如何不使用进行左外连接在C＃中的LINQ to对象join-on-equals-into条款？ 有没有办法做到这一点与where的条款？ 正确的问题：对于内部联接是容易的，我有这样的一个解决方案
List<JoinPair> innerFinal = (from l in lefts from r in rights where l.Key == r.Key
select new JoinPair { LeftId = l.Id, RightId = r.Id})
但对于左外连接我需要一个解决方案。 我的是这样的事情，但它不工作
List< JoinPair> leftFinal = (from l in lefts from r in rights
select new JoinPair {
LeftId = l.Id,
RightId = ((l.Key==r.Key) ? r.Id : 0
})
其中JoinPair是一个类：
public class JoinPair { long leftId; long rightId; }
Answer 1:
如前所述上：
101个LINQ示例- LEFT OUTER JOIN
var q =
from c in categories
join p in products on c.Category equals p.Category into ps
from p in ps.DefaultIfEmpty()
select new { Category = c, ProductName = p == null ? "(No products)" : p.ProductName };
Answer 2:
如果使用一个数据库驱动LINQ提供商，显著更可读的左外联接可被写为这样：
from maintable in Repo.T_Whatever
from xxx in Repo.T_ANY_TABLE.Where(join condition).DefaultIfEmpty()
如果省略DefaultIfEmpty()你将有一个内部联接。
以接受的答案：
from c in categories
join p in products on c equals p.Category into ps
from p in ps.DefaultIfEmpty()
这句法非常混乱，而且目前还不清楚它是如何工作，当你想左连接多个表。
注意
应当指出的是， from alias in Repo.whatever.Where(condition).DefaultIfEmpty()是相同的外，应用/左加入外侧，其任何（体面）数据库的优化是完全能够翻译成的左连接，只要你不引入每行值（又名实际外适用）。 不要在LINQ的-2-对象做到这一点（因为有当您使用LINQ到对象没有DB-优化）。
详细示例
var query2 = (
from users in Repo.T_User
from mappings in Repo.T_User_Group
.Where(mapping => mapping.USRGRP_USR == users.USR_ID)
.DefaultIfEmpty() // <== makes join left join
from groups in Repo.T_Group
.Where(gruppe => gruppe.GRP_ID == mappings.USRGRP_GRP)
.DefaultIfEmpty() // <== makes join left join
// where users.USR_Name.Contains(keyword)
// || mappings.USRGRP_USR.Equals(666)
// || mappings.USRGRP_USR == 666
// || groups.Name.Contains(keyword)
select new
{
UserId = users.USR_ID
,UserName = users.USR_User
,UserGroupId = groups.ID
,GroupName = groups.Name
}
);
var xy = (query2).ToList();
当使用LINQ 2 SQL中，它将很好地转化为以下非常清晰的SQL查询：
SELECT
users.USR_ID AS UserId
,users.USR_User AS UserName
,groups.ID AS UserGroupId
,groups.Name AS GroupName
FROM T_User AS users
LEFT JOIN T_User_Group AS mappings
ON mappings.USRGRP_USR = users.USR_ID
LEFT JOIN T_Group AS groups
ON groups.GRP_ID == mappings.USRGRP_GRP
编辑：
另请参见“ 转换的SQL Server查询Linq查询 ”用于更复杂的例子。
另外，如果你在LINQ的-2-对象做这件事（而不是LINQ的-2-SQL），你应该这样做老式的方式（因为LINQ to SQL的将这种正确的加盟业务，但在反对这种方法部队全面扫描，并没有充分利用索引搜索，whyever ...）：
var query2 = (
from users in Repo.T_Benutzer
join mappings in Repo.T_Benutzer_Benutzergruppen on mappings.BEBG_BE equals users.BE_ID into tmpMapp
join groups in Repo.T_Benutzergruppen on groups.ID equals mappings.BEBG_BG into tmpGroups
from mappings in tmpMapp.DefaultIfEmpty()
from groups in tmpGroups.DefaultIfEmpty()
select new
{
UserId = users.BE_ID
,UserName = users.BE_User
,UserGroupId = mappings.BEBG_BG
,GroupName = groups.Name
}
);
Answer 3:
使用lambda表达式
db.Categories
.GroupJoin(
db.Products,
Category => Category.CategoryId,
Product => Product.CategoryId,
(x, y) => new { Category = x, Products = y })
.SelectMany(
xy => xy.Products.DefaultIfEmpty(),
(x, y) => new { Category = x.Category, Product = y })
.Select(s => new
{
CategoryName = s.Category.Name,
ProductName = s.Product.Name
})
Answer 4:
看看这个例子 。 该查询应该工作：
var leftFinal = from left in lefts
join right in rights on left equals right.Left into leftRights
from leftRight in leftRights.DefaultIfEmpty()
select new { LeftId = left.Id, RightId = left.Key==leftRight.Key ? leftRight.Id : 0 };
Answer 5:
现在，作为一个扩展的方法：
public static class LinqExt
{
