In the following method definitions, what does the * and ** do for param2?
def foo(param1, *param2):
def bar(param1, **param2):
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试):
问题:
回答1:
The *args and **kwargs is a common idiom to allow arbitrary number of arguments to functions as described in the section more on defining functions in the Python documentation.
The *args will give you all function parameters as a tuple:
def foo(*args):
for a in args:
print(a)
foo(1)
# 1
foo(1,2,3)
# 1
# 2
# 3
The **kwargs will give you all
keyword arguments except for those corresponding to a formal parameter as a dictionary.
def bar(**kwargs):
for a in kwargs:
print(a, kwargs[a])
bar(name='one', age=27)
# age 27
# name one
Both idioms can be mixed with normal arguments to allow a set of fixed and some variable arguments:
def foo(kind, *args, **kwargs):
pass
It is also possible to use this the other way around:
def foo(a, b, c):
print(a, b, c)
obj = {'b':10, 'c':'lee'}
foo(100,**obj)
# 100 10 lee
Another usage of the *l idiom is to unpack argument lists when calling a function.
def foo(bar, lee):
print(bar, lee)
l = [1,2]
foo(*l)
# 1 2
In Python 3 it is possible to use *l on the left side of an assignment (Extended Iterable Unpacking), though it gives a list instead of a tuple in this context:
first, *rest = [1,2,3,4]
first, *l, last = [1,2,3,4]
Also Python 3 adds new semantic (refer PEP 3102):
def func(arg1, arg2, arg3, *, kwarg1, kwarg2):
pass
Such function accepts only 3 positional arguments, and everything after * can only be passed as keyword arguments.
回答2:
It's also worth noting that you can use * and ** when calling functions as well. This is a shortcut that allows you to pass multiple arguments to a function directly using either a list/tuple or a dictionary. For example, if you have the following function:
def foo(x,y,z):
print("x=" + str(x))
print("y=" + str(y))
print("z=" + str(z))
You can do things like:
>>> mylist = [1,2,3]
>>> foo(*mylist)
x=1
y=2
z=3
>>> mydict = {'x':1,'y':2,'z':3}
>>> foo(**mydict)
x=1
y=2
z=3
>>> mytuple = (1, 2, 3)
>>> foo(*mytuple)
x=1
y=2
z=3
Note: The keys in mydict have to be named exactly like the parameters of function foo. Otherwise it will throw a TypeError:
>>> mydict = {'x':1,'y':2,'z':3,'badnews':9}
>>> foo(**mydict)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: foo() got an unexpected keyword argument 'badnews'
回答3:
The single * means that there can be any number of extra positional arguments. foo() can be invoked like foo(1,2,3,4,5). In the body of foo() param2 is a sequence containing 2-5.
The double ** means there can be any number of extra named parameters. bar() can be invoked like bar(1, a=2, b=3). In the body of bar() param2 is a dictionary containing {'a':2, 'b':3 }
With the following code:
def foo(param1, *param2):
print(param1)
print(param2)
def bar(param1, **param2):
print(param1)
print(param2)
foo(1,2,3,4,5)
bar(1,a=2,b=3)
the output is
1
(2, 3, 4, 5)
1
{'a': 2, 'b': 3}
回答4:
What does
**(double star) and*(star) do for parameters
They allow for functions to be defined to accept and for users to pass any number of arguments, positional (*) and keyword (**).
Defining Functions
*args allows for any number of optional positional arguments (parameters), which will be assigned to a tuple named args.
**kwargs allows for any number of optional keyword arguments (parameters), which will be in a dict named kwargs.
You can (and should) choose any appropriate name, but if the intention is for the arguments to be of non-specific semantics, args and kwargs are standard names.
Expansion, Passing any number of arguments
You can also use *args and **kwargs to pass in parameters from lists (or any iterable) and dicts (or any mapping), respectively.
The function recieving the parameters does not have to know that they are being expanded.
