解决与TypeTools泛型类型信息(Resolving generic type informat

在fromMap执行下面我想获得泛型类型的运行时类型T使用TypeTools但我坚持一个NullPointerException的TypeResolver.resolveRawArguments(MapperImpl.class, getClass()); 。

我怎样才能做到这一点？

Mapper.java：

import java.util.Map;

public interface Mapper<T extends Object, S extends Map<String, Object>> {
    public S toMap(T obj);
    public T fromMap(S map);
}

MapperImpl.java

import com.fasterxml.jackson.databind.ObjectMapper;
import java.util.Map;
import net.jodah.typetools.TypeResolver;

public class MapperImpl<T extends Object, S extends Map<String, Object>> 
    implements Mapper<T, S> {        

    public S toMap(T obj) {
        ObjectMapper objectMapper = new ObjectMapper();
        Map<String, Object> map = objectMapper.convertValue(obj, Map.class);
        return (S) map;
    }

    public T fromMap(S map) {
        ObjectMapper objectMapper = new ObjectMapper();

        Class<?>[] ts = TypeResolver.resolveRawArguments(MapperImpl.class, getClass());
        Class<T> classT =  (Class<T>) ts[0];

        T obj = objectMapper.convertValue(map, classT);

        return obj;
    }

Answer 1:

TypeTools，或在Java中的任何泛型类型的分辨率，总是需要的类型参数的类型定义被捕获。 你试图做会正常工作，只要MapperImpl的子类，这样的价值是什么T和S的类型定义被捕获。 例如：

public class FooMapper extends MapperImpl<Foo, ArrayList<String, Object>> {}

文章来源: Resolving generic type information with TypeTools