public static IEnumerable<TResult> LeftOuterJoin<TLeft, TRight, TKey, TResult>(this IEnumerable<TLeft> left, IEnumerable<TRight> right, Func<TLeft, TKey> leftKey, Func<TRight, TKey> rightKey,
Func<TLeft, TRight, TResult> result)
{
return left.GroupJoin(right, leftKey, rightKey, (l, r) => new { l, r })
.SelectMany(
o => o.r.DefaultIfEmpty(),
(l, r) => new { lft= l.l, rght = r })
.Select(o => result.Invoke(o.lft, o.rght));
}
}
就像你使用通常会使用连接：
var contents = list.LeftOuterJoin(list2,
l => l.country,
r => r.name,
(l, r) => new { count = l.Count(), l.country, l.reason, r.people })
希望这可以节省一些时间。
Answer 6:
左外的实现通过扩展方法可能看起来像参加
public static IEnumerable<Result> LeftJoin<TOuter, TInner, TKey, Result>(
this IEnumerable<TOuter> outer, IEnumerable<TInner> inner
, Func<TOuter, TKey> outerKeySelector, Func<TInner, TKey> innerKeySelector
, Func<TOuter, TInner, Result> resultSelector, IEqualityComparer<TKey> comparer)
{
if (outer == null)
throw new ArgumentException("outer");
if (inner == null)
throw new ArgumentException("inner");
if (outerKeySelector == null)
throw new ArgumentException("outerKeySelector");
if (innerKeySelector == null)
throw new ArgumentException("innerKeySelector");
if (resultSelector == null)
throw new ArgumentException("resultSelector");
return LeftJoinImpl(outer, inner, outerKeySelector, innerKeySelector, resultSelector, comparer ?? EqualityComparer<TKey>.Default);
}
static IEnumerable<Result> LeftJoinImpl<TOuter, TInner, TKey, Result>(
IEnumerable<TOuter> outer, IEnumerable<TInner> inner
, Func<TOuter, TKey> outerKeySelector, Func<TInner, TKey> innerKeySelector
, Func<TOuter, TInner, Result> resultSelector, IEqualityComparer<TKey> comparer)
{
var innerLookup = inner.ToLookup(innerKeySelector, comparer);
foreach (var outerElment in outer)
{
var outerKey = outerKeySelector(outerElment);
var innerElements = innerLookup[outerKey];
if (innerElements.Any())
foreach (var innerElement in innerElements)
yield return resultSelector(outerElment, innerElement);
else
yield return resultSelector(outerElment, default(TInner));
}
}
该resultselector则必须采取零元素的照顾。 FX。
static void Main(string[] args)
{
var inner = new[] { Tuple.Create(1, "1"), Tuple.Create(2, "2"), Tuple.Create(3, "3") };
var outer = new[] { Tuple.Create(1, "11"), Tuple.Create(2, "22") };
var res = outer.LeftJoin(inner, item => item.Item1, item => item.Item1, (it1, it2) =>
new { Key = it1.Item1, V1 = it1.Item2, V2 = it2 != null ? it2.Item2 : default(string) });
foreach (var item in res)
Console.WriteLine(string.Format("{0}, {1}, {2}", item.Key, item.V1, item.V2));
}
Answer 7:
采取看看这个例子
class Person
{
public int ID { get; set; }
public string FirstName { get; set; }
public string LastName { get; set; }
public string Phone { get; set; }
}
class Pet
{
public string Name { get; set; }
public Person Owner { get; set; }
}
public static void LeftOuterJoinExample()
{
Person magnus = new Person {ID = 1, FirstName = "Magnus", LastName = "Hedlund"};
Person terry = new Person {ID = 2, FirstName = "Terry", LastName = "Adams"};
Person charlotte = new Person {ID = 3, FirstName = "Charlotte", LastName = "Weiss"};
Person arlene = new Person {ID = 4, FirstName = "Arlene", LastName = "Huff"};
Pet barley = new Pet {Name = "Barley", Owner = terry};
Pet boots = new Pet {Name = "Boots", Owner = terry};
Pet whiskers = new Pet {Name = "Whiskers", Owner = charlotte};
Pet bluemoon = new Pet {Name = "Blue Moon", Owner = terry};
Pet daisy = new Pet {Name = "Daisy", Owner = magnus};
// Create two lists.
