I am facing some difficulty with calculating the time difference between two dates.
What I want is, I have two dates let say
@StartDate = '10/01/2012 08:40:18.000'
@EndDate='10/04/2012 09:52:48.000'
so the difference between two dates in the form of hh:mm:ss is 72:42:30.
How can I get this result in a T-SQL query?
declare @StartDate datetime, @EndDate datetime
select @StartDate = '10/01/2012 08:40:18.000',@EndDate='10/04/2012 09:52:48.000'
select convert(varchar(5),DateDiff(s, @startDate, @EndDate)/3600)+':'+convert(varchar(5),DateDiff(s, @startDate, @EndDate)%3600/60)+':'+convert(varchar(5),(DateDiff(s, @startDate, @EndDate)%60)) as [hh:mm:ss]
This query will helpful to you.
The shortest code would be:
Select CAST((@EndDateTime-@StartDateTime) as time(0)) '[hh:mm:ss]'
While maybe not the most efficient, this would work:
declare @StartDate datetime, @EndDate datetime
select @StartDate = '10/01/2012 08:40:18.000',@EndDate='10/04/2012 09:52:48.000'
select convert(varchar(5),DateDiff(s, @startDate, @EndDate)/3600)+':'+convert(varchar(5),DateDiff(s, @startDate, @EndDate)%3600/60)+':'+convert(varchar(5),(DateDiff(s, @startDate, @EndDate)%60))
if you can run two selects then this would be better because you only do the datediff once:
declare @StartDate datetime, @EndDate datetime
select @StartDate = '10/01/2012 08:40:18.000',@EndDate='10/04/2012 09:52:48.000'
declare @Sec BIGINT
select @Sec = DateDiff(s, @startDate, @EndDate)
select convert(varchar(5),@sec/3600)+':'+convert(varchar(5),@sec%3600/60)+':'+convert(varchar(5),(@sec%60))
I like the idea of making this into a function so it becomes re-useable and your queries become much easier to read:
--get the difference between two datetimes in the format: 'h:m:s'
CREATE FUNCTION getDateDiff(@startDate DATETIME, @endDate DATETIME)
RETURNS VARCHAR(10)
AS BEGIN
DECLARE @seconds INT = DATEDIFF(s, @startDate, @endDate)
DECLARE @difference VARCHAR(10) =
CONVERT(VARCHAR(4), @seconds / 3600) + ':' +
CONVERT(VARCHAR(2), @seconds % 3600 / 60) + ':' +
CONVERT(VARCHAR(2), @seconds % 60)
RETURN @difference
END
Usage:
DECLARE @StartDate DATETIME = '10/01/2012 08:40:18.000'
DECLARE @endDate DATETIME = '10/04/2012 09:52:48.000'
SELECT dbo.getDateDiff(@startDate, @endDate) AS DateDifference
Result:
DateDifference
1 73:12:30
It's also easier to read the result if you add padding so the format is always hh:mm:ss. For example, here's how you would do that in SQL Server 2012 or later:
--get the difference between two datetimes in the format: 'hh:mm:ss'
CREATE FUNCTION getDateDiff(@startDate DATETIME, @endDate DATETIME)
RETURNS VARCHAR(10)
AS BEGIN
DECLARE @seconds INT = DATEDIFF(s, @startDate, @endDate)
DECLARE @difference VARCHAR(10) =
FORMAT(@seconds / 3600, '00') + ':' +
FORMAT(@seconds % 3600 / 60, '00') + ':' +
FORMAT(@seconds % 60, '00')
RETURN @difference
END
Note that this will not clip the hour if it is more than 2 digits long. So 1 hour would show up as 01:00:00 and 100 hours would show up as 100:00:00
If you're not opposed to implicit type casting I'll offer this an alternative solution. Is it more readable with better formatting? You be the judge.