For example, Python 2's xrange does not explicitly expect *args, but since it takes 3 integers as arguments:
>>> x = xrange(3) # create our *args - an iterable of 3 integers
>>> xrange(*x) # expand here
xrange(0, 2, 2)
As another example, we can use dict expansion in str.format:
>>> foo = 'FOO'
>>> bar = 'BAR'
>>> 'this is foo, {foo} and bar, {bar}'.format(**locals())
'this is foo, FOO and bar, BAR'
New in Python 3: Defining functions with keyword only arguments
You can have keyword only arguments after the *args - for example, here, kwarg2 must be given as a keyword argument - not positionally:
def foo(arg, kwarg=None, *args, kwarg2=None, **kwargs):
return arg, kwarg, args, kwarg2, kwargs
Usage:
>>> foo(1,2,3,4,5,kwarg2='kwarg2', bar='bar', baz='baz')
(1, 2, (3, 4, 5), 'kwarg2', {'bar': 'bar', 'baz': 'baz'})
Also, * can be used by itself to indicate that keyword only arguments follow, without allowing for unlimited positional arguments.
def foo(arg, kwarg=None, *, kwarg2=None, **kwargs):
return arg, kwarg, kwarg2, kwargs
Here, kwarg2 again must be an explicitly named, keyword argument:
>>> foo(1,2,kwarg2='kwarg2', foo='foo', bar='bar')
(1, 2, 'kwarg2', {'foo': 'foo', 'bar': 'bar'})
And we can no longer accept unlimited positional arguments because we don't have *args*:
>>> foo(1,2,3,4,5, kwarg2='kwarg2', foo='foo', bar='bar')
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: foo() takes from 1 to 2 positional arguments
but 5 positional arguments (and 1 keyword-only argument) were given
Again, more simply, here we require kwarg to be given by name, not positionally:
def bar(*, kwarg=None):
return kwarg
In this example, we see that if we try to pass kwarg positionally, we get an error:
>>> bar('kwarg')
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: bar() takes 0 positional arguments but 1 was given
We must explicitly pass the kwarg parameter as a keyword argument.
>>> bar(kwarg='kwarg')
'kwarg'
Python 2 compatible demos
*args (typically said "star-args") and **kwargs (stars can be implied by saying "kwargs", but be explicit with "double-star kwargs") are common idioms of Python for using the * and ** notation. These specific variable names aren't required (e.g. you could use *foos and **bars), but a departure from convention is likely to enrage your fellow Python coders.
We typically use these when we don't know what our function is going to receive or how many arguments we may be passing, and sometimes even when naming every variable separately would get very messy and redundant (but this is a case where usually explicit is better than implicit).
Example 1
The following function describes how they can be used, and demonstrates behavior. Note the named b argument will be consumed by the second positional argument before :
def foo(a, b=10, *args, **kwargs):
'''
this function takes required argument a, not required keyword argument b
and any number of unknown positional arguments and keyword arguments after
'''
print('a is a required argument, and its value is {0}'.format(a))
print('b not required, its default value is 10, actual value: {0}'.format(b))
# we can inspect the unknown arguments we were passed:
# - args:
print('args is of type {0} and length {1}'.format(type(args), len(args)))
for arg in args:
print('unknown arg: {0}'.format(arg))
# - kwargs:
print('kwargs is of type {0} and length {1}'.format(type(kwargs),
len(kwargs)))
for kw, arg in kwargs.items():
print('unknown kwarg - kw: {0}, arg: {1}'.format(kw, arg))
# But we don't have to know anything about them
# to pass them to other functions.
print('Args or kwargs can be passed without knowing what they are.')
# max can take two or more positional args: max(a, b, c...)
print('e.g. max(a, b, *args) \n{0}'.format(
max(a, b, *args)))
kweg = 'dict({0})'.format( # named args same as unknown kwargs
', '.join('{k}={v}'.format(k=k, v=v)
for k, v in sorted(kwargs.items())))
print('e.g. dict(**kwargs) (same as {kweg}) returns: \n{0}'.format(
dict(**kwargs), kweg=kweg))
We can check the online help for the function's signature, with help(foo), which tells us
foo(a, b=10, *args, **kwargs)
Let's call this function with foo(1, 2, 3, 4, e=5, f=6, g=7)
which prints:
a is a required argument, and its value is 1
b not required, its default value is 10, actual value: 2
args is of type <type 'tuple'> and length 2
unknown arg: 3
unknown arg: 4
kwargs is of type <type 'dict'> and length 3
unknown kwarg - kw: e, arg: 5
unknown kwarg - kw: g, arg: 7
unknown kwarg - kw: f, arg: 6
Args or kwargs can be passed without knowing what they are.