List<Person> people = new List<Person> {magnus, terry, charlotte, arlene};
List<Pet> pets = new List<Pet> {barley, boots, whiskers, bluemoon, daisy};
var query = from person in people
where person.ID == 4
join pet in pets on person equals pet.Owner into personpets
from petOrNull in personpets.DefaultIfEmpty()
select new { Person=person, Pet = petOrNull};
foreach (var v in query )
{
Console.WriteLine("{0,-15}{1}", v.Person.FirstName + ":", (v.Pet == null ? "Does not Exist" : v.Pet.Name));
}
}
// This code produces the following output:
//
// Magnus: Daisy
// Terry: Barley
// Terry: Boots
// Terry: Blue Moon
// Charlotte: Whiskers
// Arlene:
现在你可以include elements from the left ，即使该元素has no matches in the right ，对我们来说，我们retrived Arlene即使他在右侧没有匹配
这里是参考
如何执行左外连接（C＃编程指南）
Answer 8:
这是一般形式（如已经在其他的答案中提供）
var c =
from a in alpha
join b in beta on b.field1 equals a.field1 into b_temp
from b_value in b_temp.DefaultIfEmpty()
select new { Alpha = a, Beta = b_value };
然而这里的，我希望能澄清一下这实际上意味着一个解释！
join b in beta on b.field1 equals a.field1 into b_temp
本质上创建一个单独的结果集b_temp其有效地包括（在“B”的条目），用于在右手侧的条目为空“行”。
然后下一行：
from b_value in b_temp.DefaultIfEmpty()
..iterates在该结果集，在右侧的“行”设置默认为空值，并设置右边行的结果连接到“b_value”（即值的值在右边右手边，如果有匹配的记录，或“空”如果不存在）。
现在，如果右手边是一个单独的LINQ查询的结果，它会由匿名类型，只能或者是“东西”或“空”的。 如果它是一个然而枚举（如清单 - 其中MyObjectB是2场的一类），那么它可能是具体的关于“空”值，使用什么默认为它的属性：
var c =
from a in alpha
join b in beta on b.field1 equals a.field1 into b_temp
from b_value in b_temp.DefaultIfEmpty( new MyObjectB { Field1 = String.Empty, Field2 = (DateTime?) null })
select new { Alpha = a, Beta_field1 = b_value.Field1, Beta_field2 = b_value.Field2 };
这确保了“B”本身不是空（但其属性可以为空，使用您所指定的默认空值），这可以让你检查b_value的性质没有得到对b_value一个空引用异常。 需要注意的是可为空值的日期时间，类型（的DateTime？），即“为空的日期时间”必须指定为规范的“DefaultIfEmpty”的空的“类型”（这也适用于不属于“本地类型'可为空的例如双，浮动）。
您可以执行多个左外部通过简单的链接上面的语法联接。
Answer 9:
举个例子，如果你需要连接超过2个表：
from d in context.dc_tpatient_bookingd
join bookingm in context.dc_tpatient_bookingm
on d.bookingid equals bookingm.bookingid into bookingmGroup
from m in bookingmGroup.DefaultIfEmpty()
join patient in dc_tpatient
on m.prid equals patient.prid into patientGroup
from p in patientGroup.DefaultIfEmpty()
参考： https://stackoverflow.com/a/17142392/2343
Answer 10:
有三个表：个人，学校和persons_schools，连接人员，他们在研究学校使用id = 6人的引用是表persons_schools缺席。 然而使用id = 6中的人结果呈现LEF接网格。
List<Person> persons = new List<Person>
{
new Person { id = 1, name = "Alex", phone = "4235234" },
new Person { id = 2, name = "Bob", phone = "0014352" },
new Person { id = 3, name = "Sam", phone = "1345" },
new Person { id = 4, name = "Den", phone = "3453452" },
new Person { id = 5, name = "Alen", phone = "0353012" },
new Person { id = 6, name = "Simon", phone = "0353012" }
};
List<School> schools = new List<School>
{
new School { id = 1, name = "Saint. John's school"},
new School { id = 2, name = "Public School 200"},
new School { id = 3, name = "Public School 203"}
};
List<PersonSchool> persons_schools = new List<PersonSchool>
