将文字转换成具有一定键和值的字典[复制](Convert text into a dictionar

这个问题已经在这里有答案 ：

如何提取文本文件转换成字典 （3个回答）

可能重复：
如何提取文本文件转换成字典

我有一个文本文件，我想将它变成一个Python字典。 该文本文件如下。 当我想有键为“太阳”和“地球”和“月亮”，然后这些值的轨道半径，周期和这样的，这样我可以实现动画太阳能系统进入快挂。

RootObject: Sun

Object: Sun
Satellites: Mercury,Venus,Earth,Mars,Jupiter,Saturn,Uranus,Neptune,Ceres,Pluto,Haumea,Makemake,Eris
Radius: 20890260
Orbital Radius: 0

Object: Earth
Orbital Radius: 77098290
Period: 365.256363004
Radius: 6371000.0
Satellites: Moon

Object: Moon
Orbital Radius: 18128500
Radius: 1737000.10
Period: 27.321582

到目前为止我的代码是

def file():
    file = open('smallsolar.txt', 'r')
    answer = {}
    text = file.readlines() 
    print(text)



text = file() 
print (text)

我不知道现在是什么做的。 有任何想法吗？

Answer 1:

answer = {} # initialize an empty dict
with open('path/to/file') as infile: # open the file for reading. Opening returns a "file" object, which we will call "infile"

    # iterate over the lines of the file ("for each line in the file")
    for line in infile:

        # "line" is a python string. Look up the documentation for str.strip(). 
        # It trims away the leading and trailing whitespaces
        line = line.strip()

        # if the line starts with "Object"
        if line.startswith('Object'):

            # we want the thing after the ":" 
            # so that we can use it as a key in "answer" later on
            obj = line.partition(":")[-1].strip()

        # if the line does not start with "Object" 
        # but the line starts with "Orbital Radius"
        elif line.startswith('Orbital Radius'):

            # get the thing after the ":". 
            # This is the orbital radius of the planetary body. 
            # We want to store that as an integer. So let's call int() on it
            rad = int(line.partition(":")[-1].strip())

            # now, add the orbital radius as the value of the planetary body in "answer"
            answer[obj] = rad

希望这可以帮助

有时候，如果你有十进制数字（“浮点数”在python-说吧）在您的文件（ 3.14等），调用int上会失败。 在这种情况下，使用float()代替int()

Answer 2:

读取文件中的一个字符串，而不是readlines方法（），然后分裂的“\ n \ n”，这样一来，你将有一个项目列表，每个描述你的对象。

这时，你可能想创建一个类确实是这样的：

class SpaceObject:
  def __init__(self,string):
    #code here to parse the string

    self.name = name
    self.radius = radius
    #and so on...

然后您可以创建这些对象的列表

#items is the list containing the list of strings describing the various items
l = map(lambda x: SpaceObject(x),items).

再简单地做以下

d= {}
for i in l:
  d[i.name] = i

文章来源: Convert text into a dictionary with certain keys and values [duplicate]