Remove useless zero digits from decimals in PHP

2020-01-24 04:03发布

问题:

I'm trying to find a fast way to remove zero decimals from number values like this:

echo cleanNumber('125.00');
// 125

echo cleanNumber('966.70');
// 966.7

echo cleanNumber(844.011);
// 844.011

Does exists some optimized way to do that?

回答1:

$num + 0 does the trick.

echo 125.00 + 0; // 125
echo '125.00' + 0; // 125
echo 966.70 + 0; // 966.7

Internally, this is equivalent to casting to float with (float)$num or floatval($num) but I find it simpler.



回答2:

you could just use the floatval function

echo floatval('125.00');
// 125

echo floatval('966.70');
// 966.7

echo floatval('844.011');
// 844.011


回答3:

This is what I use:

function TrimTrailingZeroes($nbr) {
    return strpos($nbr,'.')!==false ? rtrim(rtrim($nbr,'0'),'.') : $nbr;
}

N.B. This assumes . is the decimal separator. It has the advantage that it will work on arbitrarily large (or small) numbers since there is no float cast. It also won't turn numbers into scientific notation (e.g. 1.0E-17).



回答4:

Simply adding + to your string variable will cause typecast to (float) and removes zeros:

var_dump(+'125.00');     // double(125)
var_dump(+'966.70');     // double(966.7)
var_dump(+'844.011');    // double(844.011)
var_dump(+'844.011asdf');// double(844.011)


回答5:

For everyone coming to this site having the same problem with commata instead, change:

$num = number_format($value, 1, ',', '');

to:

$num = str_replace(',0', '', number_format($value, 1, ',', '')); // e.g. 100,0 becomes 100


If there are two zeros to be removed, then change to:

$num = str_replace(',00', '', number_format($value, 2, ',', '')); // e.g. 100,00 becomes 100

More here: PHP number: decimal point visible only if needed



回答6:

You should cast your numbers as floats, which will do this for you.

$string = "42.422005000000000000000000000000";
echo (float)$string;

Output of this will be what you are looking for.

42.422005



回答7:

If you want to remove the zero digits just before to display on the page or template.

You can use the sprintf() function

sprintf('%g','125.00');
//125

‌‌sprintf('%g','966.70');
//966.7

‌‌‌‌sprintf('%g',844.011);
//844.011


回答8:

$x = '100.10'; 
$x = preg_replace("/\.?0*$/",'',$x); 
echo $x;

There is nothing that can't be fixed with a simple regex ;)

http://xkcd.com/208/



回答9:

Typecast to a float.

$int = 4.324000;
$int = (float) $int;


回答10:

Due to this question is old. First, I'm sorry about this.

The question is about number xxx.xx but in case that it is x,xxx.xxxxx or difference decimal separator such as xxxx,xxxx this can be harder to find and remove zero digits from decimal value.

/**
 * Remove zero digits from decimal value.
 * 
 * @param string|int|float $number The number can be any format, any where use in the world such as 123, 1,234.56, 1234.56789, 12.345,67, -98,765.43
 * @param string The decimal separator. You have to set this parameter to exactly what it is. For example: in Europe it is mostly use "," instead of ".".
 * @return string Return removed zero digits from decimal value.
 */
function removeZeroDigitsFromDecimal($number, $decimal_sep = '.')
{
    $explode_num = explode($decimal_sep, $number);
    if (is_array($explode_num) && isset($explode_num[count($explode_num)-1]) && intval($explode_num[count($explode_num)-1]) === 0) {
        unset($explode_num[count($explode_num)-1]);
        $number = implode($decimal_sep, $explode_num);
    }
    unset($explode_num);
    return (string) $number;
}

And here is the code for test.

$numbers = [
    1234,// 1234
    -1234,// -1234
    '12,345.67890',// 12,345.67890
    '-12,345,678.901234',// -12,345,678.901234
    '12345.000000',// 12345
    '-12345.000000',// -12345
    '12,345.000000',// 12,345
    '-12,345.000000000',// -12,345
];
foreach ($numbers as $number) {
    var_dump(removeZeroDigitsFromDecimal($number));
}


echo '<hr>'."\n\n\n";


$numbers = [
    1234,// 12324
    -1234,// -1234
    '12.345,67890',// 12.345,67890
    '-12.345.678,901234',// -12.345.678,901234
    '12345,000000',// 12345
    '-12345,000000',// -12345
    '12.345,000000',// 12.345
    '-12.345,000000000',// -12.345
    '-12.345,000000,000',// -12.345,000000 STRANGE!! but also work.
];
foreach ($numbers as $number) {
    var_dump(removeZeroDigitsFromDecimal($number, ','));
}


回答11:

Strange, when I get a number out of database with a "float" type and if my number is ex. 10000 when I floatval it, it becomes 1.