{
new PersonSchool{id_person = 1, id_school = 1},
new PersonSchool{id_person = 2, id_school = 2},
new PersonSchool{id_person = 3, id_school = 3},
new PersonSchool{id_person = 4, id_school = 1},
new PersonSchool{id_person = 5, id_school = 2}
//a relation to the person with id=6 is absent
};
var query = from person in persons
join person_school in persons_schools on person.id equals person_school.id_person
into persons_schools_joined
from person_school_joined in persons_schools_joined.DefaultIfEmpty()
from school in schools.Where(var_school => person_school_joined == null ? false : var_school.id == person_school_joined.id_school).DefaultIfEmpty()
select new { Person = person.name, School = school == null ? String.Empty : school.name };
foreach (var elem in query)
{
System.Console.WriteLine("{0},{1}", elem.Person, elem.School);
}
Answer 11:
这就像左拓法加入语法加盟
public static class LinQExtensions
{
public static IEnumerable<TResult> LeftJoin<TOuter, TInner, TKey, TResult>(
this IEnumerable<TOuter> outer, IEnumerable<TInner> inner,
Func<TOuter, TKey> outerKeySelector,
Func<TInner, TKey> innerKeySelector,
Func<TOuter, TInner, TResult> resultSelector)
{
return outer.GroupJoin(
inner,
outerKeySelector,
innerKeySelector,
(outerElement, innerElements) => resultSelector(outerElement, innerElements.FirstOrDefault()));
}
}
只是写它.NET的核心，它似乎可以按预期工作。
小测试：
var Ids = new List<int> { 1, 2, 3, 4};
var items = new List<Tuple<int, string>>
{
new Tuple<int, string>(1,"a"),
new Tuple<int, string>(2,"b"),
new Tuple<int, string>(4,"d"),
new Tuple<int, string>(5,"e"),
};
var result = Ids.LeftJoin(
items,
id => id,
item => item.Item1,
(id, item) => item ?? new Tuple<int, string>(id, "not found"));
result.ToList()
Count = 4
[0]: {(1, a)}
[1]: {(2, b)}
[2]: {(3, not found)}
[3]: {(4, d)}
Answer 12:
这是一个SQL语法比较LINQ语法内，左外连接。 左外连接：
http://www.ozkary.com/2011/07/linq-to-entity-inner-and-left-joins.html
“下面的例子做的产品和类别组加入，这基本上是左连接。在进入表达式返回即使类别表是空的数据。要访问类别表的属性，我们现在必须从枚举结果选择在catList.DefaultIfEmpty（）语句从CL加入。
Answer 13:
执行左外LINQ在C＃中加入//执行左外连接
class Person
{
public string FirstName { get; set; }
public string LastName { get; set; }
}
class Child
{
public string Name { get; set; }
public Person Owner { get; set; }
}
public class JoinTest
{
public static void LeftOuterJoinExample()
{
Person magnus = new Person { FirstName = "Magnus", LastName = "Hedlund" };
Person terry = new Person { FirstName = "Terry", LastName = "Adams" };
Person charlotte = new Person { FirstName = "Charlotte", LastName = "Weiss" };
Person arlene = new Person { FirstName = "Arlene", LastName = "Huff" };
Child barley = new Child { Name = "Barley", Owner = terry };
Child boots = new Child { Name = "Boots", Owner = terry };
Child whiskers = new Child { Name = "Whiskers", Owner = charlotte };
Child bluemoon = new Child { Name = "Blue Moon", Owner = terry };
Child daisy = new Child { Name = "Daisy", Owner = magnus };
// Create two lists.
