters in punctuation category
There are many other CharacterSets. Check it yourself as per your requirement.
回答6:
Swift version
Only trims spaces at the end of the String:
private func removingSpacesAtTheEndOfAString(var str: String) -> String {
var i: Int = countElements(str) - 1, j: Int = i
while(i >= 0 && str[advance(str.startIndex, i)] == " ") {
--i
}
return str.substringWithRange(Range<String.Index>(start: str.startIndex, end: advance(str.endIndex, -(j - i))))
}
Trims spaces on both sides of the String:
var str: String = " Yolo "
var trimmedStr: String = str.stringByTrimmingCharactersInSet(NSCharacterSet.whitespaceCharacterSet())
回答7:
This will remove only the trailing characters of your choice.
func trimRight(theString: String, charSet: NSCharacterSet) -> String {
var newString = theString
while String(newString.characters.last).rangeOfCharacterFromSet(charSet) != nil {
newString = String(newString.characters.dropLast())
}
return newString
}
回答8:
In Swift
To trim space & newline from both side of the String:
var url: String = "\n http://example.com/xyz.mp4 "
var trimmedUrl: String = url.stringByTrimmingCharactersInSet(NSCharacterSet.whitespaceAndNewlineCharacterSet())
回答9:
To trim all trailing whitespace characters (I'm guessing that is actually your intent), the following is a pretty clean & concise way to do it:
NSString *trimmedString = [string stringByReplacingOccurrencesOfString:@"\\s+$" withString:@"" options:NSRegularExpressionSearch range:NSMakeRange(0, string.length)];
One line, with a dash of regex.
回答10:
A simple solution to only trim one end instead of both ends in Objective-C:
@implementation NSString (category)
/// trims the characters at the end
- (NSString *)stringByTrimmingSuffixCharactersInSet:(NSCharacterSet *)characterSet {
NSUInteger i = self.length;
while (i > 0 && [characterSet characterIsMember:[self characterAtIndex:i - 1]]) {
i--;
}
return [self substringToIndex:i];
}
@end
And a symmetrical utility for trimming the beginning only:
@implementation NSString (category)
/// trims the characters at the beginning
- (NSString *)stringByTrimmingPrefixCharactersInSet:(NSCharacterSet *)characterSet {
NSUInteger i = 0;
while (i < self.length && [characterSet characterIsMember:[self characterAtIndex:i]]) {
i++;
}
return [self substringFromIndex:i];
}
@end
回答11:
The solution is described here: How to remove whitespace from right end of NSString?
Add the following categories to NSString:
- (NSString *)stringByTrimmingTrailingCharactersInSet:(NSCharacterSet *)characterSet {
NSRange rangeOfLastWantedCharacter = [self rangeOfCharacterFromSet:[characterSet invertedSet]
options:NSBackwardsSearch];
if (rangeOfLastWantedCharacter.location == NSNotFound) {
return @"";
}
return [self substringToIndex:rangeOfLastWantedCharacter.location+1]; // non-inclusive
}
- (NSString *)stringByTrimmingTrailingWhitespaceAndNewlineCharacters {
return [self stringByTrimmingTrailingCharactersInSet:
[NSCharacterSet whitespaceAndNewlineCharacterSet]];
}
And you use it as such:
[yourNSString stringByTrimmingTrailingWhitespaceAndNewlineCharacters]
回答12:
I came up with this function, which basically behaves similarly to one in the answer by Alex:
-(NSString*)trimLastSpace:(NSString*)str{
int i = str.length - 1;
for (; i >= 0 && [str characterAtIndex:i] == ' '; i--);
return [str substringToIndex:i + 1];
}
whitespaceCharacterSet
besides space itself includes also tab character, which in my case could not appear. So i guess a plain comparison could suffice.
回答13:
let string = " Test Trimmed String "
For Removing white Space and New line use below code :-
let str_trimmed = yourString.trimmingCharacters(in: .whitespacesAndNewlines)
For Removing only Spaces from string use below code :-
let str_trimmed = yourString.trimmingCharacters(in: .whitespaces)
回答14:
NSString* NSStringWithoutSpace(NSString* string)
{
return [string stringByReplacingOccurrencesOfString:@" " withString:@""];
}