$number = $ad['price_month']; // 1000 from the database with a float type
echo floatval($number);
Result : 1

I've tested all the solutions above but didn't work.



回答12:

$value = preg_replace('~\.0+$~','',$value);


回答13:

$str = 15.00;
$str2 = 14.70;
echo rtrim(rtrim(strval($str), "0"), "."); //15
echo rtrim(rtrim(strval($str2), "0"), "."); //14.7


回答14:

Be careful with adding +0.

echo number_format(1500.00, 2,".",",")+0;
//1

Result of this is 1.

echo floatval('1,000.00');
// 1

echo floatval('1000.00');
//1000


回答15:

Complicated way but works:

$num = '125.0100';
$index = $num[strlen($num)-1];
$i = strlen($num)-1;
while($index == '0') {
   if ($num[$i] == '0') {
     $num[$i] = '';
     $i--;
   }

   $index = $num[$i];
}

//remove dot if no numbers exist after dot
$explode = explode('.', $num);
if (isset($explode[1]) && intval($explode[1]) <= 0) {
   $num = intval($explode[0]);
}

echo $num; //125.01

the solutions above are the optimal way but in case you want to have your own you could use this. What this algorithm does it starts at the end of string and checks if its 0, if it is it sets to empty string and then goes to the next character from back untill the last character is > 0



回答16:

You can use:

print (floatval)(number_format( $Value), 2 ) );    


回答17:

Thats my small solution... Can included to a class and set vars

private $dsepparator = '.'; // decimals private $tsepparator= ','; // thousand

That can be set by constructor and change to users lang.

class foo
{
    private $dsepparator;
    private $tsepparator;

    function __construct(){
        $langDatas = ['en' => ['dsepparator' => '.', 'tsepparator' => ','], 'de' => ['dsepparator' => ',', 'tsepparator' => '.']];
        $usersLang = 'de'; // set iso code of lang from user
        $this->dsepparator = $langDatas[$usersLang]['dsepparator'];
        $this->tsepparator = $langDatas[$usersLang]['tsepparator'];
    }

    public function numberOmat($amount, $decimals = 2, $hideByZero = false)
    {
        return ( $hideByZero === true AND ($amount-floor($amount)) <= 0 ) ? number_format($amount, 0, $this->dsepparator, $this->tsepparator) : number_format($amount, $decimals, $this->dsepparator, $this->tsepparator);
    }
    /*
     * $bar = new foo();
     * $bar->numberOmat('5.1234', 2, true); // returns: 5,12
     * $bar->numberOmat('5', 2); // returns: 5,00
     * $bar->numberOmat('5.00', 2, true); // returns: 5
     */

}


回答18:

This is my solution. I want to keep ability to add thousands separator

    $precision = 5;    
    $number = round($number, $precision);
    $decimals = strlen(substr(strrchr($number, '.'), 1));
    return number_format($number, $precision, '.', ',');


回答19:

This is a simple one line function using rtrim, save separator and decimal point :

function myFormat($num,$dec)
 {
 return rtrim(rtrim(number_format($num,$dec),'0'),'.');
 }


回答20:

I found this solution is the best:

public function priceFormat(float $price): string
{
    //https://stackoverflow.com/a/14531760/5884988
    $price = $price + 0;
    $split = explode('.', $price);
    return number_format($price, isset($split[1]) ? strlen($split[1]) : 2, ',', '.');
}


回答21:

Simple and accurate!

function cleanNumber($num){
    $explode = explode('.', $num);
    $count   = strlen(rtrim($explode[1],'0'));
    return bcmul("$num",'1', $count);
}


回答22:

Ultimate Solution: The only safe way is to use regex:

echo preg_replace("/\.?0+$/", "", 3.0); // 3
echo preg_replace("/\d+\.?\d*(\.?0+)/", "", 3.0); // 3

it will work for any case



回答23:

This Code will remove zero after point and will return only two decimal digits.

$number=1200.0000;
str_replace('.00', '',number_format($number, 2, '.', ''));

Output will be: 1200