DECLARE @StartDate datetime = '10/01/2012 08:40:18.000'
,@EndDate datetime = '10/04/2012 09:52:48.000'
SELECT
STR(ss/3600, 5) + ':' + RIGHT('0' + LTRIM(ss%3600/60), 2) + ':' + RIGHT('0' + LTRIM(ss%60), 2) AS [hh:mm:ss]
FROM (VALUES(DATEDIFF(s, @StartDate, @EndDate))) seconds (ss)
DECLARE @dt1 datetime='2012/06/13 08:11:12', @dt2 datetime='2012/06/12 02:11:12'
SELECT CAST((@dt2-@dt1) as time(0))
Try this one:
declare @StartDate datetime, @EndDate datetime
select @StartDate = '2016-05-04 10:23:41.083', @EndDate='2016-05-04 10:25:26.053'
select CAST(DateDiff(MI, @startDate, @EndDate)/60 AS varchar)+':'+Cast(DateDiff(MI, @startDate, @EndDate)%60 AS varchar)+':'+cast(DateDiff(s, @startDate, @EndDate)%60 AS varchar) as [hh:mm:ss]
If you need a zero padded difference between 2 dates:
SELECT convert(varchar(2),FORMAT(DATEDIFF(s, @startDate, @endDate)/3600,'0#'))+':'
+convert(varchar(2),FORMAT(DATEDIFF(s, @startDate, @endDate)%3600/60,'0#'))+':'
+convert(varchar(2),FORMAT(DATEDIFF(s, @startDate, @endDate)%60,'0#')) AS Duration
Take a look at these. I didn't use more parenthesis to keep it readable, so remember that multiplication is done before addition or subtraction.
Both below return:
hr mins sec timediff
73 12 30 73:12:30
This is written to not use a sub-query and be the most readable and understandable:
declare @StartDate datetime,
@EndDate datetime
set @StartDate = '10/01/2012 08:40:18.000'
set @EndDate = '10/04/2012 09:52:48.000'
select datediff(hour, @StartDate, @EndDate) hr,
datediff(minute, @StartDate, @EndDate)
- datediff(hour, @StartDate, @EndDate) * 60 mins,
datediff(second, @StartDate, @EndDate)
- (datediff(minute, @StartDate, @EndDate) * 60) sec,
cast(datediff(hour, @StartDate, @EndDate) as varchar)+':'+
cast(datediff(minute, @StartDate, @EndDate)
- datediff(hour, @StartDate, @EndDate) * 60 as varchar)+':'+
cast(datediff(second, @StartDate, @EndDate)
- (datediff(minute, @StartDate, @EndDate) * 60) as varchar) timediff
This is a version that would perform better if you have a lot of data. It requires a sub-query.
declare @StartDate datetime,
@EndDate datetime
set @StartDate = '10/01/2012 08:40:18.000'
set @EndDate = '10/04/2012 09:52:48.000'
select s.seconds / 3600 hrs,
s.seconds / 60 - (seconds / 3600 ) * 60 mins,
s.seconds - (s.seconds / 60) * 60 seconds,
cast(s.seconds / 3600 as varchar) + ':' +
cast((s.seconds / 60 - (seconds / 3600 ) * 60) as varchar) + ':' +
cast((s.seconds - (s.seconds / 60) * 60) as varchar) timediff
from (select datediff(second, @StartDate, @EndDate) as seconds) s
I came across this post today as I was trying to gather the time difference between fields located in separate tables joined together on a key field. This is the working code for such an endeavor. (tested in sql 2010) Bare in mind that my original query co-joined 6 tables on a common keyfield, in the code below I have removed the other tables as to not cause any confusion for the reader.
