I can set Request.Content-Type = ... , Request.Content-Length = ...
How to set Accept and Accept-Language?
I want to upload a file (RFC 1867) and need to create a request like this:
POST /test-upload.php.xml HTTP/1.1
Host: example.com
User-Agent: Mozilla/5.0 (Windows NT 5.2; WOW64; rv:2.0.1) Gecko/20100101 Firefox/4.0.1
Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8
Accept-Language: tr-tr,tr;q=0.8,en-us;q=0.5,en;q=0.3
Accept-Encoding: gzip, deflate
Accept-Charset: ISO-8859-9,utf-8;q=0.7,*;q=0.7
Keep-Alive: 115
Connection: keep-alive
Content-Type: multipart/form-data; boundary=---------------------------21724139663430
Content-Length: 56048
Take a look at Accept property:
HttpWebRequest myHttpWebRequest=(HttpWebRequest)WebRequest.Create(myUri);
myHttpWebRequest.Accept="image/*";
HttpWebResponse myHttpWebResponse=
(HttpWebResponse)myHttpWebRequest.GetResponse();
This MSDN article shows how to add custom headers to your request:
//Get the headers associated with the request.
WebHeaderCollection myWebHeaderCollection = myHttpWebRequest.Headers;
//Add the Accept-Language header (for Danish) in the request.
myWebHeaderCollection.Add("Accept-Language:da");
//Include English in the Accept-Langauge header.
myWebHeaderCollection.Add("Accept-Language","en;q=0.8");
You need to be sure that you type cast the request to (HttpWebRequest), where the accept header property is available.
In the old WebRequest class, the Accept header is not accessible.
When you want to set the Accept type and content type, just cast the webrequest to HttpwebRequest
var webreq= (HttpWebRequest)WebRequest.Create(requestUri);
webreq.Method = "POST";
webreq.Accept = "application/json";
webreq.ContentType = "application/json";
I have to confirm after several annoying attempts to use the headers that the
myWebHeaderCollection.Add("foo","bar");
solution works perfectly.
if you want to set the Language.
myWebHeaderCollection.Add("AcceptCharset", "ISO-8859-1,utf-8;q=0.7,*;q=0.7");
myWebHeaderCollection.Add("TransferEncoding", "gzip,deflate");
Does not set the values however. Which may seem like a logical conclusion given the first one works.
If you are using HttpRequestMessage, set the header using Headers.Add method. In your case :
request.Headers.Add("Accept", "text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8");