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问题:
I have a file which contains several thousand numbers, each on it's own line:
34
42
11
6
2
99
...
I'm looking to write a script which will print the sum of all numbers in the file. I've got a solution, but it's not very efficient. (It takes several minutes to run.) I'm looking for a more efficient solution. Any suggestions?
回答1:
For a Perl one-liner, it's basically the same thing as the awk
solution in Ayman Hourieh's answer:
% perl -nle '$sum += $_ } END { print $sum'
If you're curious what Perl one-liners do, you can deparse them:
% perl -MO=Deparse -nle '$sum += $_ } END { print $sum'
The result is a more verbose version of the program, in a form that no one would ever write on their own:
BEGIN { $/ = "\n"; $\ = "\n"; }
LINE: while (defined($_ = <ARGV>)) {
chomp $_;
$sum += $_;
}
sub END {
print $sum;
}
-e syntax OK
Just for giggles, I tried this with a file containing 1,000,000 numbers (in the range 0 - 9,999). On my Mac Pro, it returns virtually instantaneously. That's too bad, because I was hoping using mmap
would be really fast, but it's just the same time:
use 5.010;
use File::Map qw(map_file);
map_file my $map, $ARGV[0];
$sum += $1 while $map =~ m/(\d+)/g;
say $sum;
回答2:
You can use awk:
awk '{ sum += $1 } END { print sum }' file
回答3:
None of the solution thus far use paste
. Here's one:
paste -sd+ filename | bc
As an example, calculate Σn where 1<=n<=100000:
$ seq 100000 | paste -sd+ | bc -l
5000050000
(For the curious, seq n
would print a sequence of numbers from 1
to n
given a positive number n
.)
回答4:
Just for fun, let's benchmark it:
$ for ((i=0; i<1000000; i++)) ; do echo $RANDOM; done > random_numbers
$ time perl -nle '$sum += $_ } END { print $sum' random_numbers
16379866392
real 0m0.226s
user 0m0.219s
sys 0m0.002s
$ time awk '{ sum += $1 } END { print sum }' random_numbers
16379866392
real 0m0.311s
user 0m0.304s
sys 0m0.005s
$ time { { tr "\n" + < random_numbers ; echo 0; } | bc; }
16379866392
real 0m0.445s
user 0m0.438s
sys 0m0.024s
$ time { s=0;while read l; do s=$((s+$l));done<random_numbers;echo $s; }
16379866392
real 0m9.309s
user 0m8.404s
sys 0m0.887s
$ time { s=0;while read l; do ((s+=l));done<random_numbers;echo $s; }
16379866392
real 0m7.191s
user 0m6.402s
sys 0m0.776s
$ time { sed ':a;N;s/\n/+/;ta' random_numbers|bc; }
^C
real 4m53.413s
user 4m52.584s
sys 0m0.052s
I aborted the sed run after 5 minutes
I've been diving to lua, and it is speedy:
$ time lua -e 'sum=0; for line in io.lines() do sum=sum+line end; print(sum)' < random_numbers
16388542582.0
real 0m0.362s
user 0m0.313s
sys 0m0.063s
and while I'm updating this, ruby:
$ time ruby -e 'sum = 0; File.foreach(ARGV.shift) {|line| sum+=line.to_i}; puts sum' random_numbers
16388542582
real 0m0.378s
user 0m0.297s
sys 0m0.078s
Heed Ed Morton's advice: using $1
$ time awk '{ sum += $1 } END { print sum }' random_numbers
16388542582
real 0m0.421s
user 0m0.359s
sys 0m0.063s
vs using $0
$ time awk '{ sum += $0 } END { print sum }' random_numbers
16388542582
real 0m0.302s
user 0m0.234s
sys 0m0.063s
回答5:
Another option is to use jq
:
$ seq 10|jq -s add
55
-s
(--slurp
) reads the input lines into an array.
回答6:
This is straight Bash:
sum=0
while read -r line
do
(( sum += line ))
done < file
echo $sum
回答7:
Here's another one-liner
( echo 0 ; sed 's/$/ +/' foo ; echo p ) | dc
This assumes the numbers are integers. If you need decimals, try
( echo 0 2k ; sed 's/$/ +/' foo ; echo p ) | dc
Adjust 2 to the number of decimals needed.
