How do I print the type of a variable in Rust?

问题:

I have the following:

let mut my_number = 32.90;

How do I print the type of my_number?

Using type and type_of did not work. Is there another way I can print the number's type?

回答1:

If you merely wish to find out the type of a variable and are willing to do it at compile time, you can cause an error and get the compiler to pick it up.

For example, set the variable to a type which doesn't work:

let mut my_number: () = 32.90;
// let () = x; would work too

error[E0308]: mismatched types
 --> src/main.rs:2:29
  |
2 |     let mut my_number: () = 32.90;
  |                             ^^^^^ expected (), found floating-point number
  |
  = note: expected type `()`
             found type `{float}`

Or call an invalid method:

let mut my_number = 32.90;
my_number.what_is_this();

error[E0599]: no method named `what_is_this` found for type `{float}` in the current scope
 --> src/main.rs:3:15
  |
3 |     my_number.what_is_this();
  |               ^^^^^^^^^^^^

Or access an invalid field:

let mut my_number = 32.90;
my_number.what_is_this

error[E0610]: `{float}` is a primitive type and therefore doesn't have fields
 --> src/main.rs:3:15
  |
3 |     my_number.what_is_this
  |               ^^^^^^^^^^^^

These reveal the type, which in this case is actually not fully resolved. It’s called “floating-point variable” in the first example, and “{float}” in all three examples; this is a partially resolved type which could end up f32 or f64, depending on how you use it. “{float}” is not a legal type name, it’s a placeholder meaning “I’m not completely sure what this is”, but it is a floating-point number. In the case of floating-point variables, if you don't constrain it, it will default to f64¹. (An unqualified integer literal will default to i32.)

See also:

• What is the {integer} or {float} in a compiler error message?

---

¹ There may still be ways of baffling the compiler so that it can’t decide between f32 and f64; I’m not sure. It used to be as simple as 32.90.eq(&32.90), but that treats both as f64 now and chugs along happily, so I don’t know.

回答2:

There is an unstable function std::intrinsics::type_name that can get you the name of a type, though you have to use a nightly build of Rust (this is unlikely to ever work in stable Rust). Here’s an example:

#![feature(core_intrinsics)]

fn print_type_of<T>(_: &T) {
    println!("{}", unsafe { std::intrinsics::type_name::<T>() });
}

fn main() {
    print_type_of(&32.90);          // prints "f64"
    print_type_of(&vec![1, 2, 4]);  // prints "std::vec::Vec<i32>"
    print_type_of(&"foo");          // prints "&str"
}

回答3:

If you know all the types beforehand, you can use traits to add a type_of method:

trait TypeInfo {
    fn type_of(&self) -> &'static str;
}

impl TypeInfo for i32 {
    fn type_of(&self) -> &'static str {
        "i32"
    }
}

impl TypeInfo for i64 {
    fn type_of(&self) -> &'static str {
        "i64"
    }
}

//...

No intrisics or nothin', so although more limited this is the only solution here that gets you a string and is stable. (see French Boiethios's answer) However, it's very laborious and doesn't account for type parameters, so we could...

trait TypeInfo {
    fn type_name() -> String;
    fn type_of(&self) -> String;
}

macro_rules! impl_type_info {
    ($($name:ident$(<$($T:ident),+>)*),*) => {
        $(impl_type_info_single!($name$(<$($T),*>)*);)*
    };
}

macro_rules! mut_if {
    ($name:ident = $value:expr, $($any:expr)+) => (let mut $name = $value;);
    ($name:ident = $value:expr,) => (let $name = $value;);
}

macro_rules! impl_type_info_single {
    ($name:ident$(<$($T:ident),+>)*) => {
        impl$(<$($T: TypeInfo),*>)* TypeInfo for $name$(<$($T),*>)* {
            fn type_name() -> String {
                mut_if!(res = String::from(stringify!($name)), $($($T)*)*);
                $(
                    res.push('<');
                    $(
                        res.push_str(&$T::type_name());
                        res.push(',');
                    )*
                    res.pop();
                    res.push('>');
                )*
                res
            }
            fn type_of(&self) -> String {
                $name$(::<$($T),*>)*::type_name()
            }
        }
    }
}

impl<'a, T: TypeInfo + ?Sized> TypeInfo for &'a T {
    fn type_name() -> String {
        let mut res = String::from("&");
        res.push_str(&T::type_name());
        res
    }
    fn type_of(&self) -> String {
        <&T>::type_name()
    }
}

impl<'a, T: TypeInfo + ?Sized> TypeInfo for &'a mut T {
    fn type_name() -> String {
        let mut res = String::from("&mut ");
        res.push_str(&T::type_name());
        res
    }
    fn type_of(&self) -> String {
        <&mut T>::type_name()
    }
}

macro_rules! type_of {
    ($x:expr) => { (&$x).type_of() };
}

Let's use it:

impl_type_info!(i32, i64, f32, f64, str, String, Vec<T>, Result<T,S>)

fn main() {
    println!("{}", type_of!(1));
    println!("{}", type_of!(&1));
    println!("{}", type_of!(&&1));
    println!("{}", type_of!(&mut 1));
    println!("{}", type_of!(&&mut 1));
    println!("{}", type_of!(&mut &1));
    println!("{}", type_of!(1.0));
    println!("{}", type_of!("abc"));
    println!("{}", type_of!(&"abc"));
    println!("{}", type_of!(String::from("abc")));
    println!("{}", type_of!(vec![1,2,3]));

    println!("{}", <Result<String,i64>>::type_name());
    println!("{}", <&i32>::type_name());
    println!("{}", <&str>::type_name());
}

output:

i32
&i32
&&i32
&mut i32
&&mut i32
&mut &i32
f64
&str
&&str
String
Vec<i32>
Result<String,i64>
&i32
&str