e.g. max(a, b, *args)
4
e.g. dict(**kwargs) (same as dict(e=5, f=6, g=7)) returns:
{'e': 5, 'g': 7, 'f': 6}
Example 2
We can also call it using another function, into which we just provide a:
def bar(a):
b, c, d, e, f = 2, 3, 4, 5, 6
# dumping every local variable into foo as a keyword argument
# by expanding the locals dict:
foo(**locals())
bar(100) prints:
a is a required argument, and its value is 100
b not required, its default value is 10, actual value: 2
args is of type <type 'tuple'> and length 0
kwargs is of type <type 'dict'> and length 4
unknown kwarg - kw: c, arg: 3
unknown kwarg - kw: e, arg: 5
unknown kwarg - kw: d, arg: 4
unknown kwarg - kw: f, arg: 6
Args or kwargs can be passed without knowing what they are.
e.g. max(a, b, *args)
100
e.g. dict(**kwargs) (same as dict(c=3, d=4, e=5, f=6)) returns:
{'c': 3, 'e': 5, 'd': 4, 'f': 6}
Example 3: practical usage in decorators
OK, so maybe we're not seeing the utility yet. So imagine you have several functions with redundant code before and/or after the differentiating code. The following named functions are just pseudo-code for illustrative purposes.
def foo(a, b, c, d=0, e=100):
# imagine this is much more code than a simple function call
preprocess()
differentiating_process_foo(a,b,c,d,e)
# imagine this is much more code than a simple function call
postprocess()
def bar(a, b, c=None, d=0, e=100, f=None):
preprocess()
differentiating_process_bar(a,b,c,d,e,f)
postprocess()
def baz(a, b, c, d, e, f):
... and so on
We might be able to handle this differently, but we can certainly extract the redundancy with a decorator, and so our below example demonstrates how *args and **kwargs can be very useful:
def decorator(function):
'''function to wrap other functions with a pre- and postprocess'''
@functools.wraps(function) # applies module, name, and docstring to wrapper
def wrapper(*args, **kwargs):
# again, imagine this is complicated, but we only write it once!
preprocess()
function(*args, **kwargs)
postprocess()
return wrapper
And now every wrapped function can be written much more succinctly, as we've factored out the redundancy:
@decorator
def foo(a, b, c, d=0, e=100):
differentiating_process_foo(a,b,c,d,e)
@decorator
def bar(a, b, c=None, d=0, e=100, f=None):
differentiating_process_bar(a,b,c,d,e,f)
@decorator
def baz(a, b, c=None, d=0, e=100, f=None, g=None):
differentiating_process_baz(a,b,c,d,e,f, g)
@decorator
def quux(a, b, c=None, d=0, e=100, f=None, g=None, h=None):
differentiating_process_quux(a,b,c,d,e,f,g,h)
And by factoring out our code, which *args and **kwargs allows us to do, we reduce lines of code, improve readability and maintainability, and have sole canonical locations for the logic in our program. If we need to change any part of this structure, we have one place in which to make each change.
回答5:
Let us first understand what are positional arguments and keyword arguments. Below is an example of function definition with Positional arguments.
def test(a,b,c):
print(a)
print(b)
print(c)
test(1,2,3)
#output:
1
2
3
So this is a function definition with positional arguments. You can call it with keyword/named arguments as well:
def test(a,b,c):
print(a)
print(b)
print(c)
test(a=1,b=2,c=3)
#output:
1
2
3
Now let us study an example of function definition with keyword arguments:
def test(a=0,b=0,c=0):
print(a)
print(b)
print(c)
print('-------------------------')
test(a=1,b=2,c=3)
#output :
1
2
3
-------------------------
You can call this function with positional arguments as well:
def test(a=0,b=0,c=0):
print(a)
print(b)
print(c)
print('-------------------------')
test(1,2,3)
# output :
1
2
3
---------------------------------
So we now know function definitions with positional as well as keyword arguments.
Now let us study the '*' operator and '**' operator.
Please note these operators can be used in 2 areas:
a) function call
b) function definition
The use of '*' operator and '**' operator in function call.
