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问题:
I have Activity A
with android:launchMode="singleTop"
in the manifest.
If I go to Activity B
, C
, and D
there I have menu shortcuts to return to my applications root activity (A
).
The code looks like this:
Intent myIntent = new Intent(getBaseContext(), MainActivity.class);
startActivity(myIntent);
However, instead of returning to the already existing instance A
of my MainActivity.class
it creates a new instance -> it goes to onCreate()
instead of onNewIntent()
.
This is not the expected behavior, right?
回答1:
This should do the trick.
<activity ... android:launchMode="singleTop" />
When you create an intent to start the app use:
Intent intent= new Intent(context, YourActivity.class);
intent.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK | Intent.FLAG_ACTIVITY_SINGLE_TOP);
This is that should be needed.
回答2:
What actually worked for me in the end was this:
Intent myIntent = new Intent(getBaseContext(), MainActivity.class);
myIntent.setFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
startActivity(myIntent);
回答3:
Quote from the documentation:
The "standard" and "singleTop" modes
differ from each other in just one
respect: Every time there's new intent
for a "standard" activity, a new
instance of the class is created to
respond to that intent. Each instance
handles a single intent. Similarly, a
new instance of a "singleTop" activity
may also be created to handle a new
intent. However, if the target task
already has an existing instance of
the activity at the top of its
stack, that instance will receive
the new intent (in an onNewIntent()
call); a new instance is not created.
I'm not 100% sure what "already has an existing instance of the activity at the top of its stack" means, but perhaps your activity isn't meeting this condition.
Would singleTask
or singleInstance
work for you? Or perhaps you could try setting FLAG_ACTIVITY_SINGLE_TOP
on the intent you are creating to see if that makes a difference, although I don't think it will.
回答4:
You can return to the same existing instance of Activity with
android:launchMode="singleInstance"
in the manifest.
When you return to A
from B
, may be needed finish()
to destroy B
.
回答5:
Firstly, Stack structure can be examined. For the launch mode:singleTop
If an instance of the same activity is already on top of the task stack, then this instance will be reused to respond to the intent.
All activities are hold in the stack("first in last out") so if your current activity is at the top of stack and if you define it in the manifest.file as singleTop
android:name=".ActivityA"
android:launchMode="singleTop"
if you are in the ActivityA recreate the activity it will not enter onCreate will resume onNewIntent() and you can see by creating a notification
Not:İf you do not implement onNewIntent(Intent) you will not get new intent.
Intent activityMain = new Intent(ActivityA.this,
ActivityA.class);
activityMain.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK
| Intent.FLAG_ACTIVITY_SINGLE_TOP);
startActivity(activityMain);
@Override
protected void onNewIntent(Intent intent) {
super.onNewIntent(intent);
notify("onNewIntent");
}
private void notify(String methodName) {
String name = this.getClass().getName();
String[] strings = name.split("\\.");
Notification noti = new Notification.Builder(this)
.setContentTitle(methodName + "" + strings[strings.length - 1])
.setAutoCancel(true).setSmallIcon(R.drawable.ic_launcher)
.setContentText(name).build();
NotificationManager notificationManager = (NotificationManager) getSystemService(NOTIFICATION_SERVICE);
notificationManager.notify((int) System.currentTimeMillis(), noti);
}
回答6:
This is because the original A activity is already being destroyed by the time you start it from B, C or D. Therefore, onCreate will be called in stead of onNewIntent(). One way of solving this is to always destroy the existing A(using FLAG_ACTIVITY_CLEAR_TASK | FLAG_ACTIVITY_NEW_TASK conjunction when startActivity) before starting a new A, so onCreate will always be called, and you put the code of onNewIntent() into onCreate by checking if getIntent() is the intent you started with.