The purpose of the query is to calculate the difference between the variables CreatedUTC & BackupUTC, where difference is expressed in days and the field is called 'DaysActive.'
declare @CreatedUTC datetime
declare @BackupUtc datetime
SELECT TOP 500
table02.Column_CreatedUTC AS DeviceCreated,
CAST(DATEDIFF(day, table02.Column_CreatedUTC, table03.Column_EndDateUTC) AS nvarchar(5))+ ' Days' As DaysActive,
table03.Column_EndDateUTC AS LastCompleteBackup
FROM
Operations.table01 AS table01
LEFT OUTER JOIN
dbo.table02 AS table02
ON
table02.Column_KeyField = table01.Column_KeyField
LEFT OUTER JOIN
dbo.table03 AS table03
ON
table01.Column_KeyField = table03.Column_KeyField
Where table03.Column_EndDateUTC > dateadd(hour, -24, getutcdate()) --Gathers records with an end date in the last 24 hours
AND table02.[Column_CreatedUTC] = COALESCE(@CreatedUTC, table02.[Column_CreatedUTC])
AND table03.[Column_EndDateUTC] = COALESCE(@BackupUTC, table03.[Column_EndDateUTC])
GROUP BY table03.Column_EndDateUTC, table02.Column_CreatedUTC
ORDER BY table02.Column_CreatedUTC ASC, DaysActive, table03.Column_EndDateUTC DESC
The Output will be as follows:
[DeviceCreated]..[DaysActive]..[LastCompleteBackup]
---------------------------------------------------------
[2/13/12 16:04]..[463 Days]....[5/21/13 12:14]
[2/12/13 22:37]..[97 Days].....[5/20/13 22:10]
It's A Script Write Copy then write in your script file and change your requered field and get out put
DECLARE @Sdate DATETIME, @Edate DATETIME, @Timediff VARCHAR(100)
SELECT @Sdate = '02/12/2014 08:40:18.000',@Edate='02/13/2014 09:52:48.000'
SET @Timediff=DATEDIFF(s, @Sdate, @Edate)
SELECT CONVERT(VARCHAR(5),@Timediff/3600)+':'+convert(varchar(5),@Timediff%3600/60)+':'+convert(varchar(5),@Timediff%60) AS TimeDiff
DECLARE @StartDate datetime = '10/01/2012 08:40:18.000'
,@EndDate datetime = '10/10/2012 09:52:48.000'
,@DaysDifferent int = 0
,@Sec BIGINT
select @Sec = DateDiff(s, @StartDate, @EndDate)
IF (DATEDIFF(day, @StartDate, @EndDate) > 0)
BEGIN
select @DaysDifferent = DATEDIFF(day, @StartDate, @EndDate)
select @Sec = @Sec - ( @DaysDifferent * 86400 )
SELECT LTRIM(STR(@DaysDifferent,3)) +'d '+ LTRIM(STR(@Sec/3600, 5)) + ':' + RIGHT('0' + LTRIM(@Sec%3600/60), 2) + ':' + RIGHT('0' + LTRIM(@Sec%60), 2) AS [dd hh:mm:ss]
END
ELSE
BEGIN
SELECT LTRIM(STR(@DaysDifferent,3)) +'d '+ LTRIM(STR(@Sec/3600, 5)) + ':' + RIGHT('0' + LTRIM(@Sec%3600/60), 2) + ':' + RIGHT('0' + LTRIM(@Sec%60), 2) AS [dd hh:mm:ss]
END
----------------------------------------------------------------------------------
dd HH:MM:SS
9d 1:12:30
declare @StartDate datetime, @EndDate datetime
set @StartDate = '10/01/2012 08:40:18.000'
set @EndDate = '10/04/2012 09:52:48.000'
SELECT CONVERT(CHAR(8), CAST(CONVERT(varchar(23),@EndDate,121) AS DATETIME)
-CAST(CONVERT(varchar(23),@StartDate,121)AS DATETIME),8) AS TimeDiff
declare @StartDate datetime;
declare @EndDate datetime;
select @StartDate = '10/01/2012 08:40:18.000';
select @EndDate='10/04/2012 09:52:48.000';
select cast(datediff(hour,@StartDate,@EndDate) as varchar(10)) + left(right(cast(cast(cast((@EndDate-@StartDate) as datetime) as time) as varchar(16)),14),6)
