所以我想实现使用多个自动完成这种宝石和simple_form和我得到一个错误。
我尝试这样做：
<%= f.input_field :neighborhood_id, collection: Neighborhood.order(:name), :url => autocomplete_neighborhood_name_searches_path, :as => :autocomplete, 'data-delimiter' => ',', :multiple => true, :class => "span8" %>
这是我的错误：
undefined method `to_i' for ["Alley Park, Madison"]:Array
在我的参数，可以是在发送此neighborhood_id ：
"search"=>{"neighborhood_id"=>["Alley Park, Madison"],
因此，它甚至没有使用这些值的ID。
有没有人有什么想法？
编辑1：
为了响应@ jvnill的问题，我没有明确地做任何事情params[:search]在控制器中。 一个搜索创建了一个新的记录，并搜索listings 。
在我的搜索控制器， create行动，我只是这样做：
@search = Search.create!(params[:search])
然后我search.rb （即搜索模型）有这样的：
def listings
@listings ||= find_listings
end
private
def find_listings
key = "%#{keywords}%"
listings = Listing.order(:headline)
listings = listings.includes(:neighborhood).where("listings.headline like ? or neighborhoods.name like ?", key, key) if keywords.present?
listings = listings.where(neighborhood_id: neighborhood_id) if neighborhood_id.present?
#truncated for brevity
listings
end
首先，如果形式返回ID，而不是附近的名称，这将是更容易。 我没有使用过的宝石又是那么我不熟悉它是如何工作的。 阅读上的自述说，它会返回IDS，但我不知道为什么你只得到名称。 我敢肯定，一旦你弄清楚如何返回的ID，你就可以改变下面的代码，以适应这一点。
你需要一个邻里和搜索之间创建一个连接表。 让我们称之为search_neighborhoods。
rails g model search_neighborhood neighborhood_id:integer search_id:integer
# dont forget to add indexes in the migration
在这之后，你要设置你的模型。
# search.rb
has_many :search_neighborhoods
has_many :neighborhoods, through: :search_neighborhoods
# search_neighborhood.rb
belongs_to :search
belongs_to :neighborhood
# neighborhood.rb
has_many :search_neighborhoods
has_many :searches, through: :search_neighborhoods
现在，我们已经建立了关联，我们需要设置的制定者和属性
# search.rb
attr_accessible :neighborhood_names
# this will return a list of neighborhood names which is usefull with prepopulating
def neighborhood_names
neighborhoods.map(&:name).join(',')
end
# we will use this to find the ids of the neighborhoods given their names
# this will be called when you call create!
def neighborhood_names=(names)
names.split(',').each do |name|
next if name.blank?
if neighborhood = Neighborhood.find_by_name(name)
search_neighborhoods.build neighborhood_id: neighborhood.id
end
end
end
# view
# you need to change your autocomplete to use the getter method
<%= f.input :neighborhood_names, url: autocomplete_neighborhood_name_searches_path, as: :autocomplete, input_html: { data: { delimiter: ',', multiple: true, class: "span8" } %>
最后但并非最不重要的是更新find_listings
def find_listings
key = "%#{keywords}%"
listings = Listing.order(:headline).includes(:neighborhood)
if keywords.present?
listings = listings.where("listings.headline LIKE :key OR neighborhoods.name LIKE :key", { key: "#{keywords}")
end
if neighborhoods.exists?
listings = listings.where(neighborhood_id: neighborhood_ids)
end
listings
end
仅此而已:)
更新：使用f.input_field
# view
<%= f.input_field :neighborhood_names, url: autocomplete_neighborhood_name_searches_path, as: :autocomplete, data: { delimiter: ',' }, multiple: true, class: "span8" %>
# model
# we need to put [0] because it returns an array with a single element containing
# the string of comma separated neighborhoods
def neighborhood_names=(names)
names[0].split(',').each do |name|
next if name.blank?
if neighborhood = Neighborhood.find_by_name(name)
search_neighborhoods.build neighborhood_id: neighborhood.id
end
end
end
你的问题是，如何你从附近收集型值
Neighborhood.order(:name)
将返回名称数组，你还需要收集ID，但只显示名称中使用收集和传递块，我beleive这可能OWRK你
Neighborhood.collect {|n| [n.name, n.id]}
声明对邻里类范围的名字，如果你想获得theat功能回来，因为这种行为也是在新型属于好歹来订购吧。
编辑>要在范围/类方法添加到邻域模型，你通常做soemthing这样
scope :desc, where("name DESC")
比你写的东西，如：
Neighborhood.desc.all
它会返回一个阵列，从而使.collect但也有其他的方式来获得由选择的选项承认的名称和id属性。
文章来源: Getting rails3-autocomplete-jquery gem to work nicely with Simple_Form with multiple inputs