List<Person> people = new List<Person> { magnus, terry, charlotte, arlene };
List<Child> childs = new List<Child> { barley, boots, whiskers, bluemoon, daisy };
var query = from person in people
join child in childs
on person equals child.Owner into gj
from subpet in gj.DefaultIfEmpty()
select new
{
person.FirstName,
ChildName = subpet!=null? subpet.Name:"No Child"
};
// PetName = subpet?.Name ?? String.Empty };
foreach (var v in query)
{
Console.WriteLine($"{v.FirstName + ":",-25}{v.ChildName}");
}
}
// This code produces the following output:
//
// Magnus: Daisy
// Terry: Barley
// Terry: Boots
// Terry: Blue Moon
// Charlotte: Whiskers
// Arlene: No Child
https://dotnetwithhamid.blogspot.in/
Answer 14:
If you need to join and filter on something, that can be done outside of the join. Filter can be done after creating the collection.
In this case if I do this in the join condition I reduce the rows that are returned.
Ternary condition is used (= n == null ? "__" : n.MonDayNote,)
If the object is null (so no match), then return what is after the ?. __, in this case.
Else, return what is after the :, n.MonDayNote.
Thanks to the other contributors that is where I started with my own issue.
var schedLocations = (from f in db.RAMS_REVENUE_LOCATIONS
join n in db.RAMS_LOCATION_PLANNED_MANNING on f.revenueCenterID equals
n.revenueCenterID into lm
from n in lm.DefaultIfEmpty()
join r in db.RAMS_LOCATION_SCHED_NOTE on f.revenueCenterID equals r.revenueCenterID
into locnotes
from r in locnotes.DefaultIfEmpty()
where f.LocID == nLocID && f.In_Use == true && f.revenueCenterID > 1000
orderby f.Areano ascending, f.Locname ascending
select new
{
Facname = f.Locname,
f.Areano,
f.revenueCenterID,
f.Locabbrev,
// MonNote = n == null ? "__" : n.MonDayNote,
MonNote = n == null ? "__" : n.MonDayNote,
TueNote = n == null ? "__" : n.TueDayNote,
WedNote = n == null ? "__" : n.WedDayNote,
ThuNote = n == null ? "__" : n.ThuDayNote,
FriNote = n == null ? "__" : n.FriDayNote,
SatNote = n == null ? "__" : n.SatDayNote,
SunNote = n == null ? "__" : n.SunDayNote,
MonEmpNbr = n == null ? 0 : n.MonEmpNbr,
TueEmpNbr = n == null ? 0 : n.TueEmpNbr,
WedEmpNbr = n == null ? 0 : n.WedEmpNbr,
ThuEmpNbr = n == null ? 0 : n.ThuEmpNbr,
FriEmpNbr = n == null ? 0 : n.FriEmpNbr,
SatEmpNbr = n == null ? 0 : n.SatEmpNbr,
SunEmpNbr = n == null ? 0 : n.SunEmpNbr,
SchedMondayDate = n == null ? dMon : n.MondaySchedDate,
LocNotes = r == null ? "Notes: N/A" : r.LocationNote
}).ToList();
Func<int, string> LambdaManning = (x) => { return x == 0 ? "" : "Manning:" + x.ToString(); };
DataTable dt_ScheduleMaster = PsuedoSchedule.Tables["ScheduleMasterWithNotes"];
var schedLocations2 = schedLocations.Where(x => x.SchedMondayDate == dMon);
Answer 15:
我想补充一点，如果你得到MoreLinq扩展有现在支持现在无论是同质和异质左联接
http://morelinq.github.io/2.8/ref/api/html/Overload_MoreLinq_MoreEnumerable_LeftJoin.htm
例：
//Pretend a ClientCompany object and an Employee object both have a ClientCompanyID key on them
return DataContext.ClientCompany
.LeftJoin(DataContext.Employees, //Table being joined
company => company.ClientCompanyID, //First key