回答8:
I prefer to use R for this:
$ R -e 'sum(scan("filename"))'
回答9:
I prefer to use GNU datamash for such tasks because it's more succinct and legible than perl or awk. For example
datamash sum 1 < myfile
where 1 denotes the first column of data.
回答10:
cat nums | perl -ne '$sum += $_ } { print $sum'
(same as brian d foy's answer, without 'END')
回答11:
Just for fun, lets do it with PDL, Perl's array math engine!
perl -MPDL -E 'say rcols(shift)->sum' datafile
rcols
reads columns into a matrix (1D in this case) and sum
(surprise) sums all the element of the matrix.
回答12:
Here is a solution using python with a generator expression. Tested with a million numbers on my old cruddy laptop.
time python -c "import sys; print sum((float(l) for l in sys.stdin))" < file
real 0m0.619s
user 0m0.512s
sys 0m0.028s
回答13:
$ perl -MList::Util=sum -le 'print sum <>' nums.txt
回答14:
Perl 6
say sum lines
~$ perl6 -e '.say for 0..1000000' > test.in
~$ perl6 -e 'say sum lines' < test.in
500000500000
回答15:
sed ':a;N;s/\n/+/;ta' file|bc
回答16:
More succinct:
# Ruby
ruby -e 'puts open("random_numbers").map(&:to_i).reduce(:+)'
# Python
python -c 'print(sum(int(l) for l in open("random_numbers")))'
回答17:
I have not tested this but it should work:
cat f | tr "\n" "+" | sed 's/+$/\n/' | bc
You might have to add "\n" to the string before bc (like via echo) if bc doesn't treat EOF and EOL...
回答18:
Another for fun
sum=0;for i in $(cat file);do sum=$((sum+$i));done;echo $sum
or another bash only
s=0;while read l; do s=$((s+$l));done<file;echo $s
But awk solution is probably best as it's most compact.
回答19:
With Ruby:
ruby -e "File.read('file.txt').split.inject(0){|mem, obj| mem += obj.to_f}"
回答20:
Running R scripts
I've written an R script to take arguments of a file name and sum the lines.
#! /usr/local/bin/R
file=commandArgs(trailingOnly=TRUE)[1]
sum(as.numeric(readLines(file)))
This can be sped up with the "data.table" or "vroom" package as follows:
#! /usr/local/bin/R
file=commandArgs(trailingOnly=TRUE)[1]
sum(data.table::fread(file))
#! /usr/local/bin/R
file=commandArgs(trailingOnly=TRUE)[1]
sum(vroom::vroom(file))
Benchmarking
Same benchmarking data as @glenn jackman.
for ((i=0; i<1000000; i++)) ; do echo $RANDOM; done > random_numbers
In comparison to the R call above, running R 3.5.0 as a script is comparable to other methods (on the same Linux Debian server).
$ time R -e 'sum(scan("random_numbers"))'
0.37s user
0.04s system
86% cpu
0.478 total
R script with readLines
$ time Rscript sum.R random_numbers
0.53s user
0.04s system
84% cpu
0.679 total
R script with data.table
$ time Rscript sum.R random_numbers
0.30s user
0.05s system
77% cpu
0.453 total
R script with vroom
$ time Rscript sum.R random_numbers
0.54s user
0.11s system
93% cpu
0.696 total
Comparison with other languages
For reference here as some other methods suggested on the same hardware
Python 2 (2.7.13)
$ time python2 -c "import sys; print sum((float(l) for l in sys.stdin))" < random_numbers
0.27s user 0.00s system 89% cpu 0.298 total
Python 3 (3.6.8)
$ time python3 -c "import sys; print(sum((float(l) for l in sys.stdin)))" < random_number
0.37s user 0.02s system 98% cpu 0.393 total
Ruby (2.3.3)
$ time ruby -e 'sum = 0; File.foreach(ARGV.shift) {|line| sum+=line.to_i}; puts sum' random_numbers
0.42s user
0.03s system
72% cpu
0.625 total
Perl (5.24.1)
$ time perl -nle '$sum += $_ } END { print $sum' random_numbers
0.24s user
0.01s system
99% cpu
0.249 total
Awk (4.1.4)
$ time awk '{ sum += $0 } END { print sum }' random_numbers
0.26s user
0.01s system
99% cpu
0.265 total