Let us get straight to an example and then discuss it.
def sum(a,b): #receive args from function calls as sum(1,2) or sum(a=1,b=2)
print(a+b)
my_tuple = (1,2)
my_list = [1,2]
my_dict = {'a':1,'b':2}
# Let us unpack data structure of list or tuple or dict into arguments with help of '*' operator
sum(*my_tuple) # becomes same as sum(1,2) after unpacking my_tuple with '*'
sum(*my_list) # becomes same as sum(1,2) after unpacking my_list with '*'
sum(**my_dict) # becomes same as sum(a=1,b=2) after unpacking by '**'
# output is 3 in all three calls to sum function.
So remember
when the '*' or '**' operator is used in a function call -
'*' operator unpacks data structure such as a list or tuple into arguments needed by function definition.
'**' operator unpacks a dictionary into arguments needed by function definition.
Now let us study the '*' operator use in function definition. Example:
def sum(*args): #pack the received positional args into data structure of tuple. after applying '*' - def sum((1,2,3,4))
sum = 0
for a in args:
sum+=a
print(sum)
sum(1,2,3,4) #positional args sent to function sum
#output:
10
In function definition the '*' operator packs the received arguments into a tuple.
Now let us see an example of '**' used in function definition:
def sum(**args): #pack keyword args into datastructure of dict after applying '**' - def sum({a:1,b:2,c:3,d:4})
sum=0
for k,v in args.items():
sum+=v
print(sum)
sum(a=1,b=2,c=3,d=4) #positional args sent to function sum
In function definition The '**' operator packs the received arguments into a dictionary.
So remember:
In a function call the '*' unpacks data structure of tuple or list into positional or keyword arguments to be received by function definition.
In a function call the '**' unpacks data structure of dictionary into positional or keyword arguments to be received by function definition.
In a function definition the '*' packs positional arguments into a tuple.
In a function definition the '**' packs keyword arguments into a dictionary.
回答6:
This table is handy for using * and ** in function construction and function call:
In function construction In function call
=======================================================================
| def f(*args): | def f(a, b):
*args | for arg in args: | return a + b
| print(arg) | args = (1, 2)
| f(1, 2) | f(*args)
----------|--------------------------------|---------------------------
| def f(a, b): | def f(a, b):
**kwargs | return a + b | return a + b
| def g(**kwargs): | kwargs = dict(a=1, b=2)
| return f(**kwargs) | f(**kwargs)
| g(a=1, b=2) |
-----------------------------------------------------------------------
This really just serves to summarize Lorin Hochstein's answer but I find it helpful.
Relatedly: uses for the star/splat operators have been expanded in Python 3
回答7:
* and ** have special usage in the function argument list. *
implies that the argument is a list and ** implies that the argument
is a dictionary. This allows functions to take arbitrary number of
arguments
回答8:
For those of you who learn by examples!
- The purpose of
*is to give you the ability to define a function that can take an arbitrary number of arguments provided as a list (e.g.f(*myList)). - The purpose of
**is to give you the ability to feed a function's arguments by providing a dictionary (e.g.f(**{'x' : 1, 'y' : 2})).
Let us show this by defining a function that takes two normal variables x, y, and can accept more arguments as myArgs, and can accept even more arguments as myKW. Later, we will show how to feed y using myArgDict.
def f(x, y, *myArgs, **myKW):
print("# x = {}".format(x))
print("# y = {}".format(y))
print("# myArgs = {}".format(myArgs))
print("# myKW = {}".format(myKW))
print("# ----------------------------------------------------------------------")
# Define a list for demonstration purposes
myList = ["Left", "Right", "Up", "Down"]
# Define a dictionary for demonstration purposes
myDict = {"Wubba": "lubba", "Dub": "dub"}
# Define a dictionary to feed y
myArgDict = {'y': "Why?", 'y0': "Why not?", "q": "Here is a cue!"}
# The 1st elem of myList feeds y
f("myEx", *myList, **myDict)
# x = myEx
# y = Left
# myArgs = ('Right', 'Up', 'Down')
# myKW = {'Wubba': 'lubba', 'Dub': 'dub'}
# ----------------------------------------------------------------------
# y is matched and fed first
# The rest of myArgDict becomes additional arguments feeding myKW
f("myEx", **myArgDict)
