How do I select between the 1st day of the current

问题:

I need to select data from MySQL database between the 1st day of the current month and current day.

select*from table_name 
where date between "1st day of current month" and "current day"

Can someone provide working example of this query?

回答1:

select * from table_name 
where (date between  DATE_ADD(LAST_DAY(DATE_SUB(CURDATE(), interval 30 day), interval 1 day) AND CURDATE() )

Or better :

select * from table_name 
where (date between  DATE_FORMAT(NOW() ,'%Y-%m-01') AND NOW() )

回答2:

I was looking for a similar query where I needed to use the first day of a month in my query. The last_day function didn't work for me but DAYOFMONTH came in handy.

So if anyone is looking for the same issue, the following code returns the date for first day of the current month.

SELECT DATE_SUB(CURRENT_DATE, INTERVAL DAYOFMONTH(CURRENT_DATE)-1 DAY);

Comparing a date column with the first day of the month :

select * from table_name where date between 
DATE_SUB(CURRENT_DATE, INTERVAL DAYOFMONTH(CURRENT_DATE)-1 DAY) and CURRENT_DATE

回答3:

select * from table_name 
where `date` between curdate() - dayofmonth(curdate()) + 1
                 and curdate()

SQLFiddle example

回答4:

I have used the following query. It has worked great for me in the past.

select date(now()) - interval day(now()) day + interval 1 day

回答5:

try this :

SET @StartDate = DATE_SUB(DATE(NOW()),INTERVAL (DAY(NOW())-1) DAY);
SET @EndDate = ADDDATE(CURDATE(),1);
select * from table where (date >= @StartDate and date < @EndDate);

回答6:

Complete solution for mysql current month and current year, which makes use of indexing properly as well :)

-- Current month
SELECT id, timestampfield 
  FROM table1
 WHERE timestampfield >= DATE_SUB(CURRENT_DATE, INTERVAL DAYOFMONTH(CURRENT_DATE)-1 DAY)
   AND timestampfield <=  LAST_DAY(CURRENT_DATE);

-- Current year
SELECT id, timestampfield 
  FROM table1
 WHERE timestampfield >= DATE_SUB(CURRENT_DATE, INTERVAL DAYOFYEAR(CURRENT_DATE)-1 DAY)
   AND timestampfield <=  LAST_DAY(CURRENT_DATE);

回答7:

select * from table
where date between 
(date_add (CURRENT_DATE, INTERVAL(1 - DAYOFMonth(CURRENT_DATE)) day)) and current_date;

回答8:

select * from <table>
where <dateValue> between last_day(curdate() - interval 1 month + interval 1 day)
                  and curdate();

回答9:

A less orthodox approach might be

SELECT * FROM table_name 
WHERE LEFT(table_name.date, 7) = LEFT(CURDATE(), 7)
  AND table_name.date <= CURDATE();

as a date being between the first of a month and now is equivalent to a date being in this month, and before now. I do feel that this is a bit easier on the eyes than some other approaches, though.

回答10:

SELECT date_sub(current_date(),interval dayofmonth(current_date())-1 day) as first_day_of_month;

回答11:

I had some what similar requirement - to find first day of the month but based on year end month selected by user in their profile page.

Problem statement - find all the txns done by the user in his/her financial year. Financial year is determined using year end month value where month can be any valid month - 1 for Jan, 2 for Feb, 3 for Mar,....12 for Dec.

For some clients financial year ends on March and some observe it on December.

Scenarios - (Today is `08 Aug, 2018`)
   1. If `financial year` ends on `July` then query should return `01 Aug 2018`.
   2. If `financial year` ends on `December` then query should return `01 January 2018`.
   3. If `financial year` ends on `March` then query should return `01 April 2018`.
   4. If `financial year` ends on `September` then query should return `01 October 2017`.

And, finally below is the query. -

select @date := (case when ? >= month(now()) 
then date_format((subdate(subdate(now(), interval (12 - ? + month(now()) - 1) month), interval day(now()) - 2 day)) ,'%Y-%m-01')
else date_format((subdate(now(), interval month(now()) - ? - 1 month)), '%Y-%m-01') end)

where ? is year end month (values from 1 to 12).

回答12:

I found myself here after needing this same query for some Business Intelligence Queries I'm running on an e-commerce store. I wanted to add my solution as it may be helpful to others.

set @firstOfLastLastMonth = DATE_SUB(LAST_DAY(DATE_ADD(NOW(), INTERVAL -2 MONTH)),INTERVAL DAY(LAST_DAY(DATE_ADD(NOW(), INTERVAL -2 MONTH)))-1 DAY);
set @lastOfLastLastMonth = LAST_DAY(DATE_ADD(NOW(), INTERVAL -2 MONTH));
set @firstOfLastMonth = DATE_SUB(LAST_DAY(DATE_ADD(NOW(), INTERVAL -1 MONTH)),INTERVAL DAY(LAST_DAY(DATE_ADD(NOW(), INTERVAL -1 MONTH)))-1 DAY);
set @lastOfLastMonth = LAST_DAY(DATE_ADD(NOW(), INTERVAL -1 MONTH));
set @firstOfMonth = DATE_ADD(@lastOfLastMonth, INTERVAL 1 DAY);
set @today = CURRENT_DATE;

Today is 2019-10-08 so the output looks like

@firstOfLastLastMonth = '2019-08-01'
@lastOfLastLastMonth = '2019-08-31'
@firstOfLastMonth = '2019-09-01'
@lastOfLastMonth = '2019-09-30'
@firstOfMonth = '2019-10-01'
@today = '2019-10-08'

回答13:

The key here is to get the first day of the month. For that, there are several options. In terms of performance, our tests show that there isn't a significant difference between them - we wrote a whole blog article on the topic. Our findings show that what really matters is whether you need the result to be VARCHAR, DATETIME, or DATE.

The fastest solution to the real problem of getting the first day of the month returns VARCHAR:

SELECT CONCAT(LEFT(CURRENT_DATE, 7), '-01') AS first_day_of_month;

The second fastest solution gives a DATETIME result - this runs about 3x slower than the previous:

SELECT TIMESTAMP(CONCAT(LEFT(CURRENT_DATE, 7), '-01')) AS first_day_of_month;

The slowest solutions return DATE objects. Don't believe me? Run this SQL Fiddle and see for yourself