---

Rust Playground

回答4:

You can use the std::any::type_name function. This doesn't need a nightly compiler or an external crate, and the results are quite correct:

fn print_type_of<T>(_: &T) {
    println!("{}", std::any::type_name::<T>())
}

fn main() {
    let s = "Hello";
    let i = 42;

    print_type_of(&s); // &str
    print_type_of(&i); // i32
    print_type_of(&main); // playground::main
    print_type_of(&print_type_of::<i32>); // playground::print_type_of<i32>
    print_type_of(&{ || "Hi!" }); // playground::main::{{closure}}
}

Be warned: as said in the documentation, this information must be used for a debug purpose only:

This is intended for diagnostic use. The exact contents and format of the string are not specified, other than being a best-effort description of the type.

If you want your type representation to stay the same between compiler versions, you should use a trait, like in the phicr's answer.

回答5:

UPD The following does not work anymore. Check Shubham's answer for correction.

Check out std::intrinsics::get_tydesc<T>(). It is in "experimental" state right now, but it's OK if you are just hacking around the type system.

Check out the following example:

fn print_type_of<T>(_: &T) -> () {
    let type_name =
        unsafe {
            (*std::intrinsics::get_tydesc::<T>()).name
        };
    println!("{}", type_name);
}

fn main() -> () {
    let mut my_number = 32.90;
    print_type_of(&my_number);       // prints "f64"
    print_type_of(&(vec!(1, 2, 4))); // prints "collections::vec::Vec<int>"
}

This is what is used internally to implement the famous {:?} formatter.

回答6:

I put together a little crate to do this based off vbo's answer. It gives you a macro to return or print out the type.

Put this in your Cargo.toml file:

[dependencies]
t_bang = "0.1.2"

Then you can use it like so:

#[macro_use] extern crate t_bang;
use t_bang::*;

fn main() {
  let x = 5;
  let x_type = t!(x);
  println!("{:?}", x_type);  // prints out: "i32"
  pt!(x);                    // prints out: "i32"
  pt!(5);                    // prints out: "i32"
}

回答7:

You can also use the simple approach of using the variable in println!("{:?}", var). If Debug is not implemented for the type, you can see the type in the compiler's error message:

mod some {
    pub struct SomeType;
}

fn main() {
    let unknown_var = some::SomeType;
    println!("{:?}", unknown_var);
}

(playpen)

It's dirty but it works.

回答8:

There's a @ChrisMorgan answer to get approximate type ("float") in stable rust and there's a @ShubhamJain answer to get precise type ("f64") through unstable function in nightly rust.

Now here's a way one can get precise type (ie decide between f32 and f64) in stable rust:

fn main() {
    let a = 5.;
    let _: () = unsafe { std::mem::transmute(a) };
}

results in

error[E0512]: cannot transmute between types of different sizes, or dependently-sized types
 --> main.rs:3:27
  |
3 |     let _: () = unsafe { std::mem::transmute(a) };
  |                           ^^^^^^^^^^^^^^^^^^^
  |
  = note: source type: `f64` (64 bits)
  = note: target type: `()` (0 bits)

Update

The turbofish variation

fn main() {
    let a = 5.;
    unsafe { std::mem::transmute::<_, ()>(a) }
}

is slightly shorter but somewhat less readable.

回答9:

Some other answers don't work, but I find that the typename crate works.

1. Create a new project:

   cargo new test_typename
   

2. Modify the Cargo.toml

   [dependencies]
   typename = "0.1.1"
   

3. Modify your source code

   use typename::TypeName;
   
   fn main() {
       assert_eq!(String::type_name(), "std::string::String");
       assert_eq!(Vec::<i32>::type_name(), "std::vec::Vec<i32>");
       assert_eq!([0, 1, 2].type_name_of(), "[i32; 3]");
   
       let a = 65u8;
       let b = b'A';
       let c = 65;
       let d = 65i8;
       let e = 65i32;
       let f = 65u32;
   
       let arr = [1,2,3,4,5];
       let first = arr[0];
   
       println!("type of a 65u8  {} is {}", a, a.type_name_of());
       println!("type of b b'A'  {} is {}", b, b.type_name_of());
       println!("type of c 65    {} is {}", c, c.type_name_of());
       println!("type of d 65i8  {} is {}", d, d.type_name_of());
       println!("type of e 65i32 {} is {}", e, e.type_name_of());
       println!("type of f 65u32 {} is {}", f, f.type_name_of());
   
       println!("type of arr {:?} is {}", arr, arr.type_name_of());
       println!("type of first {} is {}", first, first.type_name_of());
   }
   

The output is:

type of a 65u8  65 is u8
type of b b'A'  65 is u8
type of c 65    65 is i32
type of d 65i8  65 is i8
type of e 65i32 65 is i32
type of f 65u32 65 is u32
type of arr [1, 2, 3, 4, 5] is [i32; 5]
type of first 1 is i32

回答10:

If your just wanting to know the type of your variable during interactive development, I would highly recommend using rls (rust language server) inside of your editor or ide. You can then simply permanently enable or toggle the hover ability and just put your cursor over the variable. A little dialog should come up with information about the variable including the type.