How do you use math.random to generate random ints

2019-01-18 11:53发布

问题:

How do you use Math.random to generate random ints?

My code is:

int abc= (Math.random()*100);
System.out.println(abc);

All it prints out is 0, how can I fix this?

回答1:

Cast abc to an integer.

(int)(Math.random()*100);


回答2:

For your code to compile you need to cast the result to an int.

int abc = (int) (Math.random() * 100);

However, if you instead use the java.util.Random class it has built in method for you

Random random = new Random();
int abc = random.nextInt(100);


回答3:

As an alternative, if there's not a specific reason to use Math.random(), use Random.nextInt():

Random rnd = new Random();
int abc = rnd.nextInt(100); // +1 if you want 1-100, otherwise will be 0-99.


回答4:

int abc= (Math.random()*100);//  wrong 

you wil get below error message

Exception in thread "main" java.lang.Error: Unresolved compilation problem: Type mismatch: cannot convert from double to int

int abc= (int) (Math.random()*100);// add "(int)" data type

,known as type casting

if the true result is

int abc= (int) (Math.random()*1)=0.027475

Then you will get output as "0" because it is a integer data type.

int abc= (int) (Math.random()*100)=0.02745

output:2 because (100*0.02745=2.7456...etc)



回答5:

You can also use this way for getting random number between 1 and 100 as:

SecureRandom src=new SecureRandom();
int random=1 + src.nextInt(100);


回答6:

you are importing java.util package. That's why its giving error. there is a random() in java.util package too. Please remove the import statement importing java.util package. then your program will use random() method for java.lang by default and then your program will work. remember to cast it i.e

int x = (int)(Math.random()*100);


回答7:

double  i = 2+Math.random()*100;
int j = (int)i;
System.out.print(j);


标签: java random