# x = myEx
# y = Why?
# myArgs = ()
# myKW = {'y0': 'Why not?', 'q': 'Here is a cue!'}
# ----------------------------------------------------------------------
# The rest of myArgDict becomes additional arguments feeding myArgs
f("myEx", *myArgDict)
# x = myEx
# y = y
# myArgs = ('y0', 'q')
# myKW = {}
# ----------------------------------------------------------------------
# Feed extra arguments manually and append even more from my list
f("myEx", 4, 42, 420, *myList, *myDict, **myDict)
# x = myEx
# y = 4
# myArgs = (42, 420, 'Left', 'Right', 'Up', 'Down', 'Wubba', 'Dub')
# myKW = {'Wubba': 'lubba', 'Dub': 'dub'}
# ----------------------------------------------------------------------
# Without the stars, the entire provided list and dict become x, and y:
f(myList, myDict)
# x = ['Left', 'Right', 'Up', 'Down']
# y = {'Wubba': 'lubba', 'Dub': 'dub'}
# myArgs = ()
# myKW = {}
# ----------------------------------------------------------------------
Caveats
**is exclusively reserved for dictionaries.- Non-optional argument assignment happens first.
- You cannot use a non-optional argument twice.
- If applicable,
**must come after*, always.
回答9:
From the Python documentation:
If there are more positional arguments than there are formal parameter slots, a TypeError exception is raised, unless a formal parameter using the syntax "*identifier" is present; in this case, that formal parameter receives a tuple containing the excess positional arguments (or an empty tuple if there were no excess positional arguments).
If any keyword argument does not correspond to a formal parameter name, a TypeError exception is raised, unless a formal parameter using the syntax "**identifier" is present; in this case, that formal parameter receives a dictionary containing the excess keyword arguments (using the keywords as keys and the argument values as corresponding values), or a (new) empty dictionary if there were no excess keyword arguments.
回答10:
I want to give an example which others haven't mentioned
* can also unpack a generator
An example from Python3 Document
x = [1, 2, 3]
y = [4, 5, 6]
unzip_x, unzip_y = zip(*zip(x, y))
unzip_x will be [1, 2, 3], unzip_y will be [4, 5, 6]
The zip() receives multiple iretable args, and return a generator.
zip(*zip(x,y)) -> zip((1, 4), (2, 5), (3, 6))
回答11:
* means receive variable arguments as tuple
** means receive variable arguments as dictionary
Used like the following:
1) single *
def foo(*args):
for arg in args:
print(arg)
foo("two", 3)
Output:
two
3
2) Now **
def bar(**kwargs):
for key in kwargs:
print(key, kwargs[key])
bar(dic1="two", dic2=3)
Output:
dic1 two
dic2 3
回答12:
In Python 3.5, you can also use this syntax in list, dict, tuple, and set displays (also sometimes called literals). See PEP 488: Additional Unpacking Generalizations.
>>> (0, *range(1, 4), 5, *range(6, 8))
(0, 1, 2, 3, 5, 6, 7)
>>> [0, *range(1, 4), 5, *range(6, 8)]
[0, 1, 2, 3, 5, 6, 7]
>>> {0, *range(1, 4), 5, *range(6, 8)}
{0, 1, 2, 3, 5, 6, 7}
>>> d = {'one': 1, 'two': 2, 'three': 3}
>>> e = {'six': 6, 'seven': 7}
>>> {'zero': 0, **d, 'five': 5, **e}
{'five': 5, 'seven': 7, 'two': 2, 'one': 1, 'three': 3, 'six': 6, 'zero': 0}
It also allows multiple iterables to be unpacked in a single function call.
>>> range(*[1, 10], *[2])
range(1, 10, 2)
(Thanks to mgilson for the PEP link.)
回答13:
In addition to function calls, *args and **kwargs are useful in class hierarchies and also avoid having to write __init__ method in Python. Similar usage can seen in frameworks like Django code.
For example,
def __init__(self, *args, **kwargs):
for attribute_name, value in zip(self._expected_attributes, args):
setattr(self, attribute_name, value)
if kwargs.has_key(attribute_name):
kwargs.pop(attribute_name)
for attribute_name in kwargs.viewkeys():
setattr(self, attribute_name, kwargs[attribute_name])
A subclass can then be
class RetailItem(Item):
_expected_attributes = Item._expected_attributes + ['name', 'price', 'category', 'country_of_origin']
class FoodItem(RetailItem):
_expected_attributes = RetailItem._expected_attributes + ['expiry_date']
The subclass then be instantiated as
food_item = FoodItem(name = 'Jam',
price = 12.0,
category = 'Foods',
country_of_origin = 'US',
expiry_date = datetime.datetime.now())
Also, a subclass with a new attribute which makes sense only to that subclass instance can call the Base class __init__ to offload the attributes setting.