$ time awk '{ sum += $1 } END { print sum }' random_numbers
0.34s user
0.01s system
99% cpu
0.354 total
C (clang version 3.3; gcc (Debian 6.3.0-18) 6.3.0 )
$ gcc sum.c -o sum && time ./sum < random_numbers
0.10s user
0.00s system
96% cpu
0.108 total
Update with additional languages
Lua (5.3.5)
$ time lua -e 'sum=0; for line in io.lines() do sum=sum+line end; print(sum)' < random_numbers
0.30s user
0.01s system
98% cpu
0.312 total
tr (8.26) must be timed in bash, not compatible with zsh
$time { { tr "\n" + < random_numbers ; echo 0; } | bc; }
real 0m0.494s
user 0m0.488s
sys 0m0.044s
sed (4.4) must be timed in bash, not compatible with zsh
$ time { head -n 10000 random_numbers | sed ':a;N;s/\n/+/;ta' |bc; }
real 0m0.631s
user 0m0.628s
sys 0m0.008s
$ time { head -n 100000 random_numbers | sed ':a;N;s/\n/+/;ta' |bc; }
real 1m2.593s
user 1m2.588s
sys 0m0.012s
note: sed calls seem to work faster on systems with more memory available (note smaller datasets used for benchmarking sed)
Julia (0.5.0)
$ time julia -e 'print(sum(readdlm("random_numbers")))'
3.00s user
1.39s system
136% cpu
3.204 total
$ time julia -e 'print(sum(readtable("random_numbers")))'
0.63s user
0.96s system
248% cpu
0.638 total
Notice that as in R, file I/O methods have different performance.
回答21:
I couldn't just pass by... Here's my Haskell one-liner. It's actually quite readable:
sum <$> (read <$>) <$> lines <$> getContents
Unfortunately there's no ghci -e
to just run it, so it needs the main function, print and compilation.
main = (sum <$> (read <$>) <$> lines <$> getContents) >>= print
To clarify, we read entire input (getContents), split it by lines, read as numbers and sum. <$>
is fmap operator - we use it instead of usual function application because sure this all happens in IO. read
needs an additional fmap, because it is also in the list.
$ ghc sum.hs
[1 of 1] Compiling Main ( sum.hs, sum.o )
Linking sum ...
$ ./sum
1
2
4
^D
7
Here's a strange upgrade to make it work with floats:
main = ((0.0 + ) <$> sum <$> (read <$>) <$> lines <$> getContents) >>= print
$ ./sum
1.3
2.1
4.2
^D
7.6000000000000005
回答22:
I don't know if you can get a lot better than this, considering you need to read through the whole file.
$sum = 0;
while(<>){
$sum += $_;
}
print $sum;
回答23:
Here's another:
open(FIL, "a.txt");
my $sum = 0;
foreach( <FIL> ) {chomp; $sum += $_;}
close(FIL);
print "Sum = $sum\n";
回答24:
C always wins for speed:
#include <stdio.h>
#include <stdlib.h>
int main(int argc, char **argv) {
ssize_t read;
char *line = NULL;
size_t len = 0;
double sum = 0.0;
while (read = getline(&line, &len, stdin) != -1) {
sum += atof(line);
}
printf("%f", sum);
return 0;
}
Timing for 1M numbers (same machine/input as my python answer):
$ gcc sum.c -o sum && time ./sum < numbers
5003371677.000000
real 0m0.188s
user 0m0.180s
sys 0m0.000s
回答25:
You can do it with Alacon - command-line utility for Alasql database.
It works with Node.js, so you need to install Node.js and then Alasql package:
To calculate sum from TXT file you can use the following command:
> node alacon "SELECT VALUE SUM([0]) FROM TXT('mydata.txt')"
回答26:
It is not easier to replace all new lines by +
, add a 0
and send it to the Ruby
interpreter?
(sed -e "s/$/+/" file; echo 0)|irb
If you do not have irb
, you can send it to bc
, but you have to remove all newlines except the last one (of echo
). It is better to use tr
for this, unless you have a PhD in sed
.
(sed -e "s/$/+/" file|tr -d "\n"; echo 0)|bc
回答27:
Just to be ridiculous:
cat f | tr "\n" "+" | perl -pne chop | R --vanilla --slave