employee => employee.ClientCompanyID, //Second Key
company => new {company, employee = (Employee)null}, //Result selector when there isn't a match
(company, employee) => new { company, employee }); //Result selector when there is a match
编辑：
现在回想起来，这可能工作，但它的IQueryable转化为一个IEnumerable作为morelinq不会将查询转换为SQL。
您可以改用群组加入如下所述： https://stackoverflow.com/a/24273804/4251433
这将确保它保持为一个IQueryable万一以后需要做进一步的逻辑运算。
Answer 16:
这是一个相当简单的使用方法语法来理解版本：
IEnumerable<JoinPair> outerLeft =
lefts.SelectMany(l =>
rights.Where(r => l.Key == r.Key)
.DefaultIfEmpty(new Item())
.Select(r => new JoinPair { LeftId = l.Id, RightId = r.Id }));
Answer 17:
(from a in db.Assignments
join b in db.Deliveryboys on a.AssignTo equals b.EmployeeId
//from d in eGroup.DefaultIfEmpty()
join c in db.Deliveryboys on a.DeliverTo equals c.EmployeeId into eGroup2
from e in eGroup2.DefaultIfEmpty()
where (a.Collected == false)
select new
{
OrderId = a.OrderId,
DeliveryBoyID = a.AssignTo,
AssignedBoyName = b.Name,
Assigndate = a.Assigndate,
Collected = a.Collected,
CollectedDate = a.CollectedDate,
CollectionBagNo = a.CollectionBagNo,
DeliverTo = e == null ? "Null" : e.Name,
DeliverDate = a.DeliverDate,
DeliverBagNo = a.DeliverBagNo,
Delivered = a.Delivered
});
Answer 18:
class Program
{
List<Employee> listOfEmp = new List<Employee>();
List<Department> listOfDepart = new List<Department>();
public Program()
{
listOfDepart = new List<Department>(){
new Department { Id = 1, DeptName = "DEV" },
new Department { Id = 2, DeptName = "QA" },
new Department { Id = 3, DeptName = "BUILD" },
new Department { Id = 4, DeptName = "SIT" }
};
listOfEmp = new List<Employee>(){
new Employee { Empid = 1, Name = "Manikandan",DepartmentId=1 },
new Employee { Empid = 2, Name = "Manoj" ,DepartmentId=1},
new Employee { Empid = 3, Name = "Yokesh" ,DepartmentId=0},
new Employee { Empid = 3, Name = "Purusotham",DepartmentId=0}
};
}
static void Main(string[] args)
{
Program ob = new Program();
ob.LeftJoin();
Console.ReadLine();
}
private void LeftJoin()
{
listOfEmp.GroupJoin(listOfDepart.DefaultIfEmpty(), x => x.DepartmentId, y => y.Id, (x, y) => new { EmpId = x.Empid, EmpName = x.Name, Dpt = y.FirstOrDefault() != null ? y.FirstOrDefault().DeptName : null }).ToList().ForEach
(z =>
{
Console.WriteLine("Empid:{0} EmpName:{1} Dept:{2}", z.EmpId, z.EmpName, z.Dpt);
});
}
}
class Employee
{
public int Empid { get; set; }
public string Name { get; set; }
public int DepartmentId { get; set; }
}
class Department
{
public int Id { get; set; }
public string DeptName { get; set; }
}
OUTPUT
Answer 19:
对于LEFT OUTER简单的解决方案JOIN：
var setA = context.SetA;
var setB = context.SetB.Select(st=>st.Id).Distinct().ToList();
var leftOuter = setA.Where(stA=> !setB.Contains(stA.Id));
注意事项 ：
- 为了提高性能组B可以被转换成词典 （如果做到这一点，那么你必须改变这一点：！setB.Contains（stA.Id））或一个HashSet
- 当有涉及到这可能是使用设置操作和实现一个类实现多个字段： 的IEqualityComparer
Answer 20:
简单的方法是用Let关键字。 这对我的作品。
from AItem in Db.A
Let BItem = Db.B.Where(x => x.id == AItem.id ).FirstOrDefault()
Where SomeCondition
Select new YourViewModel
{
X1 = AItem.a,
X2 = AItem.b,
X3 = BItem.c
}
这是左的模拟加入。 如果B中表中每个项目不匹配到项目，BItem返回NULL
文章来源: LEFT OUTER JOIN in LINQ