This is done through *args and **kwargs. kwargs mainly used so that code is readable using named arguments. For example,
class ElectronicAccessories(RetailItem):
_expected_attributes = RetailItem._expected_attributes + ['specifications']
# Depend on args and kwargs to populate the data as needed.
def __init__(self, specifications = None, *args, **kwargs):
self.specifications = specifications # Rest of attributes will make sense to parent class.
super(ElectronicAccessories, self).__init__(*args, **kwargs)
which can be instatiated as
usb_key = ElectronicAccessories(name = 'Sandisk',
price = '$6.00',
category = 'Electronics',
country_of_origin = 'CN',
specifications = '4GB USB 2.0/USB 3.0')
The complete code is here
回答14:
*args and **kwargs: allow you to pass a variable number of arguments to a function.
*args: is used to send a non-keyworded variable length argument list to the function:
def args(normal_arg, *argv):
print("normal argument:", normal_arg)
for arg in argv:
print("Argument in list of arguments from *argv:", arg)
args('animals', 'fish', 'duck', 'bird')
Will produce:
normal argument: animals
Argument in list of arguments from *argv: fish
Argument in list of arguments from *argv: duck
Argument in list of arguments from *argv: bird
**kwargs*
**kwargs allows you to pass keyworded variable length of arguments to a function. You should use **kwargs if you want to handle named arguments in a function.
def who(**kwargs):
if kwargs is not None:
for key, value in kwargs.items():
print("Your %s is %s." % (key, value))
who(name="Nikola", last_name="Tesla", birthday="7.10.1856", birthplace="Croatia")
Will produce:
Your name is Nikola.
Your last_name is Tesla.
Your birthday is 7.10.1856.
Your birthplace is Croatia.
回答15:
This example would help you remember *args, **kwargs and even super and inheritance in Python at once.
class base(object):
def __init__(self, base_param):
self.base_param = base_param
class child1(base): # inherited from base class
def __init__(self, child_param, *args) # *args for non-keyword args
self.child_param = child_param
super(child1, self).__init__(*args) # call __init__ of the base class and initialize it with a NON-KEYWORD arg
class child2(base):
def __init__(self, child_param, **kwargs):
self.child_param = child_param
super(child2, self).__init__(**kwargs) # call __init__ of the base class and initialize it with a KEYWORD arg
c1 = child1(1,0)
c2 = child2(1,base_param=0)
print c1.base_param # 0
print c1.child_param # 1
print c2.base_param # 0
print c2.child_param # 1
回答16:
Building on nickd's answer...
def foo(param1, *param2):
print(param1)
print(param2)
def bar(param1, **param2):
print(param1)
print(param2)
def three_params(param1, *param2, **param3):
print(param1)
print(param2)
print(param3)
print(foo(1, 2, 3, 4, 5))
print("\n")
print(bar(1, a=2, b=3))
print("\n")
print(three_params(1, 2, 3, 4, s=5))
Output:
1
(2, 3, 4, 5)
1
{'a': 2, 'b': 3}
1
(2, 3, 4)
{'s': 5}
Basically, any number of positional arguments can use *args and any named arguments (or kwargs aka keyword arguments) can use **kwargs.
回答17:
A good example of using both in a function is:
>>> def foo(*arg,**kwargs):
... print arg
... print kwargs
>>>
>>> a = (1, 2, 3)
>>> b = {'aa': 11, 'bb': 22}
>>>
>>>
>>> foo(*a,**b)
(1, 2, 3)
{'aa': 11, 'bb': 22}
>>>
>>>
>>> foo(a,**b)
((1, 2, 3),)
{'aa': 11, 'bb': 22}
>>>
>>>
>>> foo(a,b)
((1, 2, 3), {'aa': 11, 'bb': 22})
{}
>>>
>>>
>>> foo(a,*b)
((1, 2, 3), 'aa', 'bb')
{}
回答18:
TL;DR
It packs arguments passed to the function into list and dict respectively inside the function body. When you define a function signature like this:
def func(*args, **kwds):
# do stuff
it can be called with any number of arguments and keyword arguments. The non-keyword arguments get packed into a list called args inside the the function body and the keyword arguments get packed into a dict called kwds inside the function body.
func("this", "is a list of", "non-keyowrd", "arguments", keyword="ligma", options=[1,2,3])
now inside the function body, when the function is called, there are two local variables, args which is a list having value ["this", "is a list of", "non-keyword", "arguments"] and kwds which is a dict having value {"keyword" : "ligma", "options" : [1,2,3]}
This also works in reverse, i.e. from the caller side. for example if you have a function defined as:
def f(a, b, c, d=1, e=10):
# do stuff
you can call it with by unpacking iterables or mappings you have in the calling scope:
iterable = [1, 20, 500]
mapping = {"d" : 100, "e": 3}
f(*iterable, **mapping)
# That call is equivalent to
f(1, 20, 500, d=100, e=3)
回答19:
Context
- python 3.x
- unpacking with
** - use with string formatting
Use with string formatting
In addition to the answers in this thread, here is another detail that was not mentioned elsewhere. This expands on the answer by Brad Solomon
Unpacking with ** is also useful when using python str.format.
This is somewhat similar to what you can do with python f-strings f-string but with the added overhead of declaring a dict to hold the variables (f-string does not require a dict).
Quick Example
## init vars
ddvars = dict()
ddcalc = dict()
pass
ddvars['fname'] = 'Huomer'
ddvars['lname'] = 'Huimpson'
ddvars['motto'] = 'I love donuts!'
ddvars['age'] = 33
pass
ddcalc['ydiff'] = 5
ddcalc['ycalc'] = ddvars['age'] + ddcalc['ydiff']
pass
vdemo = []
## ********************
## single unpack supported in py 2.7
vdemo.append('''
Hello {fname} {lname}!
Today you are {age} years old!
We love your motto "{motto}" and we agree with you!
'''.format(**ddvars))
pass
## ********************
## multiple unpack supported in py 3.x
vdemo.append('''
Hello {fname} {lname}!
In {ydiff} years you will be {ycalc} years old!
'''.format(**ddvars,**ddcalc))
pass
## ********************
print(vdemo[-1])
回答20:
TL;DR
Below are 6 different use cases for * and ** in python programming:
- To accept any number of positional arguments using
*args:def foo(*args): pass, herefooaccepts any number of positional arguments, i. e., the following calls are validfoo(1),foo(1, 'bar') - To accept any number of keyword arguments using
**kwargs:def foo(**kwargs): pass, here 'foo' accepts any number of keyword arguments, i. e., the following calls are validfoo(name='Tom'),foo(name='Tom', age=33) - To accept any number of positional and keyword arguments using
*args, **kwargs:def foo(*args, **kwargs): pass, herefooaccepts any number of positional and keyword arguments, i. e., the following calls are validfoo(1,name='Tom'),foo(1, 'bar', name='Tom', age=33) - To enforce keyword only arguments using
*:def foo(pos1, pos2, *, kwarg1): pass, here*means that foo only accept keyword arguments after pos2, hencefoo(1, 2, 3)raises TypeError butfoo(1, 2, kwarg1=3)is ok. - To express no further interest in more positional arguments using
*_(Note: this is a convention only):def foo(bar, baz, *_): passmeans (by convention)fooonly usesbarandbazarguments in its working and will ignore others. - To express no further interest in more keyword arguments using
\**_(Note: this is a convention only):def foo(bar, baz, **_): passmeans (by convention)fooonly usesbarandbazarguments in its working and will ignore others.
BONUS: From python 3.8 onward, one can use / in function definition to enforce positional only parameters. In the following example, parameters a and b are positional-only, while c or d can be positional or keyword, and e or f are required to be keywords:
def f(a, b, /, c, d, *, e, f):
pass
回答21:
def foo(param1, *param2):is a method can accept arbitrary number of values for*param2,def bar(param1, **param2):is a method can accept arbitrary number of values with keys for*param2param1is a simple parameter.
For example, the syntax for implementing varargs in Java as follows:
accessModifier methodName(datatype… arg) {